Language of Chemistry Exe-1C Very Short Chemistry Class-9 ICSE Selina Publishers

Language of Chemistry Exe-1C Very Short Chemistry Class-9 ICSE Selina Publishers Solutions Chapter-1. Step By Step ICSE Selina Concise Solutions of Chapter-1 Language of Chemistry with All Exercise including MCQs, Very Short Answer Type, Short Answer Type, Long Answer Type, Numerical and Structured/Application Questions Solved . Visit official Website CISCE for detail information about ICSE Board Class-9.

Language of Chemistry Exe-1C Very Short Chemistry Class-9 ICSE Concise Selina Publishers

Board	ICSE
Publications	Selina Publication
Subject	Chemistry
Class	9th
Chapter-1	Language of Chemistry
Book Name	Concise
Topics	Solution of Exercise – (1C) Very Short Answer Type
Academic Session	2023-2024

B. Exercise – (1C) Very Short Answer Type

Language of Chemistry Class-9 Chemistry Concise Solutions  

Page 19

Question 1.

Fill in the blanks:

(a) Dalton used symbol _____ for oxygen _____ for hydrogen.

(b)Symbol represents _____ atom(s) of an element.

(c)Symbolic expression for a molecule is called _____.  .

(d)Sodium chloride has two radicals. Sodium is a _____ radical while chloride is _____ radical.

(e)Valence of carbon in CH₄ is _____, in C₂H₆ _____, in C₂H₄ ___ and in C₂H₂ is ____.

(f)Valence of Iron in FeCl₂ is _____ and in FeCl₃ it is ____.

(g)Formula of iron (ill) carbonate is _____.

Answer:

(a) Dalton used symbol [O] for oxygen,[H] for hydrogen.

(b) Symbol represents gram atom(s) of an element.

(c) Symbolic expression for a molecule is called molecular formula.

(d) Sodium chloride has two radicals. Sodium is a basic radical, while chloride is an acid radical.

(e) Valence of carbon in CH₄ is 4, in C₂H₆4, in C₂H₄4 and in C₂H₂ is 4.

(f) Valence of iron in FeCl₂ is 2 and in FeCl₃ it is 3.

(g) Formula of iron (III) carbonate is Fe₂ [CO₃]₃.

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B. Exercise – (1C) Very Short Answer Type

Language of Chemistry Class-9 Chemistry Concise Solutions  

Page 20

Question 2.

Complete the following table.

Acid Radicals → Basic Radicals ↓	Chloride	Nitrate	Sulphate	Carbonate	Hydroxide	Phosphate
Magnesium	MgCl2	Mg(NO3)2	MgSO4	MgCO3	Mg(OH)2	Mg3(PO4)2
Sodium
Zinc
Silver
Ammonium
Calcium
Iron (II)
Potassium

Answer:

The completed table is given below:

Acid Radicals → Basic Radicals ↓	Chloride	Nitrate	Sulphate	Carbonate	Hydroxide	Phosphate
Magnesium	MgCl2	Mg(NO3)2	MgSO4	MgCO3	Mg(OH)2	Mg3(PO4)2
Sodium	NaCl	NaNO3	Na2SO4	Na2CO3	NaOH	Na3PO4
Zinc	ZnCl2	Zn(NO3)2	ZnSO4	ZnCO3	Zn(OH)2	Zn3(PO4)2
Silver	AgCl	AgNO3	Ag2SO4	Ag2CO3	AgOH	Ag3PO4
Ammonium	NH4Cl	NH4NO3	(NH4)2SO4	(NH4)2CO3	NH4OH	(NH4)3PO4
Calcium	CaCl2	CaNO3	CaSO4	CaCO3	Ca(OH)2	Ca3(PO4)2
Iron (II)	FeCl2	Fe(NO3)2	FeSO4	FeCO3	Fe(OH)2	Fe3(PO4)2
Potassium	KCl	KNO3	K2SO4	K2CO3	KOH	K3PO4

Question 3.

Correct the following statements.

(a) A molecular formula represents an element.

(b) Molecular formula of water is H₂O₂.

(c) A molecule of sulphur is monoatomic.

(d) CO and Co both represent cobalt.

(e) Formula of iron (III) oxide is FeO.

Answer:

(a) A molecular formula represents the molecule of an element or of a compound.

(b) Molecular formula of water is H₂O.

(c) A molecule of sulphur is octatomic.

(d) CO represents Carbon Monoxide and Co represents cobalt.

(e) Formula of iron (III) oxide is Fe₂O₃.

Question 4.

Give the empirical formula of :(a) Benzene (C₆H₆)(b) Glucose (C₆H₁₂O₆)

(c) Acetylene (C₂H₂)

(d) Acetic acid (CH₃COOH)

Answer:

(a) Ratio of C and H atoms in Benzene (C₆H₆) = 6 : 6
Simplest Ratio = 1 : 1
∴ Empirical formula of Benzene (C₆H₆) = CH

(b) Ratio of C, H and O atoms in Glucose (C₆H₁₂O₆) = 6 : 12 : 6
Simplest Ratio = 1 : 2 : 1
∴ Empirical formula of Glucose (C₆H₁₂O₆) = CH₂O

(c) Ratio of C and H atoms in Acetylene (C₂H₂) = 2 : 2
Simplest Ratio = 1 : 1
∴ Empirical formula of Acetylene (C₂H₂) = CH

(d) Ratio of C, H and O atoms in Acetic acid (CH₃COOH) = 2 : 4 : 2
Simplest Ratio = 1 : 2 : 1
∴ Empirical formula of Acetic acid (CH₃COOH) = CH₂O

—  : End of Language of Chemistry Exe-1C Very short Answer Class-9 ICSE Chemistry Solutions :–

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