ML Aggarwal Exponents and Powers Exe-4.3 Class 7 ICSE Maths Solutions

ML Aggarwal Exponents and Powers Exe-4.3 Class 7 ICSE Maths Solutions. We Provide Step by Step Answer of  Exe-4.3 Questions for Exponents and Powers as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-7.

ML Aggarwal Exponents and Powers Exe-4.3 Class 7 Maths Solutions

Board	ICSE
Publications	Avichal Publishig Company (APC)
Subject	Maths
Class	7th
Chapter-4	Exponents and Powers
Writer	ML Aggarwal
Book Name	Understanding
Topics	Solution of Exe-4.3 Questions
Edition	2023-2024

Exponents and Powers Exe-4.3

ML Aggarwal Class 7 ICSE Maths Solutions

Page-97

Question 1. Write the following numbers in the standard form (or scientific notation):

(i) 530.7
(ii) 3908.78
(iii) 39087.8
(iv) 2.35
(v) 3,43,000
(vi) 70,00,000
(vii) 3,18,65,00,000
(viii) 893,000,000
(ix) 70,040,000,000

Answer:

(i) 530.7
= 5.307 × 10²
(ii) 3908.78
= 3.90878 × 10³
(iii) 39087.8
= 3.90878 × 10⁴

(iv) 2.35
= 2.35 × 10⁰
{a⁰= 1}
(v) 3,43,000
= 3.43000 × 10⁵
(vi) 70,00,000
= 7.0 × 10⁶
(vii) 3,18,65,00,000
= 3.186500000 × 10⁹
(viii) 893,000,000
= 8.93 × 10⁸
(ix) 70,040,000,000
= 7.004 × 10¹⁰

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Exponents and Powers Exe-4.3

ML Aggarwal Class 7 ICSE Maths Solutions

Page-98

Question 2. Write the following numbers in usual decimal notation:

(i) 4.7 × 10³
(ii) 1.205 × 10⁵
(iii) 1.234 × 10⁶
(iv) 4.87 × 10⁷
(v) 6.05 × 10⁸
(vi) 9.083 × 10¹¹

Answer:

(i) 4.7 × 10³ = 4700
(ii) 1.205 × 10⁵ = 120500
(iii) 1.234 × 10⁶ = 1234000
(iv) 4.87 × 10⁷ = 48700000
(v) 6.05 × 10⁸ = 605000000
(vi) 9.083 × 10¹¹ = 908300000000

Question 3. Express the numbers appearing in the following statements in scientific notation (or standard form):

(i) The distance between the earth and the moon is 384,000,000 m.
(ii) The diameter of the sun is 1,400,000,000m.
(iii) The universe is estimated to be about 12,0000,000 years old.
(iv) In a galaxy, there are on an average 100,000,000,000 stars.
(v) The distance of the sun from the centre of milky way galaxy is estimated to be 300,000,000,000,000,000 km.
(vi) The astronomical distance of unit is a light year (a light year is a distance travelled by the light in one year). A light year is about 9,467,500,000,000 kilometers.

Answer:

(i) The distance between the earth and the moon is 384,000,000 m.= 3.84 × 10⁸ m
(ii) The diameter of the sun is 1,400,000m .= 1.4 × 10⁸m
(iii) The universe is estimated to be about 12,0000,000 years old = 1.2 × 10¹⁰
(iv) In a galaxy, there are on an average 100,000,000 stars.= 1.4 × 10⁸m.
(v) The distance of the sun from the centre of milky way galaxy is estimated to be 300,000,000,000,000,000 km.= 3. 0× 10¹⁷
(vi) The astronomical distance of unit is a light year ( a light year is a distance travelled by the light in one year.) A light year is about 9,467,500,000,000 kilometres . = 9.4675 × 10¹² km

Question 4. Compare the following numbers:

(i) 4.3 × 10¹⁴; 3.01 × 10¹⁷
(ii) 1.439 × 10¹²; 1.4335 × 10¹²

Answer:

(i) 4.3 × 10¹⁴; 3.01 × 10¹⁷
3.01 × 10¹⁷ > 4.3 × 10¹⁴ {17 > 14}
(ii) 1.439 × 10¹²; 1.4335 × 10¹²
1.439 > 1.4335
1.439 × 10¹² > 1.4335 × 10¹²

(ML Aggarwal Exponents and Powers Exe-4.3 Class 7)

Question 5. Write the following numbers in the expanded Exponential form:

(i) 279404
(ii) 3006194
(iii) 28061906

Answer:

(i) 279404

= 2 × 10⁵  + 7 × 10⁴  + 9 × 10³  + 4 × 10²  + 4 × 10⁰
(ii) 3006194

= 3 × 10⁶ + 6 × 10³ + 1 × 10² + 9 × 10¹ + 4 × 10⁰

(iii) 28061906

= 2 × 10⁷ + 8 × 10⁶ + 6 × 10⁵ + 1 × 10³ + 9 × 10² + 6 × 10

Question 6. Find the number from each of the expanded form:

(i) 3 × 10⁴ + 7 × 10² + 5 × 10⁰
(ii) 4 × 10⁵ + 5 × 10³ + 3 × 10² + 2 × 10⁰
(iii) 8 × 10⁷ + 3 × 10⁴ + 7 × 10³ + 5 × 10² + 8 × 10¹

Answer:

(i) 3 × 10⁴ + 7 × 10² + 5 × 10⁰ = 30705

(ii) 4 × 10⁵ + 5 × 10³ + 3 × 10² + 2 × 10⁰

= 400000 + 5000 + 300 + 2 × 1
= 405302

(iii) 8 × 10⁷ + 3 × 10⁴ + 7 × 10³ + 5 × 10² + 8 × 10¹

= 80000000 + 30000 + 7000 + 500 + 80
= 80037580

—  : End of ML Aggarwal Exponents and Powers Exe-4.3 Class 7 ICSE Maths Solutions :–

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