Decimals Class- 7th RS Aggarwal Exe-3E Goyal Brothers ICSE Math Solution . We provide step by step Solutions of lesson-3 Decimals for ICSE Class-7 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan . Our Solutions contain all type Questions of Exe-3E to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-7 Mathematics.
Decimals Class- 7th RS Aggarwal Exe-3E Goyal Brothers ICSE Math Solution
| Board | ICSE |
| Publications | Goyal brothers Prakashan |
| Subject | Maths |
| Class | 7th |
| Chapter-3 | Decimals |
| Writer | RS Aggrawal |
| Book Name | Foundation |
| Topics | Solution of Exe-3E |
| Academic Session | 2023 – 2024 |
Exercise – 3E
Decimals Class- 7th RS Aggarwal Exe-3E Goyal Brothers ICSE Math Solution
1. Express each of the following as a recurring decimal :
(i) (20/3)
Solution: (20/3)
on division we get
= 6.6666……
= 6.6
(ii) (3/11)
Solution: (3/11)
on division we get
= 0.272727……..
= 0.27
(iii) (5/6)
Solution: (5/6)
on division we get
= 0.8333……
= 0.83
(iv) (17/90)
Solution: (17/90)
on division we get
= 0.1888……
= 0.18
(v) (1/37)
Solution: (1/37)
on division we get
= 0.027027…….
= 0.027
(vi) (22/7)
Solution: (22/7)
on division we get
= 3.1428571…….
= 3.1428571
(vii) (2/13)
Solution: (2/13)
on division we get
= 0.153846…….
= 0.153846
2. Convert each of the following into a vulgar fraction :
(i) 0.6
Solution: 0.6
Let x = 0.6
x = 0.666……….(1)
Multiply both sides by 10
10x = 6.666………(2)
Subtracting (1) from (2)
⇒ 9x = 6.000
⇒ 9x = 6
⇒ x = (6/9)
⇒ x = (2/3)
Fraction = (2/3)
(ii) 0.8
Solution: 0.8
Let x = 0.8
x = 0.888……….(1)
Multiply both sides by 10
10x = 8.888………(2)
Subtracting (1) from (2)
⇒ 9x = 8.000
⇒ 9x = 8
⇒ x = (8/9)
Fraction = (8/9)
(iii) 0.34
Solution: 0.34
Let x = 0.34
x = 0.343434……….(1)
Multiply both sides by 100
100x = 34.343434………(2)
Subtracting (1) from (2)
⇒ 99x = 34
⇒ x = (34/99)
Fraction = (34/99)
(iv) 2.13
Solution: 2.13
Let x = 2.13
x = 2.131313……….(1)
Multiply both sides by 100
100x = 213.131313……..(2)
Subtracting (1) from (2)
⇒ 99x = 213
⇒ x = (213/99)
Fraction = 2(13/99)
(v) 1.243
Solution: 1.243
Let x = 1.243
x = 1.243243243……….(1)
Multiply both sides by 1000
1000x = 1243.243243……..(2)
Subtracting (1) from (2)
⇒ 999x = 1243
⇒ x = (1243/999)
Fraction = 1(243/999)
3. Convert each of the following into a vulgar fraction :
(i) 0.16
Solution: 0.16
= (16 – 1)/90
= (15/90)
= (1/6)
(ii) 0.143
Solution: 0.143
= (143 – 1)/990
= (142/990)
= (71/459)
(iii) 0.574
Solution: 0.574
= (574 – 57)/900
= (517/900)
(iv) 0.1234
Solution: 0.1234
= (1234 – 12)/9990
= (1222/9990)
= (611/4995)
— : end of Decimals Class- 7th RS Aggarwal Exe-3E Goyal Brothers ICSE Math Solution:–
Return to- ICSE Class -7 RS Aggarwal Goyal Brothers Math Solutions
Thanks
Please share with yours friends if you find it helpful.
unbelievable answers