Decimals Class- 7th RS Aggarwal Exe-3D Goyal Brothers ICSE Math Solution

Decimals Class- 7th RS Aggarwal Exe-3D Goyal Brothers ICSE Math Solution . We provide step by step Solutions of lesson-3 Decimals for ICSE Class-7 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan . Our Solutions contain all type Questions of Exe-3D to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-7 Mathematics.

Decimals Class- 7th RS Aggarwal Exe-3D Goyal Brothers ICSE Math Solution

Decimals Class- 7th RS Aggarwal Exe-3D Goyal Brothers ICSE Math Solution

Board ICSE
Publications Goyal brothers Prakashan
Subject Maths
Class 7th
Chapter-3 Decimals
Writer RS Aggrawal
Book Name Foundation
Topics Solution of Exe-3D
Academic Session 2023 – 2024

Exercise – 3D

Decimals Class- 7th RS Aggarwal Exe-3D Goyal Brothers ICSE Math Solution

1. Divide :

(i) 2.8 ÷ 10

Solution:  2.8 ÷ 10

= 0.28

(ii) 0.63 ÷ 10

Solution: 0.63 ÷ 10

= 0.063

(iii) 3.05 ÷ 10

Solution: 3.05 ÷ 10

= 0.305

(iv) 245.6 ÷ 100

Solution: 245.6 ÷ 100

= 2.456

(v) 0.9 ÷ 100

Solution: 0.9 ÷ 100

= 0.009

(vi) 1.23 ÷ 100

Solution: 1.23 ÷ 100

= 0.0123

(vii) 134.2 ÷ 1000

Solution: 134.2 ÷ 1000

= 0.1342

(viii) 23.4 ÷ 1000

Solution: 23.4 ÷ 1000

= 0.0234

(ix) 0.7 ÷ 1000

Solution: 0.7 ÷ 1000

= 0.0007

2. Divide :

(i) 20.79 ÷ 9

Solution: 20.79 ÷ 9

= 2.31

(ii) 78.48 ÷ 12

Solution: 78.48 ÷ 12

= 6.54

(iii) 142.8 ÷ 21

Solution: 142.8 ÷ 21

= 6.8

(iv) 6.02 ÷ 7

Solution: 6.02 ÷ 7

=0.86

(v) 0.688 ÷ 8

Solution: 0.688 ÷ 8

= 0.86

(vi) 0.125 ÷ 25

Solution:  0.125 ÷ 25

= 0.005

(vii) 0.992 ÷ 31

Solution: 0.992 ÷ 31

= 0.32

(viii) 0.1728 ÷ 72

Solution: 0.1728 ÷ 72

= 0.0024

(ix) 0.12749 ÷ 61

Solution: 0.12749 ÷ 61

= 0.00209

3. Divide :

(i) 2.24 ÷ 0.8

Solution: 2.24 ÷ 0.8

= Converting the divisor 0.8 into whole number by multiplying it by 10.

= (2.24/0.8)

= (2.24 × 10)/(0.8 × 10)

= (22.4/8)

= 2.8

(ii) 1.242 ÷ 1.8

Solution: 1.242 ÷ 1.8

= Converting the divisor 1.8 into whole number by multiplying it by 10.

= (1.242/1.8)

= (1.242 × 10)/(1.8 × 10)

= (1.242/18)

= 0.69

(iii) 0.1575 ÷ 0.21

Solution: 0.1575 ÷ 0.21

= Converting the divisor 0.21 into whole number by multiplying it by 100.

= (0.1575/0.21)

= (0.1575 × 100)/(0.21 × 100)

= (15.75/21)

= 0.75

(iv) 0.0144 ÷ 0.12

Solution: 0.0144 ÷ 0.12

= Converting the divisor 0.12 into whole number by multiplying it by 100.

= (0.0144/0.12)

= (0.0144 × 100)/(0.12 × 100)

= (144/12)

= 0.12

(v) 0.0783 ÷ 0.9

Solution: 0.0783 ÷ 0.9

= Converting the divisor 0.9 into whole number by multiplying it by 10.

= (0.0783/0.9)

= (0.0783 × 10)/(0.9 × 10)

= (0.783 /9)

= 0.087

(vi) 0.1164 ÷ 0.012

Solution: 0.1164 ÷ 0.012

= Converting the divisor 0.012 into whole number by multiplying it by 1000.

= (0.1164/0.012)

= (0.1164 × 1000)/(0.012 × 1000)

= (116.4/12)

= 9.7

(vii) 0.068 ÷ 0.17

Solution: 0.068 ÷ 0.17

= Converting the divisor 0.17 into whole number by multiplying it by 100.

= (0.068/0.17)

= (0.068 × 100)/(0.17 × 100)

= (6.8/17)

= 0.4

(viii) 0.02324 ÷ 0.28

Solution: 0.02324 ÷ 0.28

= Converting the divisor 0.28 into whole number by multiplying it by 100.

= (0.02324/0.28)

= (0.02324 × 100)/(0.28 × 100)

= (2.324/28)

= 0.083

(ix) 0.03822 ÷ 0.049 

Solution: 0.03822 ÷ 0.049

= Converting the divisor  0.049 into whole number by multiplying it by 1000.

= (0.03822/0.049)

= (0.03822 × 1000)/(0.049 × 1000)

= (38.22/49)

= 0.78

4. Simplify :

(i) 1.3 × 2.4/0.39

Solution: 1.3 × 2.4/0.39

= (1.3 × 2.4 × 100)/(0.39 × 100)

= 13 × 24 /   39

= 24/3

= 80

(ii) 2.5 × 40.4/50

Solution: 2.5 × 40.4/50

= (25 × 404)/(50 × 10 × 10)

= 202/100

= 2.02

(iii) 6.3/0.3 × 0.1

Solution: 6.3/0.3 × 0.1

= (63 × 10 × 10)/(3 × 10 × 10)

= 21 × 10

= 210

5. A boy bought 8 pencils for ₹46.80. What is the cost of each pencil?

Solution: CP of 8 pencil = 46.80

CP of 1 pencil = 46.80 ÷ 8

= 5.85 ₹

6. A car covers a distance of 276.75 km in 4.5 hours. What is the average speed of the car?

Solution: Car covers in 4.5 hours = 276.75 km

It will cover in 1 hours = ?

= 276.75 ÷ 4.5

= 27675 ÷ 450                       [converting into like decimals]

= 61.5 km

speed of car = 61.5 km/hr

7. 2.25 m of a cloth costs ₹326.25. What is the cost of 1 m of cloth?

Solution: CP of 2.25 m cloth = ₹326.25

CP of 1 m cloth = ?

= 326.25 ÷ 2.25

= (326.25/2.25)

= (32625 × 100)/(225 × 100)

= (3262500/22500)

= 145 ₹

8. The product of two numbers is 52.8. If one of them is 8.25, find the other.

Solution: Product of two numbers = 52.8

First number = 8.25

Second number = ?

= 52.8 ÷ 8.25

= 5280 ÷ 825

= 6.4

Second number = 6.4

9. How many equal pieces, each of length 3.6 cm can be cut from a rope of length 61.2 cm?

Solution: Total length of a rope = 61.2 cm

Length of one pieces of rope = 3.6 cm

Number of pieces = ?

= 61.2 ÷ 3.6                            [Converting into like decimals]

= 612 ÷ 36

= 17 pieces

— : end of Decimals Class- 7th RS Aggarwal Exe-3D Goyal Brothers ICSE Math Solution:–

Return to- ICSE Class -7 RS Aggarwal Goyal Brothers Math Solutions

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