Integers Class- 7th RS Aggarwal Exe-1C Goyal Brothers ICSE Math Solution . We provide step by step Solutions of lesson-1 Integers for ICSE Class-7 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan . Our Solutions contain all type Questions of Exe-1 C to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-7 Mathematics.
Integers Class- 7th RS Aggarwal Exe-1C Goyal Brothers ICSE Math Solution
Board | ICSE |
Publications | Goyal brothers Prakashan |
Subject | Maths |
Class | 7th |
Chapter-1 | Integers |
Writer | RS Aggrawal |
Book Name | Foundation |
Topics | Solution of Exe-1 C |
Academic Session | 2023 – 2024 |
Exercise – 1 C
Integers Class- 7th RS Aggarwal Exe-1C Goyal Brothers ICSE Math Solution
Question: 1. Find the product :
(i) 18 × 4
Answer: Given: 18 × 4
18 × 4
= 72
(ii) (-25) × 6
Answer: Given: (-25) × 6
(-25) × 6
= -125
(iii) (-30) × 7
Answer: Given: (-30) × 7
(-30) × 7
= -210
(iv) 8 × (-15)
Answer: Given: 8 × (-15)
8 × (-15)
= -120
(v) 20 × (-10)
Answer: Given: 20 × (-10)
20 × (-10)
= -200
(vi) (-12) × (-15)
Answer: Given: (-12) × (-15)
(-12) × (-15)
= 180
(vii) (-8) × (-13)
Answer: Given: (-8) × (-13)
(-8) × (-13)
= 104
(viii) (-20) × (-1)
Answer: Given: (-20) × (-1)
(-20) × (-1)
= 20
(ix) (-9) × 0
Answer: Given: (-9) × 0
(-9) × 0
= 0
(x) 0 × (-11)
Answer: Given: 0 × (-11)
0 × (-11)
= 0
Question: 2. Find the product :
(i) {(-9) × 8} × (-5)
Answer: Given: {(-9) × 8} × (-5)
{(-72)} × (-5)
= 360
(ii) {(-10) × (-5)} × 6
Answer: Given: {(-10) × (-5)} × 6
{(-50)} × 6
= -300
(iii) {(-12) × (-15)} × (-2)
Answer: Given: {(-12) × (-15)} × (-2)
180 × (-2)
= -360
(iv) (-8) × {(-5) × (-3)}
Answer: Given: (-8) × {(-5) × (-3)}
(-8) × {15}
= -120
(v) (-11) × {(-8) × 5}
Answer: Given: (-11) × {(-8) × 5}
(-11) × {-40}
= 440
Question: 3. Verify the following :
(i) (-14) × (-8) = (-8) × (-14)
Answer: Given: (-14) × (-8) = (-8) × (-14)
112 = 112
∴ L.H.S = R.H.S
(ii) {(-7) × 5} × (-6) = (-7) × {5 × (-6)}
Answer: Given: {(-7) × 5} × (-6) = (-7) × {5 × (-6)}
{-35} × (-6) = (-7) × {-30}
210 = 210
∴ L.H.S = R.H.S
(iii) (-10) × {(-7) + (-9)} = {(-10) × (-7)} + {(-10) × (-9)}
Answer: Given: (-10) × {(-7) + (-9)} = {(-10) × (-7)} + {(-10) × (-9)}
(-10) × {-7 -9} = {70} + {90}
(-10) × (-16) = 70 + 90
160 = 160
∴ L.H.S = R.H.S
Question: 4. Find the quotient :
(i) 28 ÷ (-7)
Answer: Given: 28 ÷ (-7)
28 ÷ (-7)
= -4
(ii) (-65) ÷ 13
Answer: Given: (-65) ÷ 13
(-65) ÷ 13
= -5
(iii) (-66) ÷ (-6)
Answer: Given: (-66) ÷ (-6)
(-66) ÷ (-6)
= 11
(iv) (-9) ÷ (-1)
Answer: Given: (-9) ÷ (-1)
(-9) ÷ (-1)
= 9
(v) 0 ÷ (-2)
Answer: Given: 0 ÷ (-2)
0 ÷ (-2)
= 0
(vi) (-12) ÷ (-12)
Answer: Given: (-12) ÷ (-12)
(-12) ÷ (-12)
= 1
Question: 5. Write all even integers between (i) (-4) and 11 (ii) (-13) and (-7)
Answer: (i) (-4) and 11
All even integer between -4 and 11 will be –
-2, 0, 2, 4, 6, 8, 10.
(ii) (-13) and (-7)
All even integer between (-13) and (-7) will be –
-12, -10, -8.
Question: 6. Write all odd integers between (i) (-1) and 7 (ii) (-20) and (-14)
Answer: (i) (-1) and 7
All odd integer between (-1) and 7 will be –
1, 3, 5.
(ii) (-20) and (-14)
All odd integer between (-20) and (-14) will be –
-19, -17, -15.
Question: 7. Write five consecutive even integers succeeding -21.
Answer: Solution: five consecutive even integers succeeding -21 will be –
-20, -18, -16, -14, -12.
Question: 8. Write five consecutive odd integers preceding -36.
Answer: Solution: five consecutive odd integers preceding -36 will be –
-37, -39, -41, -43, -45.
Question: 9. The product of two integers is -120. If one number is 15, find the other.
[Hint: Other number = -120 ÷ 15]
Answer: Solution:-
one number = 15
other number = ?
product of both number = -120
∴ Let the other No. be x
So, According to question –
15 × x =-120
x = -120/15
x = -8
∴ The other number is -8.
— : end of Integers Class- 7th RS Aggarwal Exe-1C Goyal Brothers ICSE Math Solution :–
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Answer: Given: (-25) × 6
(-25) × 6
= -125 is wrong its -150
please write que number also