Transpiration Class 10 Concise Structured/Applications/Skill Type Ans ICSE Biology Selina Solutions Ch-5. In this article you will get the solutions of Structured/Applications/Skill Type Questions as council latest syllabus. Visit official website CISCE for detail information about ICSE Board Class-10 Biology.
Transpiration Class 10 Concise Structured/Applications/Skill Type Ans ICSE Biology Selina Solutions Ch-5
| Board | ICSE |
| Subject | Biology |
| Class | 10 |
| Book | Selina Concise |
| Chapter-5 | Transpiration |
| Topics | Solutions of Structured/Applications/Skill Type Questions |
Solutions of Structured/Applications/Skill Type Questions on Transpiration
( Class 10 Concise ICSE Biology Selina Solutions Ch-5)
Page 66-67
Que-1: The give figure represent an experiment :
(a) Leaf A was coated with grease on both the surfaces.
(b) Leaf B was coated with grease on the lower surfaces.
(c) Leaf C was coated with grease on the upper surfaces.
(d) Leaf D was left without any application of grese.
All the four leaves A, B, C, D were left in a room for 24 hours.
(i Which leaf dries first ? Give reason
(ii) Which leaf dries last ? Give reason.)
Ans:
(i) Leaf D: i.e. the leaf with no greasing on either surfaces would dry first because it would lose water from both surfaces i.e. it would lose maximum quantity of water.
(ii) Leaf A: which was coated with grease on both the surfaces would dry last because greasing prevents evaporation of water and transpiration occurs through stomata which are present more on the lower surface of the leaf.
Que-2: Given below is the diagram of an apparatus used to study a particular phenomenon in plants:
(a) Name the apparatus.
(b) What is it used for?
(c) What is the role played by the air-bubble in this experiment?
(d) What is the use of the reservoir?
(e) What happens to the movement of the air-bubble if the apparatus is kept:
(i) In the dark
(ii) In sunlight
(iii) In front of a fan
Give a reason in each case.
Ans:
(a) Ganong’s potometer
(b) Ganong’s potometer is used to measure the water intake of a plant which is almost equal to the water lost through transpiration.
(c) The movement of the air bubble and its position in the capillary tube indicates the volume of water lost through transpiration in a given time.
(d) The water in the reservoir can be released into the capillary tube by opening the stop cock. This allows the air bubble to restore back to its original position.
(e)
(i) If the apparatus is kept in the dark, there will be no transpiration as the stomata would be closed. As a result, there would be no movement of the air bubble and it would remain stable.
(ii) If the apparatus is kept in bright sunlight, the rate of transpiration will be more. As a result, the movement of the air bubble would be larger since there would be more loss of water due to transpiration.
(iii) If the apparatus is kept in front of a fan, the rate of transpiration will be more. As a result, the movement of the air bubble would be larger since there would be more loss of water due to transpiration as the velocity of wind/air increases.
Que-3: Given ahead is the diagram of an experimental set up to study the process of transpiration in plants. Study the same and then answer the questions that follow:
(a) Name the colour of dry cobalt chloride paper.
(b) Is the experimental leaf a monocot or a dicot? Give a reason to support your answer.
(c) Why are glass slides placed over the dry cobalt chloride papers?
(d) After about half an hour what change, if any, would you expect to find in the cobalt chloride paper placed on the dorsal and ventral sides of the leaf? Give a reason to support your answer.
Ans:
(a) Blue.
(b) The experimental leaf is a dicot leaf as it shows reticulate venation and there are more number of stomatal openings on the undersurface of a dicot leaf. Hence, transpiration is more and can be easily observed.
(c) Glass slides are placed over the dry cobalt chloride papers so as to retain the strips in their position.
(d) The cobalt chloride paper on the dorsal side will turn less pink or turns pink in a much longer time; while the one on the ventral side will turn more pink. This occurs because the ventral surface has more number of stomata as compared to the dorsal surface. As a result, the rate of transpiration is more on the ventral side than on the dorsal side of a dicot leaf.
Que-4: An outline sketch of a tree is shown in a diagram below. Study the same and answer the questions that follow:
(a) Name and define the phenomenon labelled A in the diagram.
(b) Write the significance of the process mentioned in A for the plants.
(c) What do the direction of arrows in B and C indicate? Name the phenomenon.
(d) Draw a neat and labelled diagram of an opened stomata.
Ans:
(a) A is transpiration. Transpiration is the evaporative loss of water from the aerial parts (leaves and stem) of the plants.
(b) Significance of transpiration for the plant :
- Cooling effect
- Suction force
- Distribution of water and minerals
(c) Arrow B indicates water passing up the trunk and the phenomenon is lenticular transpiration/ascent of sap. Arrow C indicates water absorbed by roots from the soil and the phenomenon is called endosmosis.
(d) opened stomata :
Que-5: The figure given below represents an experimental setup with a weighing machine to demonstrate a particular process in plants. The experimental setup was placed in bright sunlight. Study the diagram and answer the following questions.
(a) Name the process intended for study.
(b) Define the above mentioned process.
(c) When the weight of the test tubes A and B is taken before and after the experiment, what change is observed? Justify.
(d) What is the purpose of keeping the test tube B in the experimental setup.
(e) What is the purpose of putting oil in the test tube.
Ans:
(a) Transpiration
(b) Transpiration is a process by which water is lost in the form of water vapour from aerial parts of the plant.
(c) Weight of test tube A before the experiment was more than its weight after the experiment. This is because water from test tube A has evaporated due to transpiration.
Weight of test tube B remains the same before and after the experiment, because no loss of water occurs in test tube B.
(d) Test tube B is used here as a control. This makes the observation of the change in test tube A easy.
(e) Oil is stops water evaporation from surface.
Que-6: An apparatus as shown below was set up to investigate a physiological process in plants. The setup was kept in sunlight for two hours. Droplets of water were then seen inside the bell jar. Answer the questions that follow:
(a) Name the process being studied.
(b) Explain the process named above in (a).
(c) Why was the pot covered with a plastic sheet?
(d) Suggest a suitable control for this experiment.
(e) Mention two ways in which this process is beneficial to plants.
(f) List three adaptations in plants to reduce the above mentioned process.
Ans:
(a) Transpiration
(b) Transpiration is a process during which water is lost in the form of water vapour through aerial parts of the plant.
(c) The pot is covered with a plastic sheet to prevent evaporation of water from the soil.
(d) A control for this experiment will be an empty polythene bag with its mouth tied.
(e) Transpiration is beneficial to plants in the following ways:
- It creates a suction force in the stem which enables the roots to absorb water and minerals.
- It helps in cooling the plant in hot weather.
(f) Adaptations in plants to reduce transpiration are
- Leaves may be modified into spines as in cactus or into needles as in pines.
- The number of stomata is reduced and they may be sunken in pits.
- Leaves may be folded or rolled up.
Que-7: The apparatus shown in the following diagram is Garreau’s potometer designed to demonstrate unequal transpiration from the two surfaces of a dorsiventral leaf. Before keeping the leaf in between the cups, anhydrous calcium chloride (CaCl2) contained in two small vials were weighed and placed in both the cups. The ends of the cups were closed with corks through which two mercury manometers were connected. After few hours, CaCl2 vials were taken out and weighed again.
(a) What is the purpose of keeping CaCl2 vials inside the cup?
(b) After few hours CaCl2 vials were taken out and weighed again. Will you expect any difference in weight? If so, give reason.
(c) What is the purpose of using a manometer?
(d) What do you mean by transpiration?
Ans:
(a) CaCl2 is a hygroscopic compound that absorbs moisture/water without changing its state. CaCl2 vials inside the cup to absorb water.
(b) Yes, after few hours the weight of the CaCl2 vials will increase because they will absorb water lost by the leaf of the plant due to transpiration.
(c) Manometer is used to measure the pressure. In order to measure the pressure exerted by the fluid, the fluid is allowed to exert pressure on one of the closed ends of the tube. Under the effect of the pressure, the liquid inside the manometer tube gets displaced and the amount of displaced liquid is measured.
(d) Transpiration is the loss of water in the form of water vapour from the aerial parts (leaves and stem) of the plant.
Que-8: The figure given below is a transverse section of an old woody stem. It shows very minute openings labelled – A on its surface.
(a) What are these tiny openings called?
(b) Mention two significant functions of these openings.
(c) Name two other tiny openings which can be found on the surface or margins of leaves.
Ans:
(a) These tiny openings are called lenticels.
(b) Two functions of lenticels:
- They facilitate transpiration.
- They allow exchange of gases.
- s (c) Stomata and hydathodes.
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