# Integers Class- 7th RS Aggarwal Exe-1D Goyal Brothers ICSE Math Solution

Integers Class- 7th RS Aggarwal Exe-1D Goyal Brothers ICSE Math Solution . We provide step by step Solutions of lesson-1 Integers for ICSE Class-7 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan . Our Solutions contain all type Questions of Exe-1 D to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-7 Mathematics.

## Integers Class- 7th RS Aggarwal Exe-1D Goyal Brothers ICSE Math Solution

 Board ICSE Publications Goyal brothers Prakashan Subject Maths Class 7th Chapter-1 Integers Writer RS Aggrawal Book Name Foundation Topics Solution of Exe-1 D Academic Session 2023 – 2024

### Exercise – 1 D

Integers Class- 7th RS Aggarwal Exe-1 D Goyal Brothers ICSE Math Solution

#### Question: 1. Simplify :

(i) 5 {(-6) + (12 ÷ 4)}

Answer: Given: 5 {(-6) + (12 ÷ 4)}

= 5 { -6 + 3}

= 5 × (-3)

= -15

(ii) 10 – {56 ÷ (-16 +9)}

Answer: Given: 10 – {56 ÷ (-16 +9)}

= 10 – {56 ÷ (-7)}

= 10 – {-8}

= 10 + 8

= 18

(iii) (-6) – {(-28) ÷ (-7)}

Answer: Given: (-6) – {(-28) ÷ (-7)}

= (-6) – {4}

= -6 – 4

= -10

(iv) 8 – {12 – (9 – 7 – 4)}

Answer: Given: 8 – {12 – (9 – 7 – 4)}

= 8 – {12 – (9 – 3)}

= 8 – {12 – 6 }

= 8 – 6

= 2

(v) 11 – [(-8) – {10 – (9 – 7 – 4)}]

Answer: Given: 11 – [(-8) – {10 – (9 – 7 – 4)}]

= 11 – [(-8) – {10 – (9 – 3)}]

= 11 – [(-8) – {10 – 6}]

= 11 – [(-8) – 4]

= 11 – [-12]

= 11 + 12

= 23

(vi) (-9) – [(-5) – {11 – (8 – 5 -2)}]

Answer: Given: (-9) – [(-5) – {11 – (8 – 5 -2)}]

= (-9) – [(-5) – {11 – (8 – 3)}]

= (-9) – [(-5) – {11 – 5}]

= (-9) – [(-5) – 6]

= (-9) – [-11]

= -9 + 11

= 2

(vii) 10 – [8 – {11 + 30 ÷ (4 – 5 – 7)}]

[Hint: 10 – [8 – {11 + 30 ÷ (4 + 2)}]]

Answer: Given: 10 – [8 – {11 + 30 ÷ (4 – 5 – 7)}]

= 10 – [8 – {11 + 30 ÷ (4 – 2)}]

= 10 – [8 – {11 + 30 ÷ 6}]

= 10 – [8 – {11 + 5}

= 10 – [8 – 16]

= 10 – [-8]

= 10 + 8

= 18

— : end of Integers Class-7th RS Aggarwal Exe-1 D Goyal Brothers ICSE Math Solution :–