ML Aggarwal Integers Check Your Progress Class 7 ICSE Maths Solutions. We Provide Step by Step Answer of  Check Your Progress Questions for Integers as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-7.

## ML Aggarwal Integers Check Your Progress Class 7 ICSE Maths Solutions

 Board ICSE Publications Avichal Publishig Company (APC) Subject Maths Class 7th Chapter-1 Integers Writer ML Aggarwal Book Name Understanding Topics Solution of Check Your Progress Questions Edition 2023-2024

ML Aggarwal Class 7 ICSE Maths Solutions

Page-27

#### Question 1. Evaluate the following:

(i) (-7) × (-9) × (-11)
(ii) (-5) × 7 × (-6) × (-8)
(iii) (-1024) ÷ 32
(iv) (-216) ÷ (-12)

(i) (-7) × (-9) × (-11)
= (63) × (-11)
= -693
(ii) (-5) × 7 × (-6) × (-8)
= -35 × (48)
= – 1680
(iii) (-1024) ÷ 32
= -1024/32
= – 32

(iv) (-216) ÷ (-12)
= -216/-12
= +18
= 18

#### Question 2. What will be the sign of the product if we multiply 39 negative integers and 98 positive integers?

39 is odd and 98 is even.
Product of 39 negative and 98 positive integers will negative.

#### Question 3. Use the sign >, < or = in the box to make the following statements true:

(i) (-15) + 38 ……… 27 + (-50)
(ii) (-13) × 0 × (-5) …….. (-7) × (-6) × 14
(iii) (-18) ÷ (-3) …….. (-10) + (-15) + 31
(iv) (-5) × (-7) × (-10) …….. (-1400) ÷ (-4)

(i) (-15) + 38 …….. 27 + (-50)
LHS = -15 + 38 = 23
RHS = 27 -50 = -23
(23) > (-23)

(ii) (-13) × 0 × (-5) ………… (-7) × (-6) × 14
LHS = -13 × 0 × (-5) = 0
And (-7) × (-6) × 14
RHS = 42 × 14 = 588
0 < 588
(iii) (-18) ÷ (-3) ……. (-10) + (-15) +31
LHS = -18 ÷ -3 = 6
RHS = (-10) + (-15) + 31 = -25 +31 = 6
6 = 6

#### Question 4. Is {(-45) ÷ (-15)} ÷ (-3) = (-45) ÷ [(-15) ÷ (-3)]?

(-45) ÷ (-15) ÷ (-3)
LHS =  (-45/-15) ÷ (-3)
= 3 ÷ -3
= -1
And
RHS = -45 ÷ (-15/-3)
= -45 ÷ 5
= -9

(-1) ≠ -9
No, not equal.

#### Question 5. Simplify the following:

(i) (-7) + (-6) ÷ 2 – {(-5) × (-4) – (3 – 5)}
(ii) 11 – [7 – (5 – 3 (9 – 36)}].

(i) (-7) + (-6) ÷ 2 – {(-5) × ( -4) – (3 – 5) }
= (-7) + (-6) ÷ 2 – [ +20 – (-2) ]
= (-7) + (-6) ÷ 2 – (20 + 2)
= (-7) + (-6/2) – 22
= ( -7) + (-3) – 22
= -7 – 3 – 22
= -32

(ii) 11 – [ 7 – { 5 – 3 ( 9 -3 – 6 ) }]
= 11 – [ 7 – { 5 – 3 ( 9 -3 + 6 ) }]

= 11 – [ 7 – ( 5 – 3 × 12}]

= 11 – [ 7 – ( 5 – 36 ) }]

= 11 – [ 7 – (-31) ]

= 11 – 38

= -27

—  : End of ML Aggarwal Integers Check Your Progress Class 7 ICSE Maths Solutions :–

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