Ratio and Proportional MCQ Type Questions ICSE Class-10 Maths for Sem-1. These MCQ / Objective Type Questions is based on latest reduced syllabus according 2021-22 session on bifurcated pattern. Main motto of MCQ Type Question is cracking the next upcoming exam of council. Visit official website CISCE for detail information about ICSE Board Class-10 Maths.
ICSE Class-10 Maths Ratio and Proportional MCQ Type Questions for Sem-1
| Board | ICSE |
| Class | 10th ( x ) |
| Subject | Maths |
| Chapter | Ratio and Proportional |
| Syllabus | on bifurcated syllabus (after reduction) |
| bifurcated pattern |
Semester-1 |
| Session | 2021-22 |
| Topic | MCQ / Objective Type Question |
Maths Ratio and Proportional MCQ Type Questions of ICSE Class-10 for Sem-1
Question-1 Given that (a3 + 3ab2) / (b3 + 3a2b) = 63 / 62 . Using componendo and dividendo , The value of a: b will be
(i) a : b = 2 : 3 ; (ii) a : b = 63 : 62 (iii) a : b = 62 : 63 (iv) a : b = 3 : 2
Ans:- (iv) a : b = 3 : 2
Hint
Given that (a3 + 3ab2)/(b3 + 3a2b) = 63/62
By componendo and dividendo,
(a3 + 3ab2 + b3 + 3a2b)/(a3 + 3ab2 – b3 – 3a2b) = (63 + 62)/(63 – 62) = 125/1
⇒ {(a + b)3}/{(a – b)3} = (5/1)3
⇒ (a + b)/(a – b) = 5
⇒ a + b = 5a – 5b
⇒ 5a – a – 5b – b = 0
⇒ 4a – 6b = 0
⇒ 4a = 6b
⇒ a/b = 6/4
⇒ a/b = 3/2
a : b = 3 : 2
Question- 2 If 3A = 4B = 6C, find A: B: C
(i) 5: 3: 2 ; (ii) 4: 1: 2 (iii) 4: 5: 2 (iv) 4: 3: 2
Ans:- (iv) 4: 3: 2
Hint
3A = 4B
A/B = 4/3
A: B = 4: 3
Similarly 4B = 6C
B/C = 6/4 = 3/2
B: C = 3: 2
So we get
A: B: C = 4: 3: 2
Question-3 If (x – 9) : (3x + 6) is the duplicate ratio of 4 : 9, the value of x
(i) 33 ; (ii) 25 (iii) 48 (iv) 96
Ans:- (ii) 25
hint
(x – 9)/ (3x + 6) = (4/9)2
(x – 9)/ (3x + 6) = 16/81
81x – 729 = 48x + 96
81x – 48x = 96 + 729
33x = 825
x = 825/33
= 25
Question-4 A certain sum was divided among A, B and C in the ratio 7 : 5 : 4. If B got Rs 500 more than C, find the total sum divided.
(i) 8000 ; (ii) 6000 (iii) 7000 (iv) 9000
Ans:- (i) 8000
hint
Ratio between A, B and C = 7 : 5 : 4
Let A’s share = 7x
B’s share = 5x
and C’s share = 4x
Total sum = 7x + 5x + 4x = 16x
5x – 4x = 500
x = 500
So the total sum = 16x = 16 × 500 = Rs 8000
Question- 5 the mean proportion of:(a – b) and (a3 – a2b), a ˃ b
(i) a (b – a)
(ii) a (a – b)
(iii) -a (a – b)
(iv) a (-a – b)
Ans (ii) a (a – b)
Hint
let x as the mean proportion of (a – b) and (a3 – a2b), a ˃ b
(a – b): x :: (a3 – a2b)
x2 = (a – b) (a3 – a2b)
x2 = (a – b) a2 (a – b)
x2 = a2 (a – b)2
x = a (a – b)
Hence, mean proportion is a (a – b).
Question -6 If a, 12, 16 and b are in continued proportion value of a and b will be
(i) a = 9 and b = 3
(ii) a = 64 and b = 3
(iii) a =64/3 and b = 9
(iv) a = 9 and b = 64/3
Answer- (iv) a = 9 and b = 64/3
hint
∵ a, 12, 16, b are in continued proportion, then
a/12 = 12/16 = 16/b
a/12 = 12/16
16a = 144 (By cross multiplication)
a = 144/16 = 9
and
12/16 = 16/b
12b = 16 × 16 = 256 (By cross multiplication)
b = 256/12 = 64/3 = 21 1/3
Hence, a = 9 and b = 64/3
Question-7 The following numbers, K + 3, K + 2, 3K – 7 and 2K – 3 are in proportion. value of k
(i) K = 5 or K = – 1
(ii) K = -5 or K = 1
(iii) K = 5 or K = 1
(iv) K = -5 or K = – 1
Answer-(i) K = 5 or K = – 1
Hint
(K + 3) / (K + 2) = (3K – 7) / (2K – 3 )
⇒ (K + 3) (2K – 3) = (K + 2) (3K – 7).
⇒ 2K2 – 3K + 6K – 9 = 3K2 – 7K + 6K – 14
⇒ K2 – 4K – 5 = 0
⇒ (K – 5) (K + 1) = 0
⇒ K = 5 or K = – 1
Question- 8 If x + 5 is the mean proportion between x + 2 and x + 9, find the value of x.
(i) 7 (ii) 8 (iii) 9 (iv) 10
Answer-(i) 7
Hint
∵ x + 5 is the mean proportion between x + 2 and x + 9, then
(x + 5)² = (x + 2) (x + 9)
⇒ x² + 10x + 25 = x² + 11x + 18,
and ⇒ x² + 10x – x² – 11x = 18 – 25
so ⇒ – x = – 7
∵ x = 7 Ans.
Question -9 The two numbers such that the mean proportional between them is 28 and the third proportional to them is 224. The two numbers are
(i) 28 x 224 /2 and (28 /224)/2
(ii) 28/2 and 224/2
(iii) 784 and 224
(iv) 14 and 56
Answer-(iv) 14 and 56
Hint
Let the two numbers are a and b.
∵ 28 is the mean proportional
∵ a : 28 : : 28 : b
ab = 282 = 784
Here a = 784/b …… (1)
224 is the third proportional
a: b :: b: 224
b2 = 224a ….. (2)
substituting the value of a in equation (2)
b2 = 224 × 784/b
b3 = 224 × 784
b3 = 175616 = 563
b = 56
substituting the value of b in equation (1)
a = 784/56 = 14
Hence 14 and 56 are the two numbers
Question -10 Rs. 8400 is divided among A, B, C and D in such a way that the shares of A and B, B and C, and C and D are in the ratios of 2:3, 4:5 and 6:7 respectively. The share of A is
(i) Rs. 1280 ; (ii) Rs. 1920 (iii) Rs. 2400 (iv) Rs. 2800
Ans- (i) Rs. 1280
Question -11 The ratio of the present age of father to that of son is 7:2. After 10 years their ages will be in the ratio of 9:4. The present ages of the father is
Question -14. A ratio equivalent to 3 : 7 is:
(i) 3 : 9; (ii) 6 : 10; (iii) 9 : 21; (iv) 18 : 49
Ans:- (iii) 9 : 21;
Question -15. The ratio 35 : 84 in simplest form is:
(i) 5 : 7; (ii) 7 : 12; (iii) 5 : 12; (iv) none of these
Ans:- (iii) 5 : 12;
Question -16 In a class there are 20 boys and 15 girls. The ratio of boys to girls is:
(i) 4 : 3; (ii) 3 : 4; (iii) 4 : 5; (iv) none of these
Ans:-(i) 4 : 3;
Question -17 Two numbers are in the ratio 7 : 9. If the sum of the numbers is 112, then the larger number is:
(i) 49; (ii) 72; (iii) 63; (iv) 42
Ans:-(iii) 63;
Question -18 The ratio of 1.5 m to 10 cm is:
(i) 1 : 15; (ii) 15 : 10; (iii) 10 : 15; (iv) 15 : 1
Ans:-(iv) 15 : 1
Question -19 The ratio of 1 hour to 300 seconds is:
(i) 1 : 12; (ii) 12 : 1; (iii) 1 : 5; (iv) 5 : 1
Ans:-(ii) 12 : 1;
Question -20. In 4 : 7 : : 16 : 28, 7 and 16 are called
(i) extreme terms; (ii) middle terms; (iii) b middle and c extreme term; (iv) none of these
Ans:-(ii) middle terms;
Question -21The first, second and fourth terms of a proportion are 16, 24 and 54 respectively. Then the third term is:
(i) 36; (ii) 28; (iii) 48; (iv) 32
Ans:-(i) 36;
Question -22 If 12, 21, 72, 126 are in proportion, then:
(i) 12 × 21 = 72 × 126; (ii) 12 × 72 = 21 × 126; (iii) 12 × 126 = 21 × 72; (iv) none of these
Ans:-(iii) 12 × 126 = 21 × 72;
Question -23. If x, y and z are in proportion, then:
(i) x : y : : z : x; (ii) x : y : : y : z; (iii) x : y : : z : y; (iv) x : z : : y : z
Ans:- (ii) x : y : : y : z
Question -24 7 : 12 is equivalent to:
(i) 28 : 40; (ii) 42 : 71; (iii) 72 : 42; (iv) 42 : 72
Ans:- (iv) 42 : 72
Question -25 The length and breadth of a rectangle are in the ratio 3 : 1. If the breadth is 7 cm, then the length of the rectangle is:
(i) 14 cm; (ii) 16 cm; (iii) 18 cm; (iv) 21 cm
Ans:- (iv) 21 cm
Question -26 The value of m, if 3, 18, m, 42 are in proportion is:
(i) 6; (ii) 54; (iii) 7; (iv) none of these
Ans:- (ii) 54;
Question -27 Length and width of a field are in the ratio 5 : 3. If the width of the field is 42 m then its length is:
(i) 100 m; (ii) 80 m; (iii) 50 m; (iv) 70 m
Ans:- (iv) 70 m
More Questions on Ratio and Proportional MCQ of ML Aggarwal
Question -1
The ratio of 4 litres to 900 mL is
(a) 4 : 9
(b) 40 : 9
(c) 9 : 40
(d) 20 : 9
Answer-
4l : 900 mL,
= 4000 mL : 900 mL,
= 4000 : 900,
= 40 : 9
Question -2
When the number 210 is increased in the ratio 5 : 7, the the new number is
(a) 150
(b) 180
(c) 294
(d) 420
Answer –
210 is increased in the ratio 5 : 7, then
New increased number will be = 210 × 7/5
= 294
Question-3
Two numbers are in the ratio 7 : 9. If the sum of the numbers is 288, then the smaller number is
(a) 126
(b) 162
(c) 112
(d) 144
Answer –
Ratio in two number = 7 : 9
Sum of numbers = 288
Sum of ratios = 7 + 9 = 16
Smaller number = (288 × 7)/16
= 126
Question -4
The ratio of number of edges of a cube to the number of its faces is
(a) 2 : 1
(b) 1 : 2
(c) 3 : 8
(d) 8 : 3
Answer –
No. of edges of the cube = 12
No. of faces = 6
Ratio in edges a cube to the number of faces = 12 : 6
= 2 : 1
Question-5
If x, 12, 8 and 32 are in proportion, then the value of x is
(a) 6
(b) 4
(c) 3
(d) 2
Answer-
x, 12, 8, 32 are in proportion, then
x × 32 = 12 × 8 (∵ ad = bc)
⇒ x = (12 × 8)/32 = 3
x = 3
Question-6
The fourth proportional to 3, 4, 5 is
(a) 6
(b) 20/3
(c) 15/4
(d) 12/5
Answer-
The fourth proportion to 3, 4, 5 will be
= (4 × 5)/3
= 20/3
Question-7
The third proportional to and 5 is
(a) 4
(b) 8 1⁄2
(c) 3
(d) none of these
Answer-
The third proportional to 6.1/4 and 5 is
⇒ 6. 1/4 : 5 : : 5 : x
⇒ 25/4 : 5 : : 5 : x
⇒ x = {(5 × 5)/25} × 4,
⇒ 4
Question-8
The mean proportional between 1⁄2 and 128 is
(a) 64
(b) 32
(c) 16
(d) 8
Answer-
The mean proportional between 1⁄2 and 128 is
= √(128/2)= √64 = 8 (d)
–: End of Ratio and Proportional MCQ Type Questions ICSE Class-10 Maths :-
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