Number System Class 6 RS Aggarwal Exe-1D Goyal Brothers ICSE Maths Solutions. We provide step by step Solutions of lesson-Number System for ICSE Class-6 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan . Visit official Website CISCE for detail information about ICSE Board Class-6 Mathematics.
Number System Class 6 RS Aggarwal Exe-1D Approximation Goyal Brothers ICSE Maths Solutions
Board | ICSE |
Publications | Goyal brothers Prakashan |
Subject | Maths |
Class | 6th |
Ch-1 | Number System |
Writer | RS Aggrawal |
Book Name | Foundation |
Topics | Solution of Exe-1D Approximation |
Academic Session | 2023 – 2024 |
Approximation (Number System)
Number System Class 6 RS Aggarwal Exe-1D Goyal Brothers Prakashan ICSE Foundation Maths Solutions.
Page- 26
Solution of Exe-1D Approximation
Que-1: Round each of the following numbers to the nearest ten :
(i) 54
Ans- 50
(ii) 327
Ans- 330
(iii) 2,793
Ans- 2,790
(iv) 8,049
Ans- 8,050
(v) 12,345
Ans- 12,350
Que-2: Round each of the following numbers to the nearest hundred :
(i) 925
Ans- 900
(ii) 6,854
Ans- 6,900
(iii) 41,263
Ans- 41,300
(iv) 27,861
Ans- 27,900
(v) 5,549
Ans- 5,500
Que-3: Round each of the following numbers to the nearest thousand :
(i) 7,386
Ans- 7,000
(ii) 34,276
Ans- 34,000
(iii) 23,804
Ans- 24,000
(iv) 76,540
Ans- 77,000
Que-4: Find the approximate sum to the nearest ten :
(i) (72 + 37)
Ans- 109 = 110
(ii) (264 + 348)
Ans- 612 = 610
(iii) (2,538 + 6,274)
Ans- 8,812 = 8,810
(iv) (4,782 + 2,345)
Ans- 7,127 = 7,130
Que-5: Find the approximate sum to the nearest hundred :
(i) (347 + 476)
Ans- 823 = 800
(ii) (654 + 247)
Ans- 901 = 900
(iii) (5,240 + 3,421)
Ans- 8,661 = 8,600
(iv) (9,483 + 6,572)
Ans- 16,055 = 16,100
Que-6: Find the approximate sum to the nearest thousand :
(i) (43,728 + 36,275)
Ans- 80,003 = 80,000
(ii) (37,804 + 22,475)
Ans- 60,279 = 60,000
(iii) (6,785 + 2,476)
Ans- 9,261 = 9,000
Que-7: Find the approximate difference to the nearest ten :
(i) (64-29)
Ans- 35 = 30
(ii) (186-49)
Ans- 137 = 140
(iii) (429-206)
Ans- 223 = 220
Que-8- Find the approximate difference to the nearest hundred :
(i) (769-435)
Ans- 334 = 400
(ii) (859-675)
Ans- 184 = 200
(iii) (8,359-4,317)
Ans- 4,042 = 4,100
Que-9: Find the approximate difference to the nearest thousand :
(i) (45,783-38,695)
Ans- 7,088 = 7,000
(ii) (38,005-29,375)
Ans- 8,630 = 9,000
(iii) (7,654-4,368)
Ans- 3,286 = 4000
Que-10: Estimate each of the following products by rounding off each number to the nearest ten :
(i) (49×72)
Ans- 3,528 = 3,500
(ii) (39×62)
Ans- 2,418 = 2,400
(iii) (63×57)
Ans- 3,591 = 3,600
(iv) (35×43)
Ans- 1,505 = 1,600
Que-11: Estimate each of the following products by rounding off each number to the nearest hundred :
(i) 265 x 334
Ans- 88,510 = 90,000
(ii) 457 x 872
Ans- 3,98,504 = 4,50,000
(iii) 381 x 316
Ans- 1,20,396 = 1,20 ,000
(iv) 455 x 138
Ans- 62,790 = 50,000
Que-12: Find the approximate quotient for each of the following :
(i) 86 ÷ 27
Ans- 3.18 = 3
(ii) 83 ÷ 19
Ans- 4.36 = 4
(iii) 286 ÷ 25
Ans- 11.44 = 10
(iv) 865 ÷ 38
Ans- 22.76 = 23
— : end of Number System Class 6 RS Aggarwal Exe-1D Approximation Goyal Brothers ICSE Foundation Maths Solutions :–
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