ML Aggarwal Matrices Ch-Test Class 10 ICSE Maths Solutions Ch-8

ML Aggarwal Matrices Ch-Test Class 10 ICSE Maths Solutions Ch-8. We Provide Step by Step Answer of Ch-Test Questions for Matrices as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-10.

ML Aggarwal ML Aggarwal Matrices Ch-Test Class 10 ICSE Maths Solutions Ch-8

Board	ICSE
Subject	Maths
Class	10th
Chapter-8	Matrices
Writer / Book	Understanding
Topics	Solutions of Ch-Test
Academic Session	2024-2025

Matrices, Ch-Test Questions

ML Aggarwal Class 10 ICSE Maths Solutions Ch-8

Page-162

Question-1 Find the values of a and b if

Answer -1

comparing the corresponding elements
a + 3 = 2a + 1
⇒ 2a – a =3 – 1
⇒ a = 2
b² + 2 = 3b
⇒ b² – 3b + 2 = 0
⇒ b² – b – 2b + 2 = 0
⇒ b (b – 1) – 2 (b – 1) = 0
⇒ (b – 1) (b – 2) = 0.
Either b – 1 = 0, then b = 1
or b – 2 = 0, then b = 2
Hence a = 2, b = 2 or 1

Question -2 Find a, b, c and d if

Answer -2

Given

Question-3 Determine the matrices A and B when
A + 2B = and 2A – B =

Answer -3

A + 2B = …..(i)
2A – B = …….(ii)
Multiplying (i) by 1 and (ii) by 2

Question-4 (i) Find the matrix B if A = and A² = A + 2B

Answer -4

(i)

A =

Comparing the corresponding elements
4 + 2a = 18
⇒ 2a = 18 – 4 = 14
∴ a = 7
1 + 2b = 7
⇒ 2b = 7 – 1 = 6
∴ b = 3
2 + 2c = 14
⇒ 2c = 14 – 2 = 12
∴ c = 6
3 + 2d = 11
⇒ 2d = 11 – 3 = 8
∴ d = 4
Hence a = 7, b = 3, c = 6, d = 4

(ii)

Question -5 If A = and B = find the each of the following and state it they are equal:
(i) (A + B)(A – B)
(ii)A² – B²

Answer-5 (i) Given
A = and B =

(A + B) (A – B)

(ii) A² – B²

It is clear that (A + B) (A – B) ≠ A² – B² .

Question -6 If A = find A² – 5A – 14 I Where I is unit matrix of order 2 x 2

Answer-6

Given
A =

Question-7

If A = and A² = 0 find p and q

Answer -7

Given
A =

Comparing the corresponding elements
9 + 3p = 0
⇒ 3p = –9
⇒ p = –3
9 + 3q = 0
⇒ 3q = –9
⇒ q = –3
Hence p = –3, q = –3.

Question -8 find a, b, c and d if

Answer-8

Given

Comparing the corresponding elements
–a = 1
⇒ a = –1
–b = 0
⇒ b = 0
c = 0 and d = –1
Hence a = –1, b = 0, c = 0, d = –1.

Question -9 Find a and b if

Answer -9

Given

Comparing the corresponding elements
2a – 4 = 0
⇒ 2a = 4
⇒ a = 2
2a – 2b = –2
⇒ 2 x 2 – 2b = –2
⇒ 4 – 2b = –2
⇒ –2b = –2 – 4 = –6
⇒ b = 3
Hence a = 2, b = 3.
Question -10 If A = and B =
Find (i) 2A – 3B (ii) A² (iii) BA