ML Aggarwal Exponents and Powers Exe-4.3 Class 7 ICSE Maths Solutions. We Provide Step by Step Answer of  Exe-4.3 Questions for Exponents and Powers as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-7.

## ML Aggarwal Exponents and Powers Exe-4.3 Class 7 Maths Solutions

 Board ICSE Publications Avichal Publishig Company (APC) Subject Maths Class 7th Chapter-4 Exponents and Powers Writer ML Aggarwal Book Name Understanding Topics Solution of Exe-4.3 Questions Edition 2023-2024

### Exponents and Powers Exe-4.3

ML Aggarwal Class 7 ICSE Maths Solutions

Page-97

#### Question 1. Write the following numbers in the standard form (or scientific notation):

(i) 530.7
(ii) 3908.78
(iii) 39087.8
(iv) 2.35
(v) 3,43,000
(vi) 70,00,000
(vii) 3,18,65,00,000
(viii) 893,000,000
(ix) 70,040,000,000

(i) 530.7
= 5.307 × 102
(ii) 3908.78
= 3.90878 × 103
(iii) 39087.8
= 3.90878 × 104

(iv) 2.35
= 2.35 × 100
{a0= 1}
(v) 3,43,000
= 3.43000 × 105
(vi) 70,00,000
= 7.0 × 106
(vii) 3,18,65,00,000
= 3.186500000 × 109
(viii) 893,000,000
= 8.93 × 108
(ix) 70,040,000,000
= 7.004 × 1010

### Exponents and Powers Exe-4.3

ML Aggarwal Class 7 ICSE Maths Solutions

Page-98

#### Question 2. Write the following numbers in usual decimal notation:

(i) 4.7 × 103
(ii) 1.205 × 105
(iii) 1.234 × 106
(iv) 4.87 × 107
(v) 6.05 × 108
(vi) 9.083 × 1011

(i) 4.7 × 103 = 4700
(ii) 1.205 × 105 = 120500
(iii) 1.234 × 106 = 1234000
(iv) 4.87 × 107 = 48700000
(v) 6.05 × 108 = 605000000
(vi) 9.083 × 1011 = 908300000000

#### Question 3. Express the numbers appearing in the following statements in scientific notation (or standard form):

(i) The distance between the earth and the moon is 384,000,000 m.
(ii) The diameter of the sun is 1,400,000,000m.
(iii) The universe is estimated to be about 12,0000,000 years old.
(iv) In a galaxy, there are on an average 100,000,000,000 stars.
(v) The distance of the sun from the centre of milky way galaxy is estimated to be 300,000,000,000,000,000 km.
(vi) The astronomical distance of unit is a light year (a light year is a distance travelled by the light in one year). A light year is about 9,467,500,000,000 kilometers.

(i) The distance between the earth and the moon is 384,000,000 m.= 3.84 × 108 m
(ii) The diameter of the sun is 1,400,000m .= 1.4 × 108m
(iii) The universe is estimated to be about 12,0000,000 years old = 1.2 × 1010
(iv) In a galaxy, there are on an average 100,000,000 stars.= 1.4 × 108m.
(v) The distance of the sun from the centre of milky way galaxy is estimated to be 300,000,000,000,000,000 km.= 3. 0× 1017
(vi) The astronomical distance of unit is a light year ( a light year is a distance travelled by the light in one year.) A light year is about 9,467,500,000,000 kilometres . = 9.4675 × 1012 km

#### Question 4. Compare the following numbers:

(i) 4.3 × 1014; 3.01 × 1017
(ii) 1.439 × 1012; 1.4335 × 1012

(i) 4.3 × 1014; 3.01 × 1017
3.01 × 1017 > 4.3 × 1014 {17 > 14}
(ii) 1.439 × 1012; 1.4335 × 1012
1.439 > 1.4335
1.439 × 1012 > 1.4335 × 1012

(ML Aggarwal Exponents and Powers Exe-4.3 Class 7)

#### Question 5. Write the following numbers in the expanded Exponential form:

(i) 279404
(ii) 3006194
(iii) 28061906

(i) 279404

= 2 × 105  + 7 × 104  + 9 × 103  + 4 × 102  + 4 × 100
(ii) 3006194

= 3 × 106 + 6 × 103 + 1 × 102 + 9 × 101 + 4 × 100

(iii) 28061906

= 2 × 107 + 8 × 106 + 6 × 105 + 1 × 103 + 9 × 102 + 6 × 10

#### Question 6. Find the number from each of the expanded form:

(i) 3 × 104 + 7 × 102 + 5 × 100
(ii) 4 × 105 + 5 × 103 + 3 × 102 + 2 × 100
(iii) 8 × 107 + 3 × 104 + 7 × 103 + 5 × 102 + 8 × 101

(i) 3 × 104 + 7 × 102 + 5 × 100 = 30705

(ii) 4 × 105 + 5 × 103 + 3 × 102 + 2 × 100

= 400000 + 5000 + 300 + 2 × 1
= 405302

(iii) 8 × 107 + 3 × 104 + 7 × 103 + 5 × 102 + 8 × 101

= 80000000 + 30000 + 7000 + 500 + 80
= 80037580

—  : End of ML Aggarwal Exponents and Powers Exe-4.3 Class 7 ICSE Maths Solutions :–

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