# Playing with Numbers ICSE Class-6th Concise Maths Selina Solutions Ch-9

**Playing with Numbers ICSE Class-6th** Concise Selina Mathematics Solutions Chapter-9. We provide step by step Solutions of Exercise / lesson-9 **Playing with Numbers**** ** for ICSE Class-6 Concise Selina Mathematics. Our Solutions contain all type Questions of Exe-9 A, Exe-9 B and Exe-9 C to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-6 .

**Playing with Numbers ICSE Class-6th** Concise Selina Mathematics Solutions Chapter-9

–: Select Topics :–

**Solved Questions of **Exercise- 9 A **Playing with Numbers for ICSE Class-6th Concise Maths**

(Using BODMAS)

**Question** -1.

19 – (1 + 5) – 3

**Answer-1**

19 – (1 + 5) – 3

= 19 – 6 – 3

= 19 – 9 = 10

**Question -2.**

30 x 6 + (5 – 2)

**Answer-2**

30 x 6 + (5 – 2)

= 30 x 6 – 3

= 30 x 2 = 60

**Question- 3.**

28 – (3 x 8) + 6

**Answer-3**

28 – (3 x 8) – 6

= 28 – 24 – 6

= 28 – 4 = 24

**Question -4.**

9 – [(4 – 3) + 2 x 5]
**Answer-4**

9 – [(4 – 3) + 2 x 5]
= 9 – [1 + 10]
= 9 – 11 = -2

**Question -5.**

[18 – (15 – 5) + 6]
**Answer-5**[18 -(15 -5) + 6] = [18 – 3 + 6] = [18 + 3] = 21

**Question -6.**

[(4 x 2) – (4 + 2)] + 8**Answer-6**[(4 x 2) – (4 – 2)] + 8

= 8 – 2 + 8

= 16 – 2 = 14

**Question -7.**

48 + 96 – 24 – 6 x 18

**Answer-7**

48 + 96 – 24 – 6 x 18

= 48 + 4 – 6 x 18

= 48 + 4 – 108

= 52 – 108 = -56

**Question- 8.**

22 – [3 – {8 – (4 + 6)}]
**Answer-8**

22 – [3 – {8 – (4 + 6)}] = 22 – [3 – {8 – 10}] = 22 – [3 + 2] = 22 – 5 = 17

**Question -9.**

**Answer-9**

= 34 – [29 – {30 + 66 + (24 – 2)}] = 34 – [29 – {30 + 66 + 22}] = 34 – [29 – {30 + 3}] = 34 – [29 – 33] = 34 – [-4] = 34 + 4 = 38

**Question- 10.**

60 – {16 + (4 x 6 – 8)}

**Answer-10**

60 – {16 + (4 x 6 – 8)}

= 60 – {16 + (24 – 8)}

= 60 – {16 + 16}

= 60 – 1 = 59

**Question- 11.**

**Answer-11**

25 – [12 – {5 + 18 + ( 4 – 5 – 3)}] = 25 – [12 – {5 + 18 + (4 – 2)}] = 25 – [12 – {5 + 18 + 2}] = 25 – [12 – {5 + 9}] = 25 – [12 – 14] = 25 – [-2] = 25 + 2 = 27

**Question -12.**

15 – [16 – {12 + 21 ÷ (9 – 2)}]
**Answer-12**

15 – [16 – {12 + 21 ÷ (9 – 2)}] = 15 – [16 – {12 + 21 ÷ 7}] = 15 – [16 – {12 + 3}] = 15 – [16 – 15] = 15 – 1 = 14

**Concise Maths Selina Solutions Playing with Numbers** Exercise – 9 B** ICSE Class-6th**

**Question -1.**

Fill in the blanks :

(i) On dividing 9 by 7, quotient = …………. and remainder = ……….

(ii) On dividing 18 by 6, quotient = …………. and remainder = ………….

(iii) Factor of a number is ………….. of …………..

(iv) Every number is a factor of …………….

(v) Every number is a multiple of …………..

(vi) …………. is factor of every number.

(vii) For every number, its factors are ………… and its multiples are …………..

(viii) x is a factor of y, then y is a ………… of x.

**Answer-1**

(i) On dividing 9 by 7, quotient =** 1** and remainder = **3**

(ii) On dividing 18 by 6, quotient = **3** and remainder = **0**

(iii) Factor of a number is **an exact division** of** the number**

(iv) Every number is a factor of **itself**

(v) Every number is a multiple of** itself**

(vi) **One** is factor of every number.

(vii) For every number, its factors are **finite** and its multiples are **infinite**

(viii) x is a factor of y, then y is a **multiple** of x.

**Question -2.**

Write all the factors of :

(i) 16

(ii) 21

(iii) 39

(iv) 48

(v) 64

(vi) 98

**Answer-2**

(i) 16

All factors of 16 are : 1, 2, 4, 8, 16

(ii) 21

All factors of 21 are : 1, 3, 7, 21.

(iii) 39

All factors of 39 are : 1, 3, 13, 39

(iv) 48

All factors of 48 are : 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

(v) 64

All factors of 64 are : 1, 2, 4, 8, 16, 32, 64

(vi) 98

All factors of 98 are : 1, 2, 7, 14, 49, 98

**Question -3.**

Write the first six multiples of :

(i) 4

(ii) 9

(iii) 11

(iv) 15

(v) 18

(vi) 16

**Answer-3**

**(i) 4**

Multiples of 4 =1 x 4, 2 x 4, 3 x 4, 4 x 4, 4 x 5, 4 x 6

First six multiples of 4 are : 4, 8, 12, 16, 20, 24

**(ii) 9**

Multiples of 9 = 1 x 9, 2 x 9, 3 x 9, 4 x 9, 5 x 9, 6 x 9

First six multiples of 9 are : 9, 18, 27, 36, 45, 54

**(iii) 11**

Multiples of 11 = 1 x 11, 2 x 11, 3 x 11, 4 x11, 5 x 11, 6 x 11

First six multiples of 11 are : 11, 22, 33, 44, 55, 66

**(iv) 15**

Multiples of 15 = 1 x 15, 2 x 15, 3 x 15, 4 x 15, 5 x 15, 6 x 15

First six multiples of 15 are : 15, 30, 45, 60, 75, 90

**(v) 18**

Multiples of 18 = 1 x 18, 2 x 18,3 x 18, 4 x 18, 5 x 18, 6 x 18

First six multiples of 18 are : 18, 32, 54, 72, 90, 108

**(vi) 16**

Multiples of 16 = 1 x 16, 2 x 16, 3 x 16,4 x 16, 5 x 16, 6 x 16

First six multiples of 16 are : 16, 32, 48, 64, 80, 9

**Question -4.**

The product of two numbers is 36 and their sum is 13. Find the numbers.

**Answer-4**

Since, 36 = 1 x 36, 2 x 18, 3 x 12, 6 x 6 or 4 x 9,

Sum of 1 + 36,= 37

Sum of 2 + 18,= 20

Sum of 3 + 12,= 15

Sum of 6 + 6,= 12

Sum of **4 + 9,= 13** √

Clearly, numbers are 4 and 9

**Question -5.**

The product of two numbers is 48 and their sum is 16. Find the numbers.

**Answer-5**

Since, 48 = 1 x 48, 2 x 24, 3 x 16, 6 x 8 , 4 x 12

Sum of 1 + 48,= 49

Sum of 2 + 24,= 26

Sum of 3 + 16= 19

Sum of 6 + 8 = 14

Sum of **12 + 4,= 16** √

Clearly, numbers are 4 and 12

**Question- 6.**

Write two numbers which differ by 3 and whose product is 54.

**Answer-6**

Since, 54 = 1 x 54, 2 x 27, 3 x 18, 6 x 9

Difference of 54 – 1 = 53

Difference of 27 – 2 = 25

Difference of 18 – 3 = 15

Difference of **9 – 6 = 3 ** √

Clearly, numbers are 6 and 9.

**Question- 7.**

Without making any actual division show that 7007 is divisible by 7.

**Answer-7**

7007

= 7000 + 7

= 7 x (1000+ 1)

= 7 x 1001

Clearly, 7007 is divisible by 7.

**Question -8.**

Without making any actual division, show that 2300023 is divisible by 23.

**Answer-8**

2300023 = 2300000 + 23

= 23 x (100000 + 1)

= 23 x 100001

Clearly, 2300023 is divisible by 23

**Question -9**

Without making any actual division, show that each of the following numbers is divisible by 11.

(i) 11011

(ii) 110011

(iii) 11000011

**Answer-9**

**(i) **

11011 = 11000+ 11

= 11 x (1000+ 1)

= 11 x 1001

Clearly, 11011 is divisible by 11.

**(ii)**

110011

= 110000+ 11

= 11 x (10000+ 1)

= 11 x 10001

Clearly, 110011 is divisible by 11.

**(iii)**

11000011

= 11000000+ 11

= 11 x (1000000+ 1)

= 11 x 1000001

Clearly, 110000 is divisible by 11.

**Question -10.**

Without actual division, show that each of the following numbers is divisible by 8 :

(i) 1608

(ii) 56008

(iii) 240008

**Answer-10**

**(i) **

1608

= 1600 + 8

= 8 (200 + 1)

= 8 x 201

Clearly, 1608 is divisible by 8.

**(ii)**

56008

= 56000 + 8

= 8 x (7000 + 1)

= 8 x 7001

Clearly, 56008 is divisible by 8.

**(iii) **

240008

= 240000 + 8

= 8 x (30000 + 1)

= 8 x 30001

Clearly, 240008 is divisible by 8

### Exercise – 9 C ** ICSE Class-6th** Concise Selina Maths Solution

**Question- 1.**

find which of the following numbers are divisible by 2 :

(i) 352

(ii) 523

(iii) 496

(iv) 649

**Answer-1**

**(i) 352**

The given number = 352

Digit at unit’s place = 2

It is divisible by 2

**(ii) 523**

The given number = 523

Digit at unit’s place = 3

It is not divisible by 2

**(iii) 496**

The given number = 496

Digit at unit’s place = 6

It is divisible by 2

**(iv) 649**

The given number = 649

Digit at unit’s place = 9

It is not divisible by 2

**Question- 2.**

Find which of the following number are divisible by 4 :

(i) 222

(ii) 532

(iii) 678

(iv) 9232

**Answer-2**

**(i) 222**

The given number = 222

The number formed by ten’s and unit’s digit is 22, which is not divisible by 4.

222 is not divisible by 4

**(ii) 532**

The given number = 532

The number formed by ten’s and unit’s digit is 32, which is divisible by 4.

532 is divisible by 4

**(iii) 678**

The given number = 678

The number formed by ten’s and unit’s digit is 78, which is not divisible by 4

678 is not divisible by 4

**(iv) 9232**

The given number = 9232

The number formed by ten’s and unit’s digit is 32, which is divisible by 4.

9232 is divisible by 4.

**Question- 3.**

Find the which of the following numbers are divisible by 8 :

(i) 324

(ii) 2536

(iii) 92760

(iv) 444320

**Answer-3**

**(i) 324**

The given number = 324

The number formed by hundred’s, ten’s and unit’s digit is 324, which is not divisible by 8

324 is not divisible by 8

**(ii) 2536**

The given number = 2536

The number formed by hundred’s, ten’s and unit’s digit is 536, which is divisible by 8

2536 is divisible by 8

**(iii) 92760**

The given number = 92760

The number formed by hundred’s, ten’s and unit’s digit is 760, which is divisible by 8

92760 is divisible by 8

**(iv) 444320**

The given number = 444320

The number formed by hundred’s, ten’s and unit’s digit is 320, which is divisible by 8

444320 is divisible by 8.

**Question- 4.**

Find which of the following numbers are divisible by 3 :

(i) 221

(ii) 543

(iii) 28492

(iv) 92349

**Answer-4**

**(i) 221**

Sum of digits = 2 + 2 + 1 = 5

Which is not divisible by 3

221 is not divisible by 3.

**(ii) 543**

Sum of digits = 5 + 4 + 3 = 12

Which is divisible by 3

543 is divisible by 3

**(iii) 28492**

The given number = 28492

Sum of its digits = 2 +8+4 + 9 + 2 = 25

Which is not divisible by 3

28492 is divisible by 3.

**(iv) 92349**

The given number = 92349

Sum of its digits = 0 + 2 + 3 + 4 + 9 = 27

Which is divisible by 3

92349 is divisible by 3

**Question- 5.**

Find which of the following numbers are divisible by 9 :

(i) 1332

(ii) 53247

(iii) 4968

(iv) 200314

**Answer-5**

**(i) 1332**

The given number = 1332

Sum of its digits = 1 + 3 + 3+ 2 = 9

Which is divisible by 9

1332 is divisible by 9

**(ii) 53247**

The given number = 53247

Sum of its digits = 5 + 3 + 2 + 4 + 7 = 21

Which is not divisible by 9

53247 is not divisible by 9

**(iii) 4968**

The given number = 4968

Sum of its digits = 4 + 9 + 6 + 8 = 27

Which is divisible by 9

4968 is divisible by 9

**(iv) 200314**

The given number = 200314

Sum of its digits = 2 + 0 + 0 + 3 + 1 + 4 = 10

Which is not divisible by 9

**Question -6.**

Find which of the following number are divisible by 6 :

(i) 324

(ii) 2010

(iii) 33278

(iv) 15505

**Answer-6**

if A number which is divisible by 2 and 3 or both then this given number is also divisible by 6

Therefore check if given number divisible by 2 as well as 3

**(i) 324**

The given number = 324

Sum of its digits =3 + 2 + 4 = 9

Which is divisible by 3

324 is even hence it is divisible by 2

Therefore 324 is divisible by 2 as well as 3

Hence The given number is divisible by 6

**(ii) 2010**

The given number = 2010

Sum of its digits = 2 + 0 + 1 + 0 = 3

Which is divisible by 3

2010 is even hence it is divisible by 2

Therefore 2010 is divisible by 2 as well as 3

Hence The given number is divisible by 6

**(iii) 33278**

The given number = 33278

Sum of its digits =3 + 3 + 2 + 7 + 8 = 23

Unit digit is 3 which is odd.

Hence not divisible by 2

The given number is not divisible by 6.

**(iv) 15505**

The given number = 15505

Sum of its digits = 1 + 5 + 5 + 0 + 5 = 16

which is not divisible by 3.

The given number is not divisible by 6

**Question- 7.**

Find which of the following numbers are divisible by 5 :

(i) 5080

(ii) 66666

(iii) 755

(iv) 9207

**Answer-7**

We know that** a number whose units digit is 0 or 5, then the number is divisible by 5.**

**(i) 5080**

Here, unit’s digit 0 5080 is divisible by 5.

**(ii) 66666**

Here, unit’s digit is 6.

66666 is not divisible by 5.

**(iii) 755**

Here, unit’s digit is 5.

755 is divisible by 5.

**(iv) 9207**

Here, unit’s digit is 7

9207 is not divisible by 5.

**Question- 8.**

Find which of the following numbers are divisible by 10 :

(i) 9990

(ii) 0

(iii) 847

(iv) 8976

**Answer-8**

We know that **a number is divisible by 10 if its ones digit is 0.**

**(i) 9990**

Here, unit’s digit is 0

9990 is divisible by 10.

**(ii) 0**

Here, unit’s digit is 0

0 is divisible by 10.

**(iii) 847**

Here, unit’s digit is 7

847 is not divisible by 10.

**(iv) 8976**

Here, unit’s digit is 6

8976 is not divisible by 10.

**Question- 9.**

Find which of the following numbers are divisible by 11 :

(i) 5918

(ii) 68,717

(iii) 3882

(iv) 10857

**Answer-9**

A number is **divisible by 11, if the difference of sum of its digits in odd places from the right side and the sum of its digits in even places from the right side is divisible by 11.**

**(i) 5918**

Sum of digits at odd places = 5 + 1=6 and,

sum of digits at even places = 9 + 8= 17

Their difference = 17 – 6 = 11 Which is divisible by 11

5918 is divisible by 11.

**(ii) 68, 717**

Sum of digits at odd places = 6 + 7 + 7 = 20

and, sum of digits at even places = 8 + 1 =9

Difference = 20 – 9 = 11

which is divisible by 11

68717, is divisible by 11.

**(iii) 3882**

Sum of digits at odd places = 3 + 8 = 11 and,

Sum of digits at even places = 8 + 2 = 10

Difference = 11 – 10 = 1 Which is not divisible by 11

3882 is not divisible by 11.

**(iv) 10857**

Sum of digits at odd places =1 + 8 + 7 = 16

and, Sum of digits at even places = 0 + 5 = 5

Difference = 16 – 5 = 11

which is divisible by 11

10857 is divisible by 11

**Question- 10.**

Find which of the following numbers are divisible by 15 :

(i) 960

(ii) 8295

(iii) 10243

(iv) 5013

**Answer-10**

A number is **divisible by 15, if it given number is divisible by 3 as well as 5**

**(i) 960**

960 is divisible by 3

960 is also divisible by 5.

Therefore 960 is divisible by 15

**(ii) 8295**

8295 is divisible by 3

8295 is also divisible by 5.

Therefore 8295 is divisible by 15

**(iii) 10243**

10243 is not divisible by 3

10243 is also not divisible by 5.

Therefore 8295 is not divisible by 15

**(iv) 5013**

5013 is divisible by 3

5013 is also not divisible by 5.

Therefore 5013 is not divisible by 15

**Question- 11.**

In each of the following numbers, replace M by the smallest number to make resulting number divisible by 3 :

(i) 64 M 3

(ii) 46 M 46

(iii) 27 M 53

**Answer-11**

**(i) 64 M 3**

The given number = 64 M 3

Sum of its digit = 6 + 4 + 3 = 13

The number next to 13 which is divisible by 3 is 15

Required smallest number =15 – 13 = 2

**(ii) 46 M 46**

The given number = 46 M 46

Sum of its digits = 4 + 6 + 4 + 6 = 20

The number next to 20 which is divisible by 3 is 21

Required smallest number = 21 – 20 = 1

**(iii) 27 M 53**

The given number = 27 M 53

Sum of its digits = 2 + 7 + 5 + 3 = 18

which is divisible by 3

Required smallest number = 0

**Question -12.**

In each of the following numbers replace M by the smallest number to make resulting number divisible by 9.

(i) 76 M 91

(ii) 77548 M

(iii) 627 M 9

**Answer-12**

**(i) 76 M 91**

The given number = 76 M 91

Sum of its given digits = 7 + 6 + 9 + 1 = 23

The number next to 23, which is divisible by 9 is 27

Required smallest number = 27 – 23 = 4

**(ii) 77548 M**

The given number = 77548 M

Sum of its given digits = 7 + 7 + 5 + 4 + 8 = 31

The number next to 31, which is divisible by 9 is 36.

Required smallest number = 36 – 31 = 5

**(iii) 627 M 9**

The given number = 627 M 9

Sum of its given digits = 6 + 2 + 7 + 9 = 24

The number next to 24, which is divisible by 9 is 27

Required smallest number = 27 – 24 = 3

**Question -13.**

In each of the following numbers, replace M by the smallest number to make resulting number divisible by 11.

(i) 39 M 2

(ii) 3 M 422

(iii) 70975 M

(iv) 14 M 75

**Answer-13**

**(i) 39 M 2**

The given number = 39 M 2

Sum of its digits in odd places = 3 + M

Sum of its digits in even place = 9 + 2 = 11

Their Difference = 11 – (3 + M)

11 – (3 + M) = 0 11 – 3 = M M = 8

**(ii) 3 M 422**

The given number = 3 M 422

Sum of its digits in odd places = 3 + 4 + 2 = 9

Sum of its digit in even places = M + 2

Difference of the two sums = 9 – (M + 2)

9 – (M + 2) = 0

9 – 2 = M

M = 7

**(iii) 70975 M**

The given number = 70975 M

Sum of its digits in odd places = 0 + 7 + M = 7 + M

Sum of its digit in even places = 5 + 9 + 7 = 21

Difference of the two sums = 21 – (7 + M)

=> 21 – (7 + M) = 0

=> 21 = 7 + M

=> M = 14

Since, M cannot be two digit number M = 14 – 11 = 3

**(iv) 14 M 75**

The given number = 14 M 75

Sum of its digit in odd places = 1 + M + 5 = M + 6

Sum of its digit in even places = 4 + 7 = 11

11 – (M + 16) = 0

11 = M + 6

11 – 6 = M

M = 5

**Question- 14.**

State, true or false :

(i) If a number is divisible by 4. It is divisible by 8.

(ii) If a number is a factor of 16 and 24, it is a factor of 48.

(iii) If a number is divisible by 18, it is divisible by 3 and 6.

(iv) If a divide b and c completely, then a divides (i) a + b (ii) a – b also completely.

**Answer-14**

(i) False

(ii) True

(iii) True

(iv) True

— End of **Playing with Numbers** Solutions :–

Return to **– **Concise Selina Maths Solutions for ICSE Class -6

Thanks