Percentage Class 7 RS Aggarwal Exe-9A Goyal Brothers ICSE Maths Solutions

Percentage Class 7 RS Aggarwal Exe-9A Goyal Brothers ICSE Foundation Maths Solutions. We provide step by step Solutions of lesson/ Chapter-9 Percentage for ICSE Class-7 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-7 Mathematics.

Percentage Class 7 RS Aggarwal Exe-9A Goyal Brothers ICSE Maths Solutions

Percentage Class 7 RS Aggarwal Exe-9A Goyal Brothers ICSE Maths Solutions

Board ICSE
Publications Goyal brothers Prakashan
Subject Maths
Class 7th
Chapter-9 Percentage
Writer RS Aggrawal
Book Name Foundation
Topics Solution of Exe-9A
Academic Session 2024 – 2025

Percentage Class 7

RS Aggarwal Exe-9A Goyal Brothers ICSE Foundation Maths Solutions.

Express each of the following as a per cent:

Question-1

(i) 3/5

Ans-(i)  [(3 * 100) / 5]% = 60%

(ii) 5/16

Ans-(ii)  [(5 * 100) / 16]% = 31.25%

(iii) 19/40

Ans-(iii)  [(19 * 100) / 40]% = 47.5%

(iv) 3¼

Ans-(iv)  13/2 = [(13 * 100) / 4]% = 325%

Question-2

(i) 0.45

Ans-(i)  45/100 = [(45 * 100) / 100]% = 45%

(ii) 0.03

Ans-(ii)  3/100 = [(3 * 100) / 100]% = 3%

(iii) 0.1

Ans-(iii)  [(1 * 100) / 10]% = 10%

(iv) 2.45

Ans-(iv) 2.45 = 245/100 = [(245 * 100) / 100]% = 245%

Question-3

(i) 5:8

Ans-(i) 5:8 = 5/8 = [(5 * 100) / 8]% = 62.5%

(ii) 11:18

Ans-(ii) 11:18 = [(11 * 100) / 18]% = 61.11%

(iii) 1:5

Ans-(iii) [(1 * 100) / 5]% = 20%

(iv) 5:4

Ans-(iv) [(5 * 100) / 4]% = 125%

Express each of the following as a fraction:

Question-4

(i) 24%

Ans-(i) 24/100 = 6/25

(ii) 12½%

Ans-(ii) 25/2 = 25/(2 * 100) = 1/8

(iii) 6⅔%

Ans-(iii) 20/3 = 20(3 * 100) = 1/15

(iv) 165%

Ans-(iv) 165/100 = 33/20

Question-5

(i) 0.25%

Ans-(i) 25/100 = 25 / (100 * 100) = 1/400

(ii) 0.05%

Ans-(ii) 5/100 = 5 / (100 * 100) = 1/2000

(iii) 2.25%

Ans-(iii) 225/100 = 225 / (100 * 100) = 9/400

(iv) 0.006%

Ans-(iv) 6/1000 = 6 / (1000 * 100) = 3/50000

Express each of the following as a ratio:

Question-6

(i) 12%

Ans-(i) 12/100 = 3:25

(ii) 3/5%

Ans-(ii) 3/(5*100) = 3:500

(iii) 7.5%

Ans-(iii) 75/(10 * 100) = 3:40

(iv) 0.36%

Ans-(iv) 36/100 = 36 / (100 * 100) = 9:2500

Question-7. Find:

(i) 25% of Rs 7

Ans-(i) (25/100) * 7 = Rs 1.75

(ii) 7½% of Rs 40

Ans-(ii) (15 * 40) / (2 * 100) = Rs 3

(iii) 1% of Rs 325

Ans-(iii) (1/100) * 325 = Rs 3.25

(iv) 8% of 5 kg

Ans-(iv) (8/100) * 5 = 0.4 kg = 400 g

(v) 16⅔% of 9 m

Ans-(v) [50/(3*100)] * 9 = 1.5 m

(vi) 0.6% of 5 km

Ans-(vi) [6/(10 *100)] * 5 = 0.03 km = 30 m

(vii) 6¼% of (1 hour 20 min)

Ans-(vii) 25/4% of 80 min = [25/(4*100)] *80 = 5 min

Question-8. Express:

(i) 56 p as a per cent of Rs 2.80

Ans-(i) First quantity= 56p , second quantity = Rs 2.80 = 280p
require percentage = [(56/280)*100]% = 20%

(ii) 45 cm as a per cent of 3 m

Ans-(ii )First quantity= 45cm , second quantity = 3m = 300cm
require percentage = [(45/300)*100]% = 15%

(iii) 630 g as a per cent of 3.5 kg

Ans-(iii) First quantity= 630g , second quantity = 3.5kg = 3500g
require percentage = [(630/3500)*100]% = 18%

(iv)18 hours as a per cent of 2 days

Ans-(iv)First quantity= 18hours , second quantity = 2days = 48hours
require percentage = [(18/48)*100]% = 37.5%

(v) 2.8 mm as a per cent of 2.24 cm

Ans-(v)First quantity= 2.8mm , second quantity = 2.24cm = 22.4mm
require percentage = [(2.8/22.4)*100]% = 12.5%

Question-9

(i) What per cent of 1.5 m is 60 cm?

Ans-(i) First quantity= 60cm = 0.6m , second quantity = 1.5m
require percentage = [(0.6/1.5)*100]% = 40%

(ii) What per cent of 2 kg is 125 g?

Ans-(ii) First quantity= 125g = 0.125kg , second quantity = 2kg
require percentage = [(0.125/2)*100]% = 6.25%

(iii) What per cent of Rs 6 is 40 p?

Ans-(iii) First quantity= 40p = Rs 0.4 , second quantity = Rs 6
require percentage = [(0.4/6)*100]% = 6.66%

(iv) What per cent of a day is 10 h?

Ans-(iv)First quantity= 10h = 0.4166 , second quantity = 1
require percentage = [(0.4166/1)*100]% = 41.66%

(v) What per cent of 7(1/3) m is 5½ m?

Ans-(v)First quantity= 11/2m, second quantity = 22/3 m
require percentage = [(11 * 3/ 2* 22)*100]% = 75%

— : End of Percentage Class 7 RS Aggarwal Exe-9A Goyal Brothers ICSE Foundation Maths Solutions. :–

Return to: – ICSE Class -7 RS Aggarwal Goyal Brothers Math Solutions

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