Simple Interest Class 7 RS Aggarwal Exe-11A Goyal Brothers ICSE Maths Solutions. We provide step by step Solutions of lesson/ Chapter-11 Simple Interest for ICSE Class-7 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-7 Mathematics.
Simple Interest Class 7 RS Aggarwal Exe-11A Goyal Brothers ICSE Maths Solutions
| Board | ICSE |
| Publications | Goyal brothers Prakashan |
| Subject | Maths |
| Class | 7th |
| Chapter-11 | Simple Interest |
| Writer | RS Aggrawal |
| Book Name | Foundation |
| Topics | Solution of Exe-11A |
| Academic Session | 2024 – 2025 |
Simple Interest Imp Questions with Solutions
Class 7 RS Aggarwal Exe-11A Goyal Brothers ICSE Foundation Maths Solutions.
Question-1: Find the simple interest and amount on each of the following:
(i) ₹8400 for 4 years at 8% per annum.
Sol – (i) Principal(P) = Rs. 8400, Time(T) = 4 years, Rate(R) = 8%
Simple Interest (SI) = PRT/100
SI = (8400×4×8) / 100
SI = 84×4×8
Hence SI = ₹ 2688.
Amount = P + SI = 8400 + 2688 = ₹11088.
Sol – (ii) ₹50000 for 3 years 12(1/2)% per annum.
Ans-(ii) Principal (P) = ₹50,000 Rate (R) = 12½ % = 25/2 % Time (T) = 3 years
Simple Interest (SI) = PRT/100
SI = 50,000 × 25/2 × 3/100
SI = ₹18750.
Amount = P + SI = ₹50,000 + ₹18,750 = ₹68,750.
Sol – (iii) ₹9275 for 2 years at 7(1/2)% per annum.
Ans-(iii) Principal(P) = ₹ 9275 Time (T) = 2 years Rate (R) = 7 1/2 %
Simple Interest (SI) = PRT/100
SI = (9275(2) (7 1/2))/100
= (18550) (15/2)/100
= (9275)(15)/100
Hence = ₹1391.25
Amount = P + SI = 9275 + 1391.25 = ₹10666.25
Question-2: In what time will ₹ 7500 amount to ₹8625, if simple interest is reckoned at 7(1/2)% per annum?
Solution: Amount= 8625, Principle= 7500, Rate = 15/2%
SI = A-P = 1125
Simple Interest (SI) = PRT/100
1125=7500 * t * (15/200)
5 * 225 =5 * 15 * 15 * (t/2)
t = 2 years.
Question-3: In what time will ₹ 3600 amount to₹ 4320 at 4% per annum simple interest?
Solution : The amount is given as Rs4320 and the principle is given as Rs3600 with the rate of 4%. Then, the simple interest will be,
S.I.= Amount−Principle =4320−3600 =720
Now, SI = (P*R*T)/100
720=(3600*4*T)/100
T=(720*100) /(3600*4)
T=5 years.
Question-4: At what rate per cent per annum will ₹6300 yield an interest of ₹2100 in 4 years?
Solution : The principle is given as Rs 6300 and the simple interest is given as Rs 2100 with time as 4 years.
S.I.= (P*R*T) /100
2100=(6300*R*4 ) /100
R=(2100*100) / (6300*4)
R = (25/3)% = 8(1/3)%
Question-5: At what rate per cent per annum simple interest will ₹66000 amount to ₹72720 in 2 years?
Solution: Principal,P = Rs. 66,000, Time(T) = 2 years
S.I. = 72,720 – 66,000 = Rs. 6,720
Rate(R) = ?
S.I. = (P * R * T ) /100
R = (6720*100) / (66,000 * 2)
Rate = 5.09% = 5(1/11)% per annum.
Question-6: The simple interest on a sum of money for 5 years is 3/5 of the sum. Find the rate per cent per annum.
Solution: Let Rs x be the sum. Then according to the question, the simple interest will be 35x.
S.I.=(P*R*T)/100
(3/5)x=(x* R *5) /100
R=(3x * 100) / (5*x*5)
R=12% p.a.
Question-7: The simple interest on a certain sum for 3 years at 10% per annum is ₹829.50. Find the sum.
Solution : The simple interest is given as Rs 829.50 with the rate of 10% per annum for 3 years
S.I.=(P*R*T) /100
829.50=(P*10 *3) /100
P=(829.50*100)/(10*3)
P=Rs 2765.
Question-8: What sum will yield an interest of ₹7840 in 2 years at 6(1/4) % per annum?
Solution: The simple interest is given as Rs7840 in 2 years at the rate of 254%.
S.I.=(P*R*T)/100
7840=(P * 254 * 2)/100
P=(7840*4*100)/(25*2)
P=Rs 62720.
Question-9: At what rate per cent per annum simple interest will a sum treble itself in 16 years?
Solution: Let Rs x be the sum, then according to question, the amount will be Rs3x. Then simple interest will be,
S.I.=Amount−Principle = 3x−x =2x
The time is given as 16 years.
S.I.=(P×R×T)/100
2x=(x × R × 16)/100
R=2x ×100x × 16
R=12.5% = 12(1/2)%.
Question-10: A sum when reckoned at 6% per annum simple interest amounts to ₹4130 in 3 years. Find the sum.
Solution : The amount is given as Rs4130 at the rate of 6% per annum in 3 years.
we known that,
S.I.=Amount−Principle
S.I.=4130−P ——eq(1)
And,
S.I.=(P×R×T)/100
S.I.=(P×6×3)/100 ——eq(2)
From equation (1) and (2),
⇒ 4130−P=(P×6×3)/100
⇒ 4130=(18P/100)+P
So 4130=(18P+100P)/100
⇒ 413000=118P
P=413000/118
P=Rs 3500.
Question-11: A sum of money put at 11% per annum simple interest amounts to ₹ 10370 in 2 years. What will it amount to in 3 years at the same rate?
Solution: Let the principal be x
Amount = Rs 10370
Simple interest = Amount – Principal
Simple Interest= 10370-x
Rate of interest = 11%
Time = 2 years
Simple interest = (PRT)/100
10370-x = (x* 11 * 2 )/100
x =8500
Now we are supposed to find what will it amount to in 3 years at the same rate
Principal = Rs.8500
Time = 3 years
Rate of interest = 11%
SI =(PRT)/100
SI = (8500 * 11 *3) /100,
Hence SI = 2805
As Amount = Principal +Interest
=8500 +2805
Amount =11305.
Question-12: A sum of money put at 9% per annum simple interest amounts to ₹10160 in 3 years. What will it amount to in 2 years at 8% per annum?
Solution: Find the interest percentage earned in 3 years:
1 year = 9%
3 years = 9 x 3 = 27%
Find the principal amount:
Interest = 27%
Percentage of money with interest = 100 + 27 = 127%
Sum of money with interest = Rs 10160
127% = rs 10160
1% = 10160 ÷ 127 = Rs 80
100 = Rs 80 x 100 = Rs 8000
Find the interest for 2 years at 8% per annum:
1 year = 8% x 8000 = 0.08 x 8000 = Rs 640
2 years = 640 x 2 = Rs 1280
Find the amount after 2 years:
Total amount = Rs 1280 + Rs8000 = Rs 9280.
— : End of Simple Interest Class 7 RS Aggarwal Exe-11A Goyal Brothers ICSE Foundation Maths Solutions :–
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