Number System Class 6 RS Aggarwal Exe-1D Goyal Brothers ICSE Maths Solutions. We provide step by step Solutions of lesson-Number System for ICSE Class-6 **Foundation RS Aggarwal Mathematics** of Goyal Brothers Prakashan . Visit official Website **CISCE** for detail information about ICSE Board Class-6 Mathematics.

## Number System Class 6 RS Aggarwal Exe-1D Approximation Goyal Brothers ICSE Maths Solutions

Board | ICSE |

Publications | Goyal brothers Prakashan |

Subject | Maths |

Class | 6th |

Ch-1 | Number System |

Writer | RS Aggrawal |

Book Name | Foundation |

Topics | Solution of Exe-1D Approximation |

Academic Session | 2023 – 2024 |

### Approximation (Number System)

Number System Class 6 RS Aggarwal Exe-1D Goyal Brothers Prakashan ICSE Foundation Maths Solutions.

**Page- 26**

#### Solution of Exe-1D Approximation

**Que-1: Round each of the following numbers to the nearest ten :**

**(i) 54**

Ans- 50

Ans-

**(ii) 327**

Ans- 330

Ans-

**(iii) 2,793**

Ans- 2,790

Ans-

**(iv) 8,049**

Ans- 8,050

Ans-

**(v) 12,345**

Ans- 12,350

Ans-

**Que-2: ****Round each of the following numbers to the nearest hundred :**

**(i) 925**

**Ans- **900

**(ii) 6,854**

**Ans- **6,900

**(iii) 41,263**

**Ans-** 41,300

**(iv) 27,861**

**Ans- **27,900

**(v) 5,549**

**Ans- **5,500

**Que-3: ****Round each of the following numbers to the nearest thousand :**

**(i) 7,386**

**Ans-** 7,000

**(ii) 34,276**

**Ans-** 34,000

**(iii) 23,804**

**Ans-** 24,000

**(iv) 76,540**

**Ans-** 77,000

**Que-4: Find the approximate sum to the nearest ten :**

**(i) (72 + 37)**

**Ans-** 109 = 110

**(ii) (264 + 348)**

**Ans-** 612 = 610

**(iii) (2,538 + 6,274)**

**Ans-** 8,812 = 8,810

**(iv) (4,782 + 2,345)**

**Ans-** 7,127 = 7,130

**Que-5: ****Find the approximate sum to the nearest hundred :**

**(i) (347 + 476)**

**Ans-** 823 = 800

**(ii) (654 + 247)**

**Ans-** 901 = 900

**(iii) (5,240 + 3,421)**

**Ans-** 8,661 = 8,600

**(iv) (9,483 + 6,572)**

**Ans-** 16,055 = 16,100

**Que-6: ****Find the approximate sum to the nearest thousand :**

**(i) (43,728 + 36,275)**

**Ans-** 80,003 = 80,000

**(ii) (37,804 + 22,475)**

**Ans-** 60,279 = 60,000

**(iii) (6,785 + 2,476)**

**Ans-** 9,261 = 9,000

**Que-7: ****Find the approximate difference to the nearest ten :**

**(i) (64-29)**

**Ans-** 35 = 30

**(ii) (186-49)**

**Ans-** 137 = 140

**(iii) (429-206)**

**Ans-** 223 = 220

**Que-8- ****Find the approximate difference to the nearest hundred :**

**(i) (769-435)**

**Ans-** 334 = 400

**(ii) (859-675)**

**Ans-** 184 = 200

**(iii) (8,359-4,317)**

**Ans-** 4,042 = 4,100

**Que-9: ****Find the approximate difference to the nearest thousand :**

**(i) (45,783-38,695)**

**Ans-** 7,088 = 7,000

**(ii) (38,005-29,375)**

**Ans-** 8,630 = 9,000

**(iii) (7,654-4,368)**

**Ans-** 3,286 = 4000

**Que-10: Estimate each of the following products by rounding off each number to the nearest ten :**

**(i) (49×72)**

**Ans-** 3,528 = 3,500

**(ii) (39×62)**

**Ans-** 2,418 = 2,400

**(iii) (63×57)**

**Ans-** 3,591 = 3,600

**(iv) (35×43)**

**Ans-** 1,505 = 1,600

**Que-11: ****Estimate each of the following products by rounding off each number to the nearest hundred :**

**(i) 265 x 334**

**Ans-** 88,510 = 90,000

**(ii) 457 x 872**

**Ans-** 3,98,504 = 4,50,000

**(iii) 381 x 316 **

**Ans-** 1,20,396 = 1,20 ,000

**(iv) 455 x 138 **

**Ans- **62,790 = 50,000

**Que-12: ****Find the approximate quotient for each of the following :**

**(i) 86 ÷ 27**

**Ans-** 3.18 = 3

**(ii) 83 ÷ 19**

**Ans- **4.36 = 4

**(iii) 286 ÷ 25**

**Ans- **11.44 = 10

**(iv) 865 ÷ 38**

**Ans-** 22.76 = 23

**— : end of Number System Class 6 RS Aggarwal Exe-1D Approximation Goyal Brothers ICSE Foundation Maths Solutions :–**

**Return to :- ICSE Class -7 RS Aggarwal Goyal Brothers Math Solutions**

Thanks

Please share with yours friends if you find it helpful