ML Aggarwal Factorisation Exe-11.5 Class 8 ICSE Ch-11 Maths Solutions. We Provide Step by Step Answer of Exe-11.5 Questions for Factorisation as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-8.
ML Aggarwal Factorisation Exe-11.5 Class 8 ICSE Maths Solutions
| Board | ICSE |
| Publications | Avichal Publishig Company (APC) |
| Subject | Maths |
| Class | 8th |
| Chapter-11 | Factorisation |
| Writer | ML Aggarwal |
| Book Name | Understanding |
| Topics | Solution of Exe-11.5 Questions |
| Edition | 2023-2024 |
Factorisation Exe-11.5
ML Aggarwal Class 8 ICSE Maths Solutions
Page-199
Question 1. Work out the following divisions:
(i) (35x + 28) ÷ (5x + 4)
(ii) 7p2q2(9r – 27) ÷ 63pq(r – 3)
Answer:
(i) (35x + 28) ÷ (5x + 4)
(ii) 7p2q2(9r – 27) ÷ 63pq(r – 3)
= p2-1 q2-1 × 9 = 9pq
Question 2. Divide as directed:
(i) 6(2x + 7) (5x – 3) ÷ 3(5x – 3)
(ii) 33pq (p + 3) (2q – 5) ÷ 11p (2q – 5)
Answer:
(i) 6(2x + 7) (5x – 3) ÷ 3(5x – 3)
= 
= 2(2x + 7)
(ii) 33pq (p + 3) (2q – 5) ÷ 11p (2q – 5)
= 
= 3q(p + 3)
Factorisation Exe-11.5
ML Aggarwal Class 8 ICSE Maths Solutions
Page-200
Question 3. Factorise the expression and divide them as directed:
(i) (7x2 – 63x) ÷ 7(x – 3)
(ii) (3p2 + 17p + 10) ÷ (p + 5)
(iii) 10xy(14y2 + 43y – 21) ÷ 5x(7y – 3)
(iv) 12pqr(6p2 – 13pq + 6q2) ÷ 6pq(2p – 3q)
Answer:
(i) (7x2 – 63x) ÷ 7(x – 3)
(ii) (3p2 + 17p + 10 ) ÷ (p + 5)
= (3p2 + 17p + 10)/ (p + 5)
(iii) 10xy(14y2 + 43y – 21) ÷ 5x(7y – 3)
(iv) 12pqr(6p2 – 13pq + 6q2) ÷ 6pq(2p – 3q)
— End of Factorisation Exe-11.5 Class 8 ICSE Maths Solutions :–
Return to : – ML Aggarwal Maths Solutions for ICSE Class -8
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