**Fractions** Class- 7th RS Aggarwal Exe-2C Goyal Brothers ICSE Math Solution . We provide step by step Solutions of lesson-2 Fractions for ICSE Class-7 **Foundation RS Aggarwal Mathematics** of Goyal Brothers Prakashan . Our Solutions contain all type Questions of Exe-2C to develop skill and confidence. Visit official Website **CISCE** for detail information about ICSE Board Class-7 Mathematics.

## Fractions Class- 7th RS Aggarwal Exe-2C Goyal Brothers ICSE Math Solution

Board | ICSE |

Publications | Goyal brothers Prakashan |

Subject | Maths |

Class | 7th |

Chapter-2 | Fractions |

Writer | RS Aggrawal |

Book Name | Foundation |

Topics | Solution of Exe-2C |

Academic Session | 2023 – 2024 |

**Exercise – 2C**

Fractions Class- 7th RS Aggarwal Exe-2C Goyal Brothers ICSE Math Solution

**Questions: Simplify :**

**1. 1(2/3) + (5/6) 0f (24/25) **

**Solution: **1(2/3) + (5/6) 0f (24/25)

= (5/3) + (5/6) × (24/25)

= (5/3) + (120/150)** **

= (5/3) × (50/50) + (120/150)

= (250/150) + (120/150)

= (370/150)

= 37/15

= 2(7/15)

**2. (1/3) of 4(2/3) ÷ 2(1/3) × 1(1/2)**

**Solution: **(1/3) of 4(2/3) ÷ 2(1/3) × 1(1/2)

= (1/3) × (14/3) ÷ (7/3) × (3/2)

= (1/3) × (14/3) × (3/7) × (3/2)

= (2/2)

= 1

**3. 2(1/4) + 1(1/6) – 1(2/3) ÷ 2(2/3) of 3(3/4)**

**Solution: **2(1/4) + 1(1/6) – 1(2/3) ÷ 2(2/3) of 3(3/4)

= (9/4) + (7/6) – (5/3) ÷ (8/3) × (15/4)

= (9/4) + (7/6) – (5/3) ÷ (120/12)

= (9/4) + (7/6) – (1/6)

= (27 + 14)/12 – (1/6)

= (41/12) – (1/6)

= (41 – 2)/12 = 39/12

= 13/4 = 3(1/4)

**4. 1(1/2) × 2(3/4) ÷ 1(4/7) of 2(5/8)**

**Solution: **1(1/2) × 2(3/4) ÷ 1(4/7) of 2(5/8)

= (3/2) × (11/4) ÷ (11/7) × (21/8)

= (3/2) × (11/4) ÷ (11 × 3)/8

= (3/2) × (11/4) ÷ (33/8)

= (3/2) × (11/4) × (8/33)

= (3/2) × (2/3)

= 1

**5. (2(3/4) + 1(5/6)) ÷ 2(1/5) of 3(1/3)**

**Solution: **(2(3/4) + 1(5/6)) ÷ 2(1/5) of 3(1/3)

= (11/4) + (11/6) ÷ (11/5) × (10/3)

= (11 × 3 + 11 × 2)/12 ÷ (11/5) × (10/3)

= (33 + 22)/12 ÷ (22/3)

= (55/12) ÷ (22/3)

= (55/12) × (3/22)

= 5/8

**6. (7/15) of (2/3) + (7/12) ÷ (5/6) – (3/5)**

**Solution: **(7/15) of (2/3) + (7/12) ÷ (5/6) – (3/5)

= (7/15) of (8 + 7)/12 ÷ (25 – 18)/30

= (7/15) of (15/12) ÷ (7/30)

= (7/15) × (15/12) ÷ (7/30)

= (7/12) ÷ (7/30)

= (7/12) × (30/7)

= 5/2 = 2(1/2)

**7. (22 ÷ 5(1/2) ÷ 2(1/5) of 3(1/3) + 1(5/11)**

**Solution: **(22 ÷ 5(1/2) ÷ 2(1/5) of 3(1/3) + 1(5/11)

= (22/1) ÷ (11/2) ÷ (11/5) of (10/3) + (16/11)

= (22/1) × (2/11) ÷ (11/5) of (10/3) + (16/11)

= (4/1) ÷ (11/5) of (10/3) + (16/11)

= (4/1) ÷ (22/3) + (16/11)

= (4/1) × (3/22) + (16/11)

= (6/11) + (16/11)

= (6 + 16)/11 = (22/11)

= 2

**8. 6(1/3) ÷ (2(1/5) + 3(1/2)) of 3(1/3)**

**Solution: **6(1/3) ÷ (2(1/5) + 3(1/2)) of 3(1/3)

= (19/3) ÷ (11/5) + (7/2) of (10/3)

= (19/3) ÷ (22 + 35)/10 of (10/3)

= (19/3) ÷ (57/10) of (10/3)

= (19/3) ÷ (57/10) × (10/3)

= (19/3) ÷ (19/1)

= (19/3) × (1/19)

= 1/3

**— : end of Fractions Class- 7th RS Aggarwal Exe-2C Goyal Brothers ICSE Math Solution:–**

**Return to- ICSE Class -7 RS Aggarwal Goyal Brothers Math Solutions**

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