Rational Numbers Class- 7th RS Aggarwal Exe-4 E Goyal Brothers ICSE Math Solution . We provide step by step Solutions of lesson-4 Rational Numbers for ICSE Class-7 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan . Our Solutions contain all type Questions of Exe-4 E to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-7 Mathematics. in this post we would learn about Reciprocal or Multiplicative Inverse of a Rational number such as What is the multiplicative inverse of rational numbers? Is the multiplicative inverse of a rational number.
Rational Numbers Class- 7th RS Aggarwal Exe-4 E Goyal Brothers ICSE Maths Solution
| Board | ICSE |
| Publications | Goyal brothers Prakashan |
| Subject | Maths |
| Class | 7th |
| Chapter-4 | Rational Numbers |
| Writer | RS Aggrawal |
| Book Name | Foundation |
| Topics | Solution of Exe-4 E |
| Academic Session | 2023 – 2024 |
Exercise – 4 E
Rational Numbers Class- 7th RS Aggarwal Goyal Brothers ICSE Maths Solution
1. Multiply :
(i) (2/3) by (4/5)
Solution: (2/3) by (4/5)
(2/3) × (4/5)
= (8/15)
(ii) (7/6) by (9/2)
Solution: (7/6) by (9/2)
(7/6) × (9/2)
= (63/12)
(iii) (5/6) by 30
Solution: (5/6) by 30
(5/6) × 30
= 25
(iv) (-3/4) by (8/7)
Solution: (-3/4) by (8/7)
(-3/4) × (8/7)
= (-6/7)
(v) (-16/9) by (12/-5)
Solution: (-16/9) by (12/-5)
(-16/9) × (12/-5)
= (-64/-15)
= (64/15)
(vi) (35/-8) by (12/-5)
Solution: (35/-8) by (12/-5)
(35/-8) × (12/-5)
= (21/2)
(vii) (-3/10) by (-40/9)
Solution: (-3/10) by (-40/9)
(-3/10) × (-40/9)
= (12/9)
= (4/3)
(viii) (-32/5) by (15/-16)
Solution: (-32/5) by (15/-16)
(-32/5) × (15/-16)
= (-6/-1)
= 6
(ix) (-8/15) by (-25/32)
Solution: (-8/15) by (-25/32)
(-8/15) × (-25/32)
= (5/12)
2. Simplify :
(i) (7/15) × (5/6)
Solution: (7/15) × (5/6)
= (7/18)
(ii) (-5/24) × (6/25)
Solution: (-5/24) × (6/25)
= (-1/20)
(iii) (7/-18) × (-9/14)
Solution: (7/-18) × (-9/14)
= (-1/-4)
= (1/4)
(iv) (-9/5) × (-10/3)
Solution: (-9/5) × (-10/3)
= (-3 × (-2))
= 6
(v) (-28) × (-8/7)
Solution: (-28) × (-8/7)
= (-4 × (-8)
= 32
(vi) (8/-21) × (-14/3)
Solution: (8/-21) × (-14/3)
= (-16/-9)
= (16/9)
3. Simplify :
(i) (5/12) × (-36)
Solution: (5/12) × (-36)
= -15
(ii) (-17/18) × 12
Solution: (-17/18) × 12
= (-34/3)
(iii) (-5/6) × (6/5)
Solution: (-5/6) × (6/5)
= -1
(iv) (-14) × (9/28)
Solution: (-14) × (9/28)
= (-9/2)
(v) -4(4/5) × (-7(1/2))
Solution: -4(4/5) × (-7(1/2))
= (-24/5) × (-15/2)
= (-12 × (-3))
= 36
(vi) (-8/15) × (-25/32)
Solution: (-8/15) × (-25/32)
= (5/12)
4. Simplify :
(i) [(2/5) × (5/8)] + [(-3/7) × (14/-15)]
Solution: [(2/5) × (5/8)] + [(-3/7) × (14/-15)]
= (1/4) + (-2/-5)
= (5 + 8)/20
= (13/20)
(ii) [(-14/3) × (-12/7)] + [(-6/25) × (15/8)]
Solution: [(-14/3) × (-12/7)] + [(-6/25) × (15/8)]
= (8/1) + (-9/20)
= (8/1) – (9/20)
= (160 – 9)/20
= (151/20)
(iii) [(6/25) × (-15/8)] – [(13/100) × (-25/26)]
Solution: [(6/25) × (-15/8)] – [(13/100) × (-25/26)]
= (-9/20) – (-1/8)
= (-9/20) + (1/8)
= (-18 + 5)/40
= (-13/40)
(iv) ((-14/5) × (-10/7)) – ((-8/9) × (3/16))
Solution: [(-14/5) × (-10/7)] – [(-8/9) × (3/16)]
= (4/1) – (-1/6)
= (4/1) + (1/6)
= (24 + 1)/6
= (25/6)
5. Find the cost of 3(1/3) kg of rice at ₹40(1/2) per kg.
Solution: Cost of 1 kg of rice = ₹40(1/2) = (81/2)
Cost of 3(1/3) kg of rice = (10/3)
So, (81/2) × (10/3)
= ₹135
Cost of 3(1/3) kg of rice is ₹135.
6. Find the distance covered by a car in 2(2/5) hours at a speed of 46(2/3) km per hour.
[Hint. Required distance = 46(2/3) × 2(2/5) km]
Solution: Speed of 1 hour = 46(2/3) = (140/3)
Distance covered by the car in 2(2/5) hour = (12/5)
So, (12/5) × (140/3)
= 112 km
Distance covered by the car in (12/5) hour =112km.
7. Write the multiplicative inverse of :
The reciprocal or multiplicative inverse of a non zero rational number (a/b) is (b/a).
(i) (5/6)
Solution: (5/6)
= (6/5)
(ii) (-3/7)
Solution: (-3/7)
= (-7/3)
(iii) -8
Solution: -8
= (-1/8)
(iv) (-11/3)
Solution: (-11/3)
= (-3/11)
(v) (-1/8)
Solution: (-1/8)
= -8
— : end of Rational Numbers Class- 7th RS Aggarwal Exe-4 E Goyal Brothers ICSE Maths Solution:–
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