ML Aggarwal Circle Exe-15.2 Class 9 ICSE Maths Solutions

ML Aggarwal Circle Exe-15.2 Class 9 ICSE Maths Solutions Ch-15. Step by Step Solutions of Exe-15.2 Questions on Circle of ML Aggarwal for ICSE Class 9th Mathematics. Visit official website CISCE for detail information about ICSE Board Class-9.

ML Aggarwal Circle Exe-15.2 Class 9 ICSE Maths Solutions

Board ICSE
Subject Maths
Class 9th
Chapter-15 Circle
Topics Solution of Exe-15.2 Questions
Academic Session 2024-2025

Solution of Exe-15.2 Questions on Circle

ML Aggarwal Class 9 ICSE Maths Solutions Ch-15

Question 1. If arcs APB and CQD of a circle are congruent, then find the ratio of AB: CD.

Answer : arc APB = arc CQD (given)

AB = CD (If two arcs are congruent, then their corresponding chords are equal)

Ratio of AB and CD = AB / CD = AB /AB = 1/1

AB : CD = 1 : 1

Question 2. A and B are points on a circle with centre O. C is a point on the circle such that OC bisects ∠AOB, prove that OC bisects the arc AB.

Answer : In a given circle with centre O,A

And B are Two points on the circle. C i

another point on the circle such that

∠AOC = ∠BOC

A and B are points on a circle with centre O. C is a point on the circle such that OC bisects ∠AOB, prove that OC bisects the arc AB.

To prove :  arc AC = arc BC

Proof: OC is the bisector of ∠AOB

⇒ ∠AOC = ∠BOC

But these are the angle subtended by the arc AC and BC

arc AC = arc BC.

Question 3. Prove that the angle subtended at the centre of a circle is bisected by the radius passing through the mid-point of the arc.

Answer : AB is the arc of the circle with

Centre O and C is the mid-Point od arc AB.

To prove: OC bisects the ∠AOB

I,e ∠AOC = ∠BOC

Proof: C is the mid-point of arc AB.

arc AC = arc BC

A and B are points on a circle with centre O. C is a point on the circle such that OC bisects ∠AOB, prove that OC bisects the arc AB.

But arc AC and arc BC subtend ∠AOC and

∠BOC at the centre

∠AOC = ∠BOC

Hence, OC Bisects the ∠AOB.

Question 4. In the given figure, two chords AB and CD of a circle intersect at P. If AB = CD, prove that arc AD = arc CB.

Answer : given that Two chord AB and CD of a Circle Intersect at P and AB = CD

In the given figure, two chords AB and CD of a circle intersect at P. If AB = CD, prove that arc AD = arc CB.

To prove :   arc AD = arc CB

Proof:  AB = CD

minor arc AB = minor arc CD

Subtracting arc BD from both sides

arc AB = arc BD = arc CD – arc BD

AD = arc CD

—  : End of ML Aggarwal Circle Exe-15.2 Class 9 ICSE Maths Solutions :–

Return to :- ML Aggarawal Maths Solutions for ICSE  Class-9

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