Fractions Class- 7th RS Aggarwal Exe-2A Goyal Brothers ICSE Math Solution . We provide step by step Solutions of lesson-2 Fractions for ICSE Class-7 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan . Our Solutions contain all type Questions of Exe-2A to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-7 Mathematics.
Fractions Class- 7th RS Aggarwal Exe-2A Goyal Brothers ICSE Math Solution
| Board | ICSE |
| Publications | Goyal brothers Prakashan |
| Subject | Maths |
| Class | 7th |
| Chapter-2 | Fractions |
| Writer | RS Aggrawal |
| Book Name | Foundation |
| Topics | Solution of Exe-2A |
| Academic Session | 2023 – 2024 |
Exercise – 2A
Fractions Class- 7th RS Aggarwal Exe-2A Goyal Brothers ICSE Math Solution
Que: Find the product:
1. (5/6) × (3/7)
Solution:
2. (7/18) × (9/14)
Solution:
= 1/4
3. 28 × (7/8)
Solution:
4. 7 × (1/7)
Solution:
= 7/7
= 1
5. 2(1/25) × (5/17)
Solution:
= 3/5
6. 1(1/13) × 7(3/7)
Solution:
= 8/1
7. (4/17) × 7(1/12)
Solution:
8. 7(1/4) × (7/58) × 1(11/21)
Solution:
9. (1/19) × 91 × 5(11/13)
Solution:
= 28
10. 7(1/4) × 2(3/16) × 2(2/7)
Solution:
11. Find the value of :
(i) (3/4) of (8/9)
Solution: (3/4) of (8/9)
= (8/9) × (3/4)
= (8 × 3)/(9 × 4) = (2 × 1)/(3 × 1)
= 2/3
(ii) (1/2) of 2(2/3)
Solution: (1/2) of 2(2/3)
= 2(2/3) × (1/2) = (8/3) × (1/2)
= (8 × 1)/(3 × 2) = (4 × 1)/(3 × 1)
= 4/3 = 1(1/3)
(iii) (4/5) of 1 hour
Solution: 1 h0ur = 60 mins.
∴ (4/5) x 1 hour= (4/5) x 60 minutes
= (4/5) x 60 minutes = 48 minutes.
Hence, (4/5) of an hour is 48 minutes.
(iv) (3/5) of ₹1
Solution: (3/5) of ₹1
₹1 rupee = 100
= ₹(100 × (3/5) )
= (3 × 20)
= 60 paise
(v) (8/15) 0f 1(1/2) meters
Solution: (8/15) 0f 1(1/2) meters
= (8/15) × (3/2)
= 4/5
∴ 1 meter = 100
= (4/5) × 100
= 80 cm
(vi) (5/7) of 2(1/3) kg
Solution: (5/7) of 2(1/3) kg
= (5/7) × (7/3) = (5 × 7)/(7 × 3)
= (5 × 1)/(1 × 3)
= 5/3 = 1(2/3)
12. A car can travel 12(1/2) km in 1 liter of petrol. How much distance can it travel in 42(3/5) liters of petrol?
Solution: 1 liter petrol = 12(1/2) km = 25/2 km
42(3/5) liters petrol = ?
42(3/5) = 213/5
13. A graphic designer charges ₹27(3/5) for each diagram. Find the amount he will charge if he designs 186 diagrams for a book.
Solution: 1 diagrams of design = ₹27(3/5) = ₹138/5
186 diagrams of design = ₹138/5 × 186
= ₹25668/5
= ₹5133(3/5)
14. If a cloth costs ₹715(1/4) per meter, find the cost of 3(2/5) meters of this cloth.
Solution: 1 meter cloth = ₹715(1/4) = ₹2861/4
3(2/5) = 17/5 meter cloth = ₹2861/4 × 17/5
= ₹48637/20
= ₹2431(17/20)
15. Advertising in a magazine costs ₹1472(2/3) per square inch. Find the cost of an advertisement of 17(6/7) square inch.
Solution:
16. A car travelled from city A to city B with a uniform speed of 52(2/7) km per hour. Find the distance between the two cities, if it took 4(3/8) hours for the car to reach city B from city A.
Solution:
17. The length of a rectangular plot of land is 29(3/7) m. If its breadth is 12(8/11) m, find its area.
Solution:
area = 515
— : end of Fractions Class- 7th RS Aggarwal Exe-2A Goyal Brothers ICSE Math Solution :–
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