Graphical Representation of Statistical Data Class 10 RS Aggarwal Exe-24 ICSE Maths Solutions Ch-24. In this article you will get the solved practice questions / problems on Graphical Representation of Statistical Data using frequency polygon. Visit official website CISCE for detail information about ICSE Board Class-10.

Graphical Representation of Statistical Data Class 10 RS Aggarwal Exe-24 ICSE Maths Solutions Ch-24

Board	ICSE
Publications	Goyal Brothers Prakashan
Subject	Maths
Class	10th
Chapter-24	Graphical Representation of Statistical Data
Writer	RS Aggarwal
Book Name	Foundation
Topics	representing data on histogram and frequency polygon

 Representing Data on Histogram and Frequency Polygon

Class 10 RS Aggarwal Exe-24 ICSE Maths Solutions Ch-24.

Que-1: Draw a histogram to represent the following data :

Marks obtained	0-10	10-20	20-30	30-40	40-50	50-60
No. of students	4	7	12	20	9	2

 

Sol:

Que-2: Draw a histogram to represent the following data :

Pocket money(in rupees)	150-200	200-250	250-300	300-350	350-400
No. of students	10	5	7	4	3

Sol:

Que- 3: Construct a histogram for the following frequency distribution :

Class interval	5-12	13-20	21-28	29-36	37-44	45-52
Frequency	4	12	26	15	6	18

Sol: Clearly , the given frequency distribution is in inclusive form . So, first we convert it to the exclusive form .
Adjustment factor = (13-12/2) = 0.5

Que-4: The following table shows the number of illiterate persons in the age group (10-69) in a town

Age-Group (in years)	10-19	20-29	30-39	40-49	50-59	60-69
No. of illiterate persons	50	125	190	275	340	410

Sol: Clearly , the given frequency distribution is in inclusive form . So, first we convert it to the exclusive form .
Adjustment factor = (20-19/2) = 0.5

Que-5: Draw a histogram to represent the following data :

Class-Mark	150	160	170	180	190	200
Frequency	15	28	12	36	8	18

Sol:

Que-6: In a study of diabetic patients in a village , the following observations were noted:

Age in years	10-20	20-30	30-40	40-50	50-60	60-70
No. of patients	2	5	12	19	9	4

Sol: Represent the above data by a frequency polygon –

We plot the following points on the graph : (5, 0), (15, 2), (25, 5), (35, 12), (45, 19), (55, 9), (65, 4) and (75, 0) and join them to form a frequency polygon as given below :

 Que-7: The ages (in years) of 360 patients treated in a hospital on a particular day are given below

Age in years	10-20	20-30	30-40	40-50	50-60	60-70
No. of patients	90	40	60	20	120	30

Sol:

Que-8: Draw a histogram and the frequency polygon from the following data:

Class-interval	20-25	25-30	30-35	35-40	40-45	45-50
Frequency	30	24	52	28	46	10

Sol:

Que-9: Draw a histogram for the following data:

Class-interval	600-640	640-680	680-720	720-760	760-800	800-840
Frequency	18	45	153	288	171	63

Sol: The given data with class mark of each class interval :
First we draw a histogram, then polygon.

Now, plotting the mid points –

Que-10: Draw an ogive to represent the following data :

Class-interval	400-450	450-500	500-550	550-600	600-650	650-700	700-750
Frequency	16	25	40	32	18	27	9

Sol: The table in cumulative frequency form,

Now, plot the point (450, 16), (500, 41), (550, 81), (600, 113), (650, 131), (700, 158) and (750, 167) on the graph and join them in free hand to get an ogive as shown in the figure.

Que-11: Draw an ogive for the following frequency distribution:

Marks obtained	Less than 10	Less than 20	Less than 30	Less than 40	Less than 50
No. of students	8	23	43	50	64

Sol: The cumulative frequency table :

Plot the point (10, 8), (20, 23), (30, 43), (40, 50) and (50, 64) on the graph and join them to from an ogive.

Que-12: Draw an ogive for the following frequency distribution:

Class-interval	10-19	20-29	30-39	40-49	50-59
Frequency	21	15	12	19	8

Sol: Class interval in exclusive form and cumulative frequency is –

Now, plot the point (19.5, 21), (29.5, 36), (39.5, 48), (49.5, 67) and (59.5, 75) on the graph and  then by joining them to get an ogive as shown-

Que-13: Draw a ogive  …………………… following data .

Class-interval	1-10	11-20	21-30	31-40	41-50	51-60
Frequency	4	6	8	11	7	5

Sol: Class interval in exclusive form and cumulative frequency is –

Now, plot the point (10.5, 4), (20.5, 10), (30.5, 18), (40.5, 29), (50.5, 36) and (60.5, 41) on the graph and  then by joining them to get an ogive as shown-

— : Graphical Representation of Statistical Data Class 10 RS Aggarwal Exe-24 ICSE Maths Solutions  :–

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