ML Aggarwal Data Handling Exe-15.4 Class 6 ICSE Maths Solutions
ML Aggarwal Data Handling Exe-15.4 Class 6 ICSE Maths Solutions. We Provide Step by Step Answer of Exe-15.4 Questions for Data Handling as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-6.
ML Aggarwal Data Handling Exe-15.4 Class 6 ICSE Maths Solutions
| Board | ICSE |
| Publications | Avichal Publishig Company (APC) |
| Subject | Maths |
| Class | 6th |
| Chapter-15 | Data Handling |
| Writer | ML Aggarwal |
| Book Name | Understanding |
| Topics | Solution of Exe-15.4 Questions |
| Edition | 2023-2024 |
Data Handling Exe-15.4
ML Aggarwal Class 6 ICSE Maths Solutions
Page-317
Question 1. Find the mean of the following data :
(i) 40, 30, 30, 0, 26, 60
(ii) 3, 5, 7, 9, 11, 13, 15
Answer:
(i) Mean of 40, 30, 30, 0, 26, 60
No. of data (n) = 6
∴ Mean = 40 + 30 + 30 + 0 + 26 + 60/6
= 186/6 = 31
(ii) Mean of 3, 5, 7, 9, 11, 13, 15
No. of data = 7
∴ Mean = 3 + 5 + 7 + 9 + 11 + 13 + 15/7
= 63/7 = 9
Question 2. Find the mean of the first five even whole numbers.
Answer:
First five even whole numbers are 0, 2, 4, 6, 8
Number of data = 5
∴ Mean = 0 + 2 + 4 + 6 + 8/5
= 20/5 = 4
Question 3. A batsman scored the following number of runs in six innings :
36, 35, 50, 46, 60, 55
Calculate the mean runs scored by him in an inning.
Answer:
In six innings, run scored was
36, 35, 50, 46, 60, 55
∴ Mean = 36 + 35 + 50 + 46 + 60 + 55/6
= 282/6
= 47
Question 4. The enrolment in a school for six consecutive years was as follows :
1555, 1670, 1750, 2013, 2540, 2825
Find the mean enrolment of the school for this period.
Answer:
Enrolment for 6 consecutive years is
1555, 1670, 1750, 2013, 2540, 2825
∴ Mean = 1555 + 1670 + 1750 + 2013 + 2540 + 2825/6
= 12353/6 = 2058.83 = 2059
Question 5. The marks (out of 100) obtained by a group of students in a science test are :
85, 76, 90, 85, 39, 48, 56, 95, 81, 75
Find the:
(i) highest and lowest marks obtained by the students.
(ii) mean marks obtained by the students.
Answer:
Marks obtained by a group of students in science test
85, 76, 90, 85, 39, 48, 56, 95, 81, 75
(i) Highest marks obtained = 95
Lowest marks = 39
(ii) Mean marks = 85 + 76 + 90 + 85 + 39 + 48 + 56 + 95 + 81 + 75/10 (Here n = 10)
= 730/10 = 73
— : End of ML Aggarwal Data Handling Exe-15.4 Class 6 ICSE Maths Solutions :–
Return to – ML Aggarwal Maths Solutions for ICSE Class -6
Thanks
