# Number System Class 6 RS Aggarwal Exe-1D Goyal Brothers ICSE Maths Solutions

Number System Class 6 RS Aggarwal Exe-1D Goyal Brothers ICSE Maths Solutions.  We provide step by step Solutions of lesson-Number System for ICSE Class-6 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan . Visit official Website CISCE for detail information about ICSE Board Class-6 Mathematics.

## Number System Class 6 RS Aggarwal Exe-1D Approximation Goyal Brothers ICSE Maths Solutions

 Board ICSE Publications Goyal brothers Prakashan Subject Maths Class 6th Ch-1 Number System Writer RS Aggrawal Book Name Foundation Topics Solution of Exe-1D Approximation Academic Session 2023 – 2024

### Approximation (Number System)

Number System Class 6 RS Aggarwal Exe-1D Goyal Brothers Prakashan ICSE Foundation Maths Solutions.

Page- 26

#### Solution of Exe-1D Approximation

(i) 925
Ans- 900

(ii) 6,854
Ans- 6,900

(iii) 41,263
Ans- 41,300

(iv) 27,861
Ans- 27,900

(v) 5,549
Ans- 5,500

(i) 7,386
Ans- 7,000

(ii) 34,276
Ans- 34,000

(iii) 23,804
Ans- 24,000

(iv) 76,540
Ans- 77,000

##### Que-4: Find the approximate sum to the nearest ten :

(i) (72 + 37)
Ans- 109 = 110

(ii) (264 + 348)
Ans- 612 = 610

(iii) (2,538 + 6,274)
Ans- 8,812 = 8,810

(iv) (4,782 + 2,345)
Ans- 7,127 = 7,130

##### Que-5: Find the approximate sum to the nearest hundred :

(i) (347 + 476)
Ans- 823 = 800

(ii) (654 + 247)
Ans- 901 = 900

(iii) (5,240 + 3,421)
Ans- 8,661 = 8,600

(iv) (9,483 + 6,572)
Ans- 16,055 = 16,100

##### Que-6: Find the approximate sum to the nearest thousand :

(i) (43,728 + 36,275)
Ans- 80,003 = 80,000

(ii) (37,804 + 22,475)
Ans- 60,279 = 60,000

(iii) (6,785 + 2,476)
Ans- 9,261 = 9,000

(i) (64-29)
Ans- 35 = 30

(ii) (186-49)
Ans- 137 = 140

(iii) (429-206)
Ans- 223 = 220

##### Que-8- Find the approximate difference to the nearest hundred :

(i) (769-435)
Ans- 334 = 400

(ii) (859-675)
Ans- 184 = 200

(iii) (8,359-4,317)
Ans- 4,042 = 4,100

##### Que-9: Find the approximate difference to the nearest thousand :

(i) (45,783-38,695)
Ans- 7,088 = 7,000

(ii) (38,005-29,375)
Ans- 8,630 = 9,000

(iii) (7,654-4,368)
Ans- 3,286 = 4000

##### Que-10: Estimate each of the following products by rounding off each number to the nearest ten :

(i) (49×72)
Ans- 3,528 = 3,500

(ii) (39×62)
Ans- 2,418 = 2,400

(iii) (63×57)
Ans- 3,591 = 3,600

(iv) (35×43)
Ans- 1,505 = 1,600

##### Que-11: Estimate each of the following products by rounding off each number to the nearest hundred :

(i) 265 x 334
Ans- 88,510 = 90,000

(ii) 457 x 872
Ans- 3,98,504 = 4,50,000

(iii) 381 x 316
Ans- 1,20,396 = 1,20 ,000

(iv) 455 x 138
Ans- 62,790 = 50,000

##### Que-12: Find the approximate quotient for each of the following :

(i) 86 ÷ 27
Ans- 3.18 = 3

(ii) 83 ÷ 19
Ans- 4.36 = 4

(iii) 286 ÷ 25
Ans- 11.44 = 10

(iv) 865 ÷ 38
Ans- 22.76 = 23

— : end of Number System Class 6 RS Aggarwal Exe-1D Approximation Goyal Brothers ICSE Foundation Maths Solutions :–

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