Fractions Class 6 RS Aggarwal Exe-4B Goyal Brothers ICSE Maths Solutions. We provide step by step Solutions of ICSE Class-6 **Foundation RS Aggarwal Mathematics** of Goyal Brothers Prakashan. This article is related on How to reduce a fraction in Simple Form. Visit official Website **CISCE** for detail information about ICSE Board Class-6 Mathematics.

## Fractions Class 6 RS Aggarwal Exe-4B Reduce in Simple Form Goyal Brothers ICSE Maths Solutions

Board | ICSE |

Publications | Goyal brothers Prakashan |

Subject | Maths |

Class | 6th |

Ch-4 | Fraction |

Writer | RS Aggrawal |

Book Name | Foundation |

Topics | Solution of Exe-4A |

Academic Session | 2023 – 2024 |

### How to Reduce a Fraction in Simple Form

Fractions Class 6 RS Aggarwal Exe-4B Goyal Brothers ICSE Maths Solutions

**Page- 65,66**

**Que-1: Which of the following fractions are in simplest form ?**

**(i) 21/40 (ii) 35/49 (iii) 42/54**

**(iv) 64/81 (v) 56/65 (vi) 23/92**

**(vii) 102/119 (viii) 91/114**

**Solution- **(i), (iv), (v), (viii) fractions are in simplest form.

**Que-2: Reduce each of the following fractions to its lowest terms :**

**(i) 27/36 (ii) 45/54 (iii) 38/95**

**(iv) 58/87 (v) 85/153 (vi) 105/168**

**(vii) 117/143 (viii) 135/150**

**Solution-** (i) Greatest common divisor GCD(27,36) = 9

Now, divide both the numerator and denominator by 9:

(27÷9)/(36÷9) = 3/4

So, 27/36 in its lowest terms is 3/4.

(ii) So ,Greatest common divisor GCD(45, 54) = 3×3 =9.

Now, divide both the numerator and denominator by 9:

(45÷9)/(54÷9) = 5/6

Therefore, 45/54 in its lowest terms is 5/6.

(iii) 38/95 = (38÷19)/(95÷19) = 2/5

So, 38/95 in its lowest terms is 2/5.

(iv) the GCD is 29.

Now, we divide both the numerator and denominator by 29:

(58÷29)/(87÷29) = 2/3

So, the fraction 58/87 in its lowest terms is 2/3.

(v) divide both the numerator and denominator by 17:

85/153 = (85÷17)/(153÷17) = 5/9

So, the fraction 85/153 reduced to its lowest terms is 5/9.

(vi) GCD (105,168) = 21

Now, we’ll divide both the numerator and the denominator by 21:

(105÷21)/(168÷21) = 5/8

So, 105/168 reduced to its lowest terms is 5/8.

(vii) Since we have reached a remainder of 0, the last non-zero divisor (13) is the GCD of 117 and 143.

Now, we divide both the numerator and denominator by the GCD:

117/143 = (117÷13)/(143÷13) = 9/11

So, 117/143 in its lowest terms is 9/11.

(viii) The greatest common divisor (GCD) of the numerator and denominator, which is 15.

Then, we divide both the numerator and denominator by their GCD:

135/150 = (135÷15)/(150÷15) = 9/10

So, 135/150 in its lowest terms is 9/10.

**— : end of Fractions Class 6 RS Aggarwal Exe-4B Goyal Brothers Publication ICSE Foundation Maths Solutions :–**

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