Acids Bases and Salts Long Ans Concise Class-10 ICSE Chemistry Selina Solutions Chapter-3. We Provide Step by Step Answer of Long Ans Questions of Exercise-3 for ICSE Class-10. The given Solutions is according to the Latest editions. Visit official Website CISCE for detail information about ICSE Board Class-10.
Acids Bases and Salts Long Ans Concise Class-10 ICSE Chemistry Selina Solutions Chapter-3
| Board | ICSE |
| Book / Publication | Concise / Selina |
| Subject | Chemistry |
| Class | 10th |
| Writer | Dr SP Singh |
| Chapter-3 | Acids Bases and Salts |
| Topics | Long Ans |
| Edition | 2025-2026 |
Long Ans Questions on Acids Bases and Salts
Page-63
Que-1: Draw the structure of the stable positive ion formed when an acid dissolves in water.
Ans: Hydronium ion is the stable positive ion formed when an acid dissolves in water. Its structure is shown below:
Que-2: Write a balanced reaction for the following conversions (A, B, C, D) (2015)
Ans:
A = HCl
B = Na2CO3
C = HNO3
D = NaOH
A: Fe + 2HCl → FeCl2 + H2
B: FeCl2 + Zn→ ZnCl2 + Fe
Fe + H2CO3 → FeCO3 + H2↑
C: FeCO3 + 2HNO3 → Fe (NO3)2 + H2O + CO2
D: Fe(NO3)2 + 2NaOH → Fe(OH)2 + 2NaNO3
Que-3: Give equations for the following conversions A to E:
Answer
(i) ZnSO4 + Na2CO3 ⟶ Na2SO4 + ZnCO3 ↓
(ii) ZnCO3 + 2HNO3 ⟶ Zn(NO3)2 + H2O + CO2 ↑
(iii) Zn(NO3)2 + 2NaOH ⟶ Zn(OH)2 + 2NaNO3
(iv) Zn(OH)2→ Δ Δ ZnO + H2O
(v) ZnO + H2SO4 ⟶ ZnSO4 + H2O
Que-4: The preparation of Lead sulphate from Lead carbonate is a two-step process. (Lead sulphate cannot be prepared by adding dilute Sulphuric acid to Lead carbonate.)
(a) What is the first step that is required to prepare Lead sulphate from Lead carbonate?
(b) Write the equation for the reaction that will take place when this first step is carried out.
(c) Why is the direct addition of dilute sulphuric acid to Lead carbonate an impractical method of preparing Lead sulphate?
Ans:
(a) The first step is to convert insoluble lead carbonate into soluble lead nitrate by treating lead carbonate with dilute nitric acid.
(b) PbCO3 (s) + 2HNO3(dil) ⟶ Pb(NO3)2 (aq) + H2O (l) + CO2
(c) When dilute sulphuric acid is added directly to lead carbonate, the lead sulphate thus formed will be deposited on solid lead carbonate disconnecting lead carbonate from sulphuric acid.
Que-5: The diagram given below is to prepare iron [III] chloride in the laboratory:
![to prepare iron [III] chloride in the laboratory](https://icsehelp.com/wp-content/uploads/2019/10/iron-chloride-300x98.png)
Look at the diagram and answer the question given below:
(i) What is substance B?
(ii) What is the purpose of B?
(iii) Why is iron [III] chloride to be stored in a closed container?
(iv) Write the equation for the reaction between iron and chlorine.
Ans:
(i) Substance B is fused calcium chloride.
(ii) Iron (III) chloride is highly deliquescent so it is kept dry with the help of B [fused calcium chloride (drying agent)]
(iii) Iron[III] chloride is to be stored in a closed container because iron (III) chloride is highly deliquescent and it absorbs moisture from the surrounding air to form a saturated solution.
(iv) 2Fe (heated) + 3Cl2 (dry) ⟶ 2FeCl3
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