Compound and Multiple Angles OP Malhotra S.Chand ISC Class-11 Maths Solutions Chapter-5. Step by step Solutions of OP Malhotra S.Chand ISC Class-11 Mathematics with Exe-5(a), Exe-5(b), Exe-5(c), Exe-5(d) with Chapter Test Questions. Visit official Website CISCE for detail information about ISC Board Class-12 Mathematics.
Compound and Multiple Angles OP Malhotra S.Chand ISC Class-11 Maths Solutions
Class: | 11th |
Subject: | Mathematics |
Chapter : | Ch-5 Compound and Multiple Angles of Section -A |
Board | ISC |
Writer | OP Malhotra |
Publications | S.Chand Publications 2020-21 |
-: Select Topics :-
Compound and Multiple Angles OP Malhotra S.Chand ISC Class-11 Maths Solutions
Compound Angles
The algebraic sum of 2 or more angles can be called a compound angle. Trigonometric identities are used to represent compound angles. The basic operations of finding the sum and difference of functions can be computed using the concept of compound angles.
Trigonometric Ratios of Compound Angles
The formulae for trigonometric ratios of compound angles are as follows:
- sin (A + B) = sin A cos B + cos A sin B
- sin (A – B) = sin A cos B – cos A sin B
- cos (A + B) = cos A cos B – sin A cos B
- cos (A – B) = cos A cos B + sin A cos B
- tan (A + B) = [tan A + tanB] / [1 – tan A tan B]
- tan (A – B) = [tan A – tan B] / [1 + tan A tan B]
- sin (A + B) sin (A – B) = sin2 A – sin2 B = cos2 B – cos2 A
- cos (A + B) cos (A – B) = cos2 A – sin2 A – sin2 B = cos2 B – sin2 A
Transformation of Products into Sum or Difference of Sines and Cosines:
(a) 2 sin A cos B = sin (A+B) + sin (A-B)
(b) 2 cos A cos B = cos (A+B) + cos (A-B)
(c) 2 cos A sin B = sin (A+B) – sin (A-B)
(d) 2 sin A sin B = cos (A-B) – cos (A+B)
Multiple and sub multiple Angles
(a) sin 2A = 2 sin A cos A = 2 tan A/(1+tan2A)
(b) cos 2A = cos2A – sin2A = 2cos2A-1 = 1-2 sin2A
(c) tan 2A = 2 tan A/(1-tan2A)
(d) sin 3A = 3 sinA – 4 sin3A
(e) cos 3A = 4 cos3A – 3 cos A
(f) tan 3A = (3 tan A- tan3A)/(1-tan2A)
Exe-5(a)
Compound and Multiple Angles OP Malhotra S.Chand ISC Class-11 Maths Solutions
Some part of the Questions is given for hint , see question from your text book :
Question 1-
Compute :
(i) sin 150 from the function of 600 and 450
(ii) cos 3450 from the function of 600 and 450
(iii) tan 1050 from the function of 600 and 600
(iv) sin 1350 from the function of 1800 and 450
(v) cos 1950 from the function of 1500 and 450
(vi) cosec (13 π/12)
Question 2-
………………………
………………………..
……………………….
Question 31-
If A + B = 2250, prove that tan A + tan B = 1- tan A tan B
Exe-5(b)
Compound and Multiple Angles OP Malhotra S.Chand ISC Class-11 Maths Solutions
Page 5-11 to 5-12
Question 1-
Convert the following products into sum or difference. If angle are given in degree evaluate from table
(i) 2 sin 480 cos 120
Question 2-
………………
( see question from your text book 🙂
………………….
Question 22-
What is the value of cos 10 + sin 20/ cos 20 – sin 10?
Exe-5(c)
Compound and Multiple Angles OP Malhotra S.Chand ISC Class-11 Maths Solutions
Page 5-25 to 5-26
Question 1-
Evaluate:
(i) 2 sin 15 cos 15
(ii) ………..
(iii)………..
Question 2-
( see question from your text book :)……………………..
……………………….
……………………..
Question 17-
Calculate without using table tan 20 tan 40 tan 80.
Exe-5(d)
Compound and Multiple Angles S.Chand ISC Class-11 Maths Solutions
Page 5-27 to 5-29
Question 1-
(i) (sin∅ – cos ∅)² = 1 – sin 2∅
(ii) {cos (θ/2) + sin(θ/2)}² = 1 + sin θ
Question 2-
( see question from your text book :)………………………
……………………..
……………………….
Question 45-
If tan …………………
Chapter Test
Compound and Multiple Angles OP Malhotra S.Chand ISC Class-11 Maths Solutions
Page 5-33 to 5-3
Question 1-
Show that tan ………………….. 4 sin 60.
Question 2-
( see question from your text book :)…………………….
………………………..
Question 16-
Prove that cos …………………. x-1.
…………………………..
………………………….
Question 21-
If tan …………………………….
-: End of Compound and Multiple Angles Solution :-
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