ML Aggarwal Circle Exe-15.2 Class 9 ICSE Maths Solutions

ML Aggarwal Circle Exe-15.2 Class 9 ICSE Maths APC Understanding Solutions. Solutions of  Exe-15.2. This post is the Solutions of  ML Aggarwal Chapter 15 – Circle for ICSE Maths Class-9.  APC Understanding ML Aggarwal Solutions (APC) Avichal Publication Solutions of Chapter-15 Circle for ICSE Board Class-9Visit official website CISCE for detail information about ICSE Board Class-9.

ML Aggarwal Circle Exe-15.2 Class 9 ICSE Maths Solutions

Board ICSE
Publications Avichal Publishig Company (APC)
Subject Maths
Class 9th
Chapter-15 Circle
Writer ML Aggarwal
Book Name Understanding
Topics Solution of Exe-15.2 Questions
Edition 2021-2022

Exe-15.2 Solutions of ML Aggarwal for ICSE Class-9 Ch-15, Circle

Note:- Before viewing Solutions of Chapter -15 Circle Class-9 of ML AggarwaSolutions .  Read the Chapter Carefully. Then solve all example given in Exercise-15.1, Exe-15.2, MCQs, Chapter Test.


Circle Exercise-15.2

ML Aggarwal Class 9 ICSE Maths Solutions

Page 341

Question 1. If arcs APB and CQD of a circle are congruent, then find the ratio of AB: CD.

Answer :

arc APB = arc CQD (given)

AB = CD (If two arcs are congruent, then their corresponding chords are equal)

Ratio of AB and CD = AB / CD = AB /AB = 1/1

AB : CD = 1 : 1

Question 2. A and B are points on a circle with centre O. C is a point on the circle such that OC bisects ∠AOB, prove that OC bisects the arc AB.

Answer :

In a given circle with centre O,A

And B are Two points on the circle. C i

another point on the circle such that

∠AOC = ∠BOC

A and B are points on a circle with centre O. C is a point on the circle such that OC bisects ∠AOB, prove that OC bisects the arc AB.

To prove : 

arc AC = arc BC

Proof: OC is the bisector of ∠AOB

⇒ ∠AOC = ∠BOC

But these are the angle subtended by the arc AC and BC

arc AC = arc BC.

Question 3. Prove that the angle subtended at the centre of a circle is bisected by the radius passing through the mid-point of the arc.

Answer :

AB is the arc of the circle with

Centre O and C is the mid-Point od arc AB.

To prove: OC bisects the ∠AOB

I,e ∠AOC = ∠BOC

Proof:

C is the mid-point of arc AB.

arc AC = arc BC

A and B are points on a circle with centre O. C is a point on the circle such that OC bisects ∠AOB, prove that OC bisects the arc AB.

But arc AC and arc BC subtend ∠AOC and

∠BOC at the centre

∠AOC = ∠BOC

Hence,

OC Bisects the ∠AOB.

Question 4. In the given figure, two chords AB and CD of a circle intersect at P. If AB = CD, prove that arc AD = arc CB.

Answer :

In the given figure, two chords AB and CD of a circle intersect at P. If AB = CD, prove that arc AD = arc CB.

Two chord AB and CD of a Circle

Intersect at P and AB = CD

To prove : 

arc AD = arc CB

Proof:

AB = CD

minor arc AB = minor arc CD

Subtracting arc BD from both sides

arc AB = arc BD = arc CD – arc BD

AD = arc CD

—  : End of ML Aggarwal Circle Exe-15.2 Class 9 ICSE Maths Solutions :–

Return to :-  ML Aggarawal Maths Solutions for ICSE  Class-9

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