ML Aggarwal Integers Check Your Progress Class 7 ICSE Maths Solutions. We Provide Step by Step Answer of Check Your Progress Questions for Integers as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-7.
ML Aggarwal Integers Check Your Progress Class 7 ICSE Maths Solutions
Board | ICSE |
Publications | Avichal Publishig Company (APC) |
Subject | Maths |
Class | 7th |
Chapter-1 | Integers |
Writer | ML Aggarwal |
Book Name | Understanding |
Topics | Solution of Check Your Progress Questions |
Edition | 2023-2024 |
Integers Check Your Progress
ML Aggarwal Class 7 ICSE Maths Solutions
Page-27
Question 1. Evaluate the following:
(i) (-7) × (-9) × (-11)
(ii) (-5) × 7 × (-6) × (-8)
(iii) (-1024) ÷ 32
(iv) (-216) ÷ (-12)
Answer:
(i) (-7) × (-9) × (-11)
= (63) × (-11)
= -693
(ii) (-5) × 7 × (-6) × (-8)
= -35 × (48)
= – 1680
(iii) (-1024) ÷ 32
= -1024/32
= – 32
(iv) (-216) ÷ (-12)
= -216/-12
= +18
= 18
Question 2. What will be the sign of the product if we multiply 39 negative integers and 98 positive integers?
Answer:
39 is odd and 98 is even.
Product of 39 negative and 98 positive integers will negative.
Question 3. Use the sign >, < or = in the box to make the following statements true:
(i) (-15) + 38 ……… 27 + (-50)
(ii) (-13) × 0 × (-5) …….. (-7) × (-6) × 14
(iii) (-18) ÷ (-3) …….. (-10) + (-15) + 31
(iv) (-5) × (-7) × (-10) …….. (-1400) ÷ (-4)
Answer:
(i) (-15) + 38 …….. 27 + (-50)
LHS = -15 + 38 = 23
RHS = 27 -50 = -23
(23) > (-23)
(ii) (-13) × 0 × (-5) ………… (-7) × (-6) × 14
LHS = -13 × 0 × (-5) = 0
And (-7) × (-6) × 14
RHS = 42 × 14 = 588
0 < 588
(iii) (-18) ÷ (-3) ……. (-10) + (-15) +31
LHS = -18 ÷ -3 = 6
RHS = (-10) + (-15) + 31 = -25 +31 = 6
6 = 6
Question 4. Is {(-45) ÷ (-15)} ÷ (-3) = (-45) ÷ [(-15) ÷ (-3)]?
Answer:
(-45) ÷ (-15) ÷ (-3)
LHS = (-45/-15) ÷ (-3)
= 3 ÷ -3
= -1
And
RHS = -45 ÷ (-15/-3)
= -45 ÷ 5
= -9
(-1) ≠ -9
No, not equal.
Question 5. Simplify the following:
(i) (-7) + (-6) ÷ 2 – {(-5) × (-4) – (3 – 5)}
(ii) 11 – [7 – (5 – 3 (9 – 3−6)}].
Answer:
(i) (-7) + (-6) ÷ 2 – {(-5) × ( -4) – (3 – 5) }
= (-7) + (-6) ÷ 2 – [ +20 – (-2) ]
= (-7) + (-6) ÷ 2 – (20 + 2)
= (-7) + (-6/2) – 22
= ( -7) + (-3) – 22
= -7 – 3 – 22
= -32
(ii) 11 – [ 7 – { 5 – 3 ( 9 -3 – 6 ) }]
= 11 – [ 7 – { 5 – 3 ( 9 -3 + 6 ) }]
= 11 – [ 7 – ( 5 – 3 × 12}]
= 11 – [ 7 – ( 5 – 36 ) }]
= 11 – [ 7 – (-31) ]
= 11 – 38
= -27
— : End of ML Aggarwal Integers Check Your Progress Class 7 ICSE Maths Solutions :–
Return to – ML Aggarwal Maths Solutions for ICSE Class -7
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