Integers Class- 7th RS Aggarwal Exe-1D Goyal Brothers ICSE Math Solution . We provide step by step Solutions of lesson-1 Integers for ICSE Class-7 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan . Our Solutions contain all type Questions of Exe-1 D to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-7 Mathematics.
Integers Class- 7th RS Aggarwal Exe-1D Goyal Brothers ICSE Math Solution
| Board | ICSE |
| Publications | Goyal brothers Prakashan |
| Subject | Maths |
| Class | 7th |
| Chapter-1 | Integers |
| Writer | RS Aggrawal |
| Book Name | Foundation |
| Topics | Solution of Exe-1 D |
| Academic Session | 2023 – 2024 |
Exercise – 1 D
Integers Class- 7th RS Aggarwal Exe-1 D Goyal Brothers ICSE Math Solution
Question: 1. Simplify :
(i) 5 {(-6) + (12 ÷ 4)}
Answer: Given: 5 {(-6) + (12 ÷ 4)}
= 5 { -6 + 3}
= 5 × (-3)
= -15
(ii) 10 – {56 ÷ (-16 +9)}
Answer: Given: 10 – {56 ÷ (-16 +9)}
= 10 – {56 ÷ (-7)}
= 10 – {-8}
= 10 + 8
= 18
(iii) (-6) – {(-28) ÷ (-7)}
Answer: Given: (-6) – {(-28) ÷ (-7)}
= (-6) – {4}
= -6 – 4
= -10
(iv) 8 – {12 – (9 – 7 – 4)}
Answer: Given: 8 – {12 – (9 – 7 – 4)}
= 8 – {12 – (9 – 3)}
= 8 – {12 – 6 }
= 8 – 6
= 2
(v) 11 – [(-8) – {10 – (9 – 7 – 4)}]
Answer: Given: 11 – [(-8) – {10 – (9 – 7 – 4)}]
= 11 – [(-8) – {10 – (9 – 3)}]
= 11 – [(-8) – {10 – 6}]
= 11 – [(-8) – 4]
= 11 – [-12]
= 11 + 12
= 23
(vi) (-9) – [(-5) – {11 – (8 – 5 -2)}]
Answer: Given: (-9) – [(-5) – {11 – (8 – 5 -2)}]
= (-9) – [(-5) – {11 – (8 – 3)}]
= (-9) – [(-5) – {11 – 5}]
= (-9) – [(-5) – 6]
= (-9) – [-11]
= -9 + 11
= 2
(vii) 10 – [8 – {11 + 30 ÷ (4 – 5 – 7)}]
[Hint: 10 – [8 – {11 + 30 ÷ (4 + 2)}]]
Answer: Given: 10 – [8 – {11 + 30 ÷ (4 – 5 – 7)}]
= 10 – [8 – {11 + 30 ÷ (4 – 2)}]
= 10 – [8 – {11 + 30 ÷ 6}]
= 10 – [8 – {11 + 5}
= 10 – [8 – 16]
= 10 – [-8]
= 10 + 8
= 18
— : end of Integers Class-7th RS Aggarwal Exe-1 D Goyal Brothers ICSE Math Solution :–
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