# Introduction to Physics HC Verma Que for Short Ans Vol-1 Ch-1

Introduction to Physics HC Verma Que for Short Ans Vol-1 Ch-1 Concept of Physics. Step by Step Solution of Questions for short answer of Ch-1 Introduction to Physics. Visit official Website CISCE for detail information about ISC Board Class-11 Physics.

**Introduction to Physics HC Verma Que for Short Ans Vol-1 Ch-1 Concept of Physics**

Board | ISC and other board |

Publications | Bharti Bhawan Publishers |

Ch-1 | Introduction to Physics |

Class | 11 |

Vol | 1st |

writer | H C Verma |

Book Name | Concept of Physics |

Topics | Solutions of Question for short answer |

Page-Number | 8 , 9 |

**-: Select Topics :-**

Ques for Short Ans

**Introduction to Physics HC Verma Que for Short Ans Vol-1 Ch-1 Concept of Physics**

(Page-8)

**Question 1 :**

The meter is defined as the distance travelled by light in

1/1299, 792, 458 second. Why didn’t people choose some easier number such as

1/1300, 000, 000second? Why not 1 second?

**Answer 1:**

The speed of light in vacuum is 299,792,458 m/s.

Then time taken by light to cover a distance of 1 metre in vacuum =1/1299, 792, 458s

Hence, the metre is defined as the distance travelled by light in 1/1299, 792, 458s.

As 300,000,000 m/s is an approximate speed of light in vacuum, it cannot be used to define the metre.

The distance travelled by light in one second is 1/299,792,458 m. This is a large quantity and cannot be used as a base unit. So, the metre is not defined in terms of second.

**Question 2 :**

**What are the dimensions of:**

(a) volume of a cube of edge *a*,

(b) volume of a sphere of radius *a*,

(c) the ratio of the volume of a cube of edge *a* to the volume of a sphere of radius *a*?

**Answer 2:**

(a) Volume of a cube of edge *a*,

V=a×a×a

[*V*] = L×L×L = L^{3}

(b) Volume of a sphere of radius *a*,

V=4/3π(a)3

[*V*] = L×L ×L = L^{3}

(c)

Volume of a cube of edge *a/Volume of a sphere of radius a*

*L ^{3} / L^{3 }*

^{=1}

Hence The ratio of the volume of the cube to the volume of the sphere is a dimensionless quantity.

Page-9

**Question 3:**

Suppose you are told that the linear size of everything in the universe has been doubled overnight. Can you test this statement by measuring sizes with a metre stick? Can you test it by using the fact that the speed of light is a universal constant and has not changed? What will happen if all the clocks in the universe also start running at half the speed?

**Answer 3:**

The validity of this statement cannot be tested by measuring sizes with a metre stick, because the size of the metre stick has also got doubled overnight.Yes, it can be verified by using the fact that speed of light is a universal constant and has not changed. If the linear size of everything in the universe is doubled and all the clocks in the universe starts running at half the speed, then we cannot test the validity of this statement by any method.

**Question 4:**

If all the terms in an equation have same units, is it necessary that they have same dimensions? If all the terms in an equation have same dimensions, is it necessary that they have same units?

**Answer 4:**

Yes, if all the terms in an equation have the same units, it is necessary that they have the same dimension.

No, if all the terms in an equation have the same dimensions, it is not necessary that they have the same unit. It is because two quantities with different units can have the same dimension, but two quantities with different dimensions cannot have the same unit. For example angular frequency and frequency, both have the dimensions

[T-1]but units of angular frequency is rd/s and frequency is Htz. Another example is energy per unit volume and pressure.Both have the dimensions of [ML-1T-2]but units of pressure is N/m^{2} and that of energy per unit volume is J/m^{3}

**Question 5:**

If two quantities have same dimensions, do they represent same physical content?

**Answer 5:**

No, even if two quantities have the same dimensions, they may represent different physical contents.

Example: Torque and energy have the same dimension, but they represent different physical contents.

**Question 6:**

It is desirable that the standards of units be easily available, invariable, indestructible and easily reproducible. If we use foot of a person as a standard unit of length, which of the above features are present and which are not?

**Answer 6:**

If we use the foot of a person as a standard unit of length,features that will not be present are variability, destructibility and reproducible nature and the feature that will be present is the availability of the foot of a person to measure any length.

**Question 7:**

Suggest a way to measure:

(a) the thickness of a sheet of paper,

(b) the distance between the sun and the moon.

**Answer 7:**

(a) The thickness of a sheet of paper can roughly be determined by measuring the height of a stack of paper.

Example: Let us consider a stack of 100 sheets of paper. We will use a ruler to measure its height. In order to determine the thickness of a sheet of paper, we will divide the height of the stack with the number of sheets (i.e., 100).

(b) The distance between the Sun and the Moon can be measured by using Pythagoras theorem when the Earth makes an angle of 90^{âˆ˜} with the Sun and the Moon. We already know the distances from the Sun to the Earth and from the Earth to the Moon. However, these distances keep on changing due to the revolution of the Moon around the Earth and the revolution of the Earth around the Sun.

— : End of Introduction to Physics HC Verma Que for Short Ans :–

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