# Moving Charge and Magnetism Nootan Solutions ISC Class-12 Physics

Moving Charge and Magnetism Nootan Solutions ISC Class-12 Physics Nageen Prakashan Chapter-7 Solved Numericals. Step by step Solutions of Kumar and Mittal ISC Physics Class-12 Nageen Prakashan Numericals Questions. Visit official Website **CISCE** for detail information about ISC Board Class-12 Physics.

## Moving Charge and Magnetism Nootan Solutions ISC Class-12 Physics Nageen Prakashan Chapter-7 Numericals of Kumar and Mittal

Class: | 12 |

Subject: | Physics |

Chapter 7: | Moving Charge and Magnetism |

Board | ISC |

Writer /Publications | Nootan / Nageen Prakashan/Kumar and Mittal |

Topics | Solved Numericals of page 338 , 339, 340, 341 |

### Moving Charge and Magnetism Nootan Solutions ISC Class-12 Physics Chapter-7 Numericals ( Kumar and Mittal Nageen Prakashan )

page-number : 338

**Question 1**

A long ……….35 A……. wire

**Answer 1**

**Question 2**

A long ……50 A…….. wire

**Answer 2**

by right hand thumb rule magnetic field will be vertically upward

**Question 3**

Two …………… field

**Answer 3**

Since the point P is at right side of both the wire therefore M.F. due to both wire will be down ward perpendicular to plane of paper

and its magnitude will be sum of magnitude of magnetic field of two wire.

page-number : 339

**Question 4**

An electron ……………… 50 cm

**Answer 4**

Q = I t

N e = I t (Q = n e)

**Question 5**

Two long ……………… directions

**Answer 5**

In case of same current in two parallel wire magnetic field at mid point will be equal and opposite. so the net field will be zero

However increase of current flowing in anti parallel direction magnetic field due to both the wire will be added

**Question 6**

A circular …………. centre

**Answer 6**

Magnitude field at the centre of circle loop

**Question 7**

A circular …………….. coil

**Answer 7**

Magnitude field at the centre of coil having n turn

**Question 8**

An alpha ……………… path

**Answer 8**

Magnetic field due to moving charge

**Question 9**

In bohr model ……………. orbit

**Answer 9**

**Question 10**

A helium …………….. circle

**Answer 10**

As question 8 and 9

**Question 11**

A long ………….. upward

**Answer 11**

magnetic field due to straight wire

**Question 12**

the figure ………….. centre O

**Answer 12**

Magnetic field due to arc

Showing that perpendicular to plane of paper inwardly

**Question 13**

A current …………. point O

**Answer 13**

Magnetic field due to bigger arc

**Question 14**

Compute …………… wire

**Answer 14**

Magnetic field due to bigger arc

**Question 15**

An air …………….. solenoid

**Answer 15**

Magnetic field due to axis of solenoid

**Question 16**

A 80 cm …………….. centre

**Answer 16**

**Question 17**

The magnitude …………… solenoid

**Answer 17**

**Question 18**

A 0.5 m ……………….. solenoid

**Answer 18**

page-number : 340

**Question 19**

An electron …………. electron

**Answer 19**

**Question 20**

calculate …………… of 10 T

**Answer 20**

**Question 21**

An electron ……………. electron

**Answer 21**

direction will be decided by right hand thumb rule

**Question 22**

An electron …………….. electron

**Answer 22**

**Question 23**

A proton …………….. east.

**Answer 23**

= 0.625 m

(iii)

………………

**Question 24**

A 2 MeV proton …………… kg.

**Answer 24**

K E of Proton =2 Me V

**Question 25**

PQ is a …………….. electron

**Answer 25**

Magnetic field due to wire of distance of 0.6 m

**Question 26**

An electron …………….. electron

**Answer 26**

Energy acquired by electron = eV

**Question 27**

A uniform ………………. electron

**Answer 27**

frequency is independent of velocity

**Question 28**

An α Particle ………… kg

**Answer 28**

**Question 29**

An ………………. electron

**Answer 29**

**Question 30**

An …………….. path.

**Answer 30**

K E = 1/2(mv²)

**Question 31**

An electron ……………… field

**Answer 31**

**Question 32**

The velocity ……………A to B

**Answer 32**

Since electron is moving clock wise therefore magnetic field is vertically down ward

**Question 33**

A proton ……………….. path

**Answer 33**

**Question 34**

What should ……………. m

**Answer 34**

directions should be find by Fleming left hand rule

**Question 35**

A 3.0 cm …………… .wire

**Answer 35**

Force on current carrying conductor

**Question 36**

Find …………… field of 0.15 T

**Answer 36**

**Question 37**

A current ……………… wire

**Answer 37**

directions can be obtained by Fleming left hand rule

page-number : 341

**Question 38**

Two parallel ………… cylinder

**Answer 38**

directions can be obtained by Fleming left hand rule

**Question 39**

On a ……………. stationary

**Answer 39**

**Question 40**

A current ……………. conductor

**Answer 40**

**Question 41**

A 60 cm ………….. wire

**Answer 41**

for neutralising tension

Force should be upward therefore direction of current will be left to right

**Question 42**

Calculate ………….. wire A

**Answer 42**

Since when current in wires is flowing in same direction wire are attracted

**Question 43**

Two long ………….. wire A

**Answer 43**

**Question 44**

A long …………….. repulsion

**Answer 44**

**Question 45**

Two very ……………….. same

**Answer 45**

The force by two wire will be opposite both the wire will attract the middle wire.

Because current in B is more than A

**Question 46**

Calculate …………. kg

**Answer 46**

**Question 47**

A cyclotron ……………kg.

**Answer 47**

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