Fractions Class 6 RS Aggarwal Exe-4G Word Problems Goyal Brothers Prakashan ICSE Foundation Maths Solutions. We provide step by step Solutions of ICSE Class-6 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan. Visit official Website CISCE for detail information about ICSE Board Class-6 Mathematics.
Fractions Class 6 RS Aggarwal Exe-4G Word Problems Goyal Brothers Prakashan ICSE Foundation Maths Solutions
| Board | ICSE |
| Publications | Goyal brothers Prakashan |
| Subject | Maths |
| Class | 6th |
| Ch-4 | Fraction |
| Writer | RS Aggrawal |
| Book Name | Foundation |
| Topics | Solution of Exe-4G |
| Academic Session | 2023 – 2024 |
Word Problems on Fractions
Fractions Class 6 RS Aggarwal Exe-4G Goyal Brothers Prakashan ICSE Foundation Maths Solutions.
Page- 83
Exercise- 4G
Que-1: A man earns Rs 18720 per month and spends 5/6 of his income. Find his monthly (i) expenditure (ii) saving.
Solution- (i) It is given that he spends 5/6 of 18720 Rupees.
So, 5/6 of 18720 Rupees :-
= 5/6 x 18720
= 5 x 3120
= 15600 Rupees
His monthly expenditures is 15600 Rupees Ans.
(ii) His saving,
= monthly income – monthly expenditure.
= (18720 – 15600) Rupees
= 3120 Rupees
His monthly savings = 3120 Rupees. Ans
Que-2: A water tank can hold 56*(1/4) litres of water. How much water is contained in the tank when it is 8/15 full?
Solution- The total capacity of the water tank is 225/4 litres.
To find the amount of water when the tank is 8/15 full, we multiply the total capacity of the tank (225/4 litres) by the fraction representing the tank’s fill level (8/15).
= (225/4) × (8/15)
= (225 × 8) / (4 × 15)
= 1800 / 60
= 30 litres. Ans
Hence, when the tank is 8/15 full, it contains 30 litres of water.
Que-3: After reading 5/8 of a book, 168 pages are left. How many pages are there in all in the book?
Solution- Let total book is 1 part
Read = 5/8 parts
Unread = [1 – ( 5/8)] parts
3/8 parts
According to the question,
(3/8) parts = 168 pages
1 part = (168 × 8)/3 pages
448 pages
∴ Total number of pages in the book is 448.
Que-4: 2/3 of a students in a class are boys and the rest are 17 girls.
(i) How many boys are there in a class?
(ii) What is the total strength of a class?
Solution- (i) Let x be the total strength of the class
No. of boys= 2x/3 ; No. of girls= 17
x = (2x+51)/3
3x = 2x+51
3x – 2x = 51
x = 51
No. of boys = 2/3 of 51
= 34 Ans.
(ii) means 1/3 are girls
So, 1/3 = 17.
2/3 = 1/3 + 1/3 = 17 + 17
= 3/4 boys are in the class.
total strength of class = 17 + 34
= 51 Ans.
Que-5: A man earns Rs 25440 per month. He spends 1/4 of it on house rent, 3/8 on food and clothes, 1/10 on insurance and 1/5 on other items. How does he save each month?
Solution- Total earning in 1 month = ₹25440
Money spent on rent is 1/4 of total earning = 1/4×25440
= ₹6360
Money spent on food is 3/8 of total earning = ₹ 3/8×25440
= ₹9540
Money spent on insurance is 1/10 of total earning = ₹ 1/10×25440
= ₹2544
Money spent on other items is 1/5 of total earning = ₹ 1/5×25440
= ₹5088
Therefore, the total money spent = ₹ (6360+9540+2544+5088)
= ₹23532
So, money saved by the man = ₹(25440-23532)
= ₹1908
Hence, the man saves ₹1908 each month.
Que-6: An objective test was given to a group of 168 students. It was found that 5/6 of the students gave all correct answers. How many students made 1 or more mistakes?
Solution- Group of students 168.
Students give correct answers = 5/6 of 168
students give correct answers = 5/6 x 168
= 140 students.
No. Students who made mistakes. (168-140) = 28 students.
Hence, 28 students made mistakes.
Que-7: In an orchard, 1/3 of the trees are guava trees, 1/8 are bananas trees and the rest are mango trees. If there are 117 mango trees in the orchard, how many trees in all there?
Solution- Let there are n trees in an orchid
Given 1/3 of the trees are guava and 1/8 of the trees are banana
Remaining are Mango i.e.,
n − n/3 − n/8 = Mango trees
Given Mango trees =117
117 = (24n−8n−3n)/24
117 = 13n/24
n = 9×24
n = 216
There are 216 trees in the orchid.
Que-8: In a school, 1/25 of a students were absent on a certain day. If 720 students were present on that day, what is the total number of students in the school?
Solution- Given that 720 students were present on that day, we can set up the following proportion to find the total number of students in the school:
24/25 = 720/x Where x represents the total number of students in the school.
We can solve this proportion for x:
x = (720 X 25)/24
x =18000/24
x = 750
Therefore, the total number of students in the school is 750.
Que-9: The products of three numbers is 7*(1/2). If two of them are 1*(1/7) and 3*(3/4), find the third number.
Solution- let the third number be x
15/2 = 8/7 × 15/4 × x
15/2 = 2/7 × 15 × x
x = 15/2 × 7/2 × 1/15
x = 7/4 = 1*(3/4)
-: end of Fractions Class 6 RS Aggarwal Exe-4G Word Problems Goyal Brothers Publication :–
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