Number System Class 6 RS Aggarwal Exe-1C Goyal Brothers ICSE Maths Solutions We provide step by step Solutions of lesson-Number System for ICSE Class-6 **Foundation RS Aggarwal Mathematics** of Goyal Brothers Prakashan . Visit official Website **CISCE** for detail information about ICSE Board Class-6 Mathematics.

## Number System Class 6 RS Aggarwal Exe-1C Goyal Brothers ICSE Maths Solutions

Board | ICSE |

Publications | Goyal brothers Prakashan |

Subject | Maths |

Class | 6th |

Ch-1 | Number System |

Writer | RS Aggrawal |

Book Name | Foundation |

Topics | Solution of Exe-1C Word Problems |

Academic Session | 2023 – 2024 |

### Word Problems on Large Numbers (Addition / Subtraction)

Number System Class 6 RS Aggarwal Exe-1C Goyal Brothers Prakashan ICSE **Foundation Maths **Solutions

**Page- 22,23**

**Exercise- 1C**

**Que-1: A survey shows that the population of Arunachal Pradesh, Meghalaya and Tripura are 13,82,611, 29,64,007, 36,71,032 respectively. What is the total population of these three states ?**

**Solution- **Total population = Population of Arunachal Pradesh + Population of Meghalaya + Population of Tripura

Total population = 13,82,611 + 29,64,007 + 36,71,032

Total population = 13,82,611 + 29,64,007 + 36,71,032

Total population = 80,17,650

So, the total population of these three states is 80,17,650.

**Que-2: The population of Andhra Pradesh and Telangana are 6,30,20,208 and 3,52,86,757 respectively. By how much does the population of Andhra Pradesh exceed that of Telangana?**

**Solution- **Population difference = Population of Andhra Pradesh – Population of Telangana

Population difference = 6,30,20,208 – 3,52,86,757

Population difference = 2,77,33,451

So, the population of Andhra Pradesh exceeds that of Telangana by 2,77,33,451.

**Que-3: There was a stock of 85,90,865 quintals of wheat in a godown of the Food Corporation of India. Out of this stock, 17,89,564 quintals was sent to Punjab and 23,17,986 quintals was sent to Delhi. How much is the balance stock now?**

**Solution- **Balance stock = Initial stock – Quantity sent to Punjab – Quantity sent to Delhi

Balance stock = 85,90,865 – 17,89,564 – 23,17,986

Balance stock = 85,90,865 – (17,89,564 + 23,17,986)

Balance stock = 85,90,865 – 41,07,550

Balance stock = 44,83,315

So, the balance stock of wheat in the godown is 44,83,315 quintals.

**Que-4: A number exceeds 47,56,908 by 16,34,096. Find the number.**

**Solution- **Number = 47,56,908 + 16,34,096

Number = 64,91,004

So, the number is 64,91,004.

**Que-5: By how much is 15,69,748 smaller than 20,00,000?**

**Solution- **20,00,000 – 15,69,748 = 4,30,252

So, 15,69,748 is smaller than 20,00,000 by 4,30,252.

**Que-6: By how much is 1,43,56,803 larger than 86,78,215?**

**Solution- **1,43,56,803 – 86,78,215 = 56,78,588

So, 1,43,56,803 is larger than 86,78,215 by 56,78,588.

**Que-7: What number must be subtracted from 23,56,714 to get 8,69,873?**

**Solution- **23,56,714 – 8,69,873 = 14,86,841

So, 8,69,873 must be subtracted from 23,56,714 to get 14,86,841.

**Que-8: What must be added to 46,97,859 to get 63,00,000?**

**Solution- **63,00,000 – 46,97,859 = 16,02,141

So, 16,02,141 must be added to 46,97,859 to get 63,00,000.

**Que-9: The sum of two numbers is 60,10,203. If one of the numbers is 48,21,325, find the other.**

**Solution- **60,10,203 – 48,21,325 = 11,88,878

So, the other number is 11,88,878.

**Que-10: A man had Rs 1,35,00,000 with him. He gave Rs 56,32,560 to his wife, Rs 37,84,890 to his son and the balance to his daughter. How much money does the daughter get?**

**Solution- **Total amount the man had = Rs 1,35,00,000

Amount given to wife = Rs 56,32,560

Amount given to son = Rs 37,84,890

Remaining amount = Total amount – (Amount given to wife + Amount given to son)

= 1,35,00,000 – (56,32,560 + 37,84,890)

= 1,35,00,000 – 94,17,450

= Rs 40,82,550

So, the daughter gets Rs 40,82,550.

**Que-11: Swati saves Rs 6,750 per month. How much she will save in 12 years?**

**Solution- **Swati saves Rs 6,750 per month.

So, in one year, she will save: 12 months/year × Rs6,750/month = Rs81,000/year

Now, to find out how much she will save in 12 years, we multiply the annual savings by 12:

Rs81,000/year × 12 years = Rs9,72,000

Therefore, Swati will save Rs 9,72,000 in 12 years.

**Que-12: The cost of a chair is Rs 1,586. How much will such 245 chairs cost?**

**Solution- **Total cost = Cost per chair × Number of chairs

= Rs 1,586 × 245

= Rs 3,88,570

So, the total cost of 245 chairs will be Rs 3,88,570.

**Que-13: A factory produces 9,675 screws in a day. How much screws will it produce in an ordinary year?**

**Solution- **Daily production rate = 9,675 screws

Number of working days in a year = 365 days

Total screws produced in a year = 9,675 screws/day×365 days/year

= 35,31,375 screws/year

So, the factory will produce 35,31,375 screws in an ordinary year.

**Que-14: An aeroplane covers 1,685 km per hour. How much distance will it cover in 58 hours?**

**Solution- **Speed of the airplane = 1,685 km/h

Time = 58 hours

Distance = 1,685 km/h×58 hours

Distance = 97,730 km

Therefore, the airplane will cover 97,730 kilometres in 58 hours.

**Que-15: A scooter costs Rs 46,850. How much will 234 such scooters cost?**

**Solution- **Cost of one scooter = Rs 46,850 Number of scooters = 234

Total cost=Cost of one scooter×Number of scooters

Total cost=Rs 46,850×234

Total cost = Rs 1,09,62,900

Therefore, the total cost of 234 scooters would be Rs 1,09,62,900.

**Que-16: How much money was collected from 1,625 students of a school for a charity show, if each student contributed Rs 740?**

**Solution- **Number of students = 1,625

Contribution per student = Rs 740

Total money collected=Contribution per student × Number of students

Total money collected=Rs740×1,625

Total money collected = Rs12,02,500

Therefore, the total amount collected from the 1,625 students for the charity show is Rs 12,02,500.

**Que-17: If the cost of 65 refrigerators is Rs 48,46,400 what is the cost of each refrigerator?**

**Solution- **Total cost of 65 refrigerators = Rs 48,46,400

Cost of each refrigerator=Total cost Number of refrigerators

Cost of each refrigerator = 48,46,40065

Cost of each refrigerator=Rs74,560

Therefore, the cost of each refrigerator is Rs 74,560.

**Que-18: If the costs of 35 flats is Rs 1,24,94,300, find the cost of each flat.**

**Solution- **Total cost of 35 flats = Rs 1,24,94,300

Cost of each flat = Total cost Number of flats

Cost of each flat = 1,24,94,30035

Cost of each flat = Rs 3,56,980

Therefore, the cost of each flat is Rs 3,56,980.

**Que-19: The product of two numbers is 17,20,740. If one of the numbers is 1,785, find the other.**

**Solution- **Product of the two numbers = 17,20,740

One of the numbers = 1,785

Let’s denote the other number as x.

x = Product/Given number

x =17,20,740/1,785

x ≈ 964

Therefore, the other number is approximately 964.

**Que-20: A car covers 4,320 km in 45 hours. At what speed per hour does the car move?**

**Solution- **Total distance covered = 4,320 km

Total time taken = 45 hours

Speed per hour=Total distance/Total time

Speed per hour=4,320 km45/ hours

Speed per hour≈96 km/h

Therefore, the car moves at approximately 96 kilometres per hour.

**Que-21: 13kg 650g of milk is distributed equally among 21 students. How much milk will each get?**

**Solution- **First, convert the milk quantity to a consistent unit. Since 1 kg = 1000 g, we can convert 13 kg 650 g to grams:

13 kg = 13 * 1000 g = 13,000 g

Now, add the grams together:

13,000 g + 650 g = 13,650 g

Now, divide the total amount of milk by the number of students:

13,650 g ÷ 21 students ≈ 650 g per student

So, each student will receive approximately 650 grams of milk.

**Que-22: A man covers 36 km in 1 hour. Find his speed in metres/sec.**

**Solution- **1 km = 1000 meters

So, 36 km = 36 * 1000 = 36,000 meters

Now, you know the distance covered is 36,000 meters in 1 hour. To find the speed in meters per second, you need to divide the distance by the time. Since 1 hour = 3600 seconds:

Speed = Distance / Time = 36,000 meters / 3600 seconds = 10 meters per second

So, the man’s speed is 10 meters per second.

**— : end of Number System Class 6 RS Aggarwal Exe-1C Goyal Brothers ICSE foundation Maths Solutions :–**

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