Fractions Class 6 RS Aggarwal Exe-4B Goyal Brothers ICSE Maths Solutions. We provide step by step Solutions of ICSE Class-6 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan. This article is related on How to reduce a fraction in Simple Form. Visit official Website CISCE for detail information about ICSE Board Class-6 Mathematics.
Fractions Class 6 RS Aggarwal Exe-4B Reduce in Simple Form Goyal Brothers ICSE Maths Solutions
| Board | ICSE |
| Publications | Goyal brothers Prakashan |
| Subject | Maths |
| Class | 6th |
| Ch-4 | Fraction |
| Writer | RS Aggrawal |
| Book Name | Foundation |
| Topics | Solution of Exe-4A |
| Academic Session | 2023 – 2024 |
How to Reduce a Fraction in Simple Form
Fractions Class 6 RS Aggarwal Exe-4B Goyal Brothers ICSE Maths Solutions
Page- 65,66
Que-1: Which of the following fractions are in simplest form ?
(i) 21/40 (ii) 35/49 (iii) 42/54
(iv) 64/81 (v) 56/65 (vi) 23/92
(vii) 102/119 (viii) 91/114
Solution- (i), (iv), (v), (viii) fractions are in simplest form.
Que-2: Reduce each of the following fractions to its lowest terms :
(i) 27/36 (ii) 45/54 (iii) 38/95
(iv) 58/87 (v) 85/153 (vi) 105/168
(vii) 117/143 (viii) 135/150
Solution- (i) Greatest common divisor GCD(27,36) = 9
Now, divide both the numerator and denominator by 9:
(27÷9)/(36÷9) = 3/4
So, 27/36 in its lowest terms is 3/4.
(ii) So ,Greatest common divisor GCD(45, 54) = 3×3 =9.
Now, divide both the numerator and denominator by 9:
(45÷9)/(54÷9) = 5/6
Therefore, 45/54 in its lowest terms is 5/6.
(iii) 38/95 = (38÷19)/(95÷19) = 2/5
So, 38/95 in its lowest terms is 2/5.
(iv) the GCD is 29.
Now, we divide both the numerator and denominator by 29:
(58÷29)/(87÷29) = 2/3
So, the fraction 58/87 in its lowest terms is 2/3.
(v) divide both the numerator and denominator by 17:
85/153 = (85÷17)/(153÷17) = 5/9
So, the fraction 85/153 reduced to its lowest terms is 5/9.
(vi) GCD (105,168) = 21
Now, we’ll divide both the numerator and the denominator by 21:
(105÷21)/(168÷21) = 5/8
So, 105/168 reduced to its lowest terms is 5/8.
(vii) Since we have reached a remainder of 0, the last non-zero divisor (13) is the GCD of 117 and 143.
Now, we divide both the numerator and denominator by the GCD:
117/143 = (117÷13)/(143÷13) = 9/11
So, 117/143 in its lowest terms is 9/11.
(viii) The greatest common divisor (GCD) of the numerator and denominator, which is 15.
Then, we divide both the numerator and denominator by their GCD:
135/150 = (135÷15)/(150÷15) = 9/10
So, 135/150 in its lowest terms is 9/10.
— : end of Fractions Class 6 RS Aggarwal Exe-4B Goyal Brothers Publication ICSE Foundation Maths Solutions :–
Return to :- ICSE Class -7 RS Aggarwal Goyal Brothers Math Solutions
Thanks
Please share with yours friends if you find it helpful
