Acids Bases and Salts Short Ans Concise Class-10 ICSE Chemistry Selina Solutions Chapter-3. We Provide Step by Step Answer of Short Ans Questions of Exercise-3 for ICSE Class-10. The given Solutions is according to the Latest editions. Visit official Website CISCE for detail information about ICSE Board Class-10.

Acids Bases and Salts Short Ans Concise Class-10 ICSE Chemistry Selina Solutions Chapter-3

Board	ICSE
Book / Publication	Concise / Selina
Subject	Chemistry
Class	10th
Writer	Dr SP Singh
Chapter-3	Acids Bases and Salts
Topics	Short Ans
Edition	2025-2026

Short Ans Questions on Acids Bases and Salts

Page-63

Que-1: Define the following term -Neutralisation.

Ans: A neutralisation reaction is when an acid and a base react to form water and a salt, and involves the combination of H⁺ ions and OH^– ions to generate water.

Que-2: State your observation when zinc granule is added to copper sulphate solution.

Ans:
Zinc displaces copper to form zinc sulphate and thus copper gets deposited and the blue coloured solution becomes colourless.
Zn + CuSO₄ ⟶ Cu + ZnSO₄

Que-3: Salt S is prepared by reacting dilute sulphuric acid with copper oxide. Identify S.

Ans: Salt S is Copper sulphate CuSO₄
CuO + H₂SO₄ (dil.) ⟶ CuSO₄ + H₂O

Que-4: From the substances given in the list below, write the equations for the reactions by which you could obtain the compounds given ahead :

Dilute sulphuric acid	sodium carbonate
Zinc	sodium sulphite
Lead	calcium carbonate

(i) hydrogen,
(ii) sulphur dioxide,
(iii) carbon dioxide,
(iv) zinc carbonate (two steps required).

Ans: Equations for the reactions are :
(i) Zn + H₂SO₄ ⟶ ZnSO₄ + H₂↑
(ii) Na₂SO₃ + 2HCl ⟶ 2NaCl + H₂O + SO₂↑
(iii) Na₂CO₃ + H₂SO₄→ Δ  ​ Na₂SO₄ + H₂O + CO₂↑
(iv) Zn + H₂SO₄ ⟶ ZnSO₄ + H₂↑
ZnSO₄ + Na₂CO₃ ⟶ Na₂SO₄ + ZnCO₃

Que-5: Choosing the substances from the list given:

dil. Sulphuric acid, Copper, Iron, Sodium, Copper (II) carbonate, Sodium carbonate, Sodium chloride, Zinc nitrate
Write balanced equations for the reactions which would be used in the laboratory to obtain the following salts:
(a) Sodium sulphate
(b) Zinc carbonate
(c) Copper (II) sulphate
(d) Iron (II) sulphate.

Ans:
(a) Sodium sulphate
Na₂CO₃ + H₂SO₄ (dil.) ⟶ Na₂SO₄ + H₂O + CO₂
(b) Zinc carbonate
Zn(NO₃)₂ + Na₂CO₃⟶ 2NaNO₃ + ZnCO₃
(c) Copper (II) sulphate
CuCO₃ + H₂SO₄ (dil.) ⟶ CuSO₄ + H₂O + CO₂
(d) Iron (II) sulphate
Fe + H₂SO₄ (dil.) ⟶ FeSO₄ + H₂

Que-6: You are given three solutions A, B and C. A is a strong acid, B is a weak acid and C is a strong alkali.

(a) Which solution contains solute molecules in addition to water molecules ?
(b) Which solution gives gelatinous white precipitate with zinc sulphate which disappears in excess solution ?

Ans:
(a) Solution B — weak acid
Hint: Weak Acid is an acid which dissociates only partially in aqueous solution thereby producing a low concentration of hydrogen [H⁺] ions [or H₃O⁺ ions]. For example — CH₃COOH ⇌ CH₃COO^– + H⁺ [contains molecules and ions]
(b) Solution C — strong alkali
Hint: Alkalis react with certain salt solutions to precipitate insoluble hydroxide. Hence,
ZnSO₄ + 2NaOH ⟶ Na₂SO₄ + Zn(OH)₂ [gelatinous white precipitate]

Que-7: Write balanced chemical equations for the following:

(a) Reaction of silver nitrate solution and sodium chloride solution.
(b) Lead nitrate solution is added to sodium chloride solution.
(c) State what happens to the crystals of washing soda when they are exposed to air. Name the phenomenon exhibited.

Ans:
(a) AgNO₃ + NaCl ⟶ NaNO₃ + AgCl ↓
(b) Pb(NO₃)₂ + 2NaCl ⟶ PbCl₂ ↓ + 2NaNO₃
(c) When crystals of washing soda are exposed to air, it loses its water of crystallisation and the phenomenon is known as Efflorescence.

Que-8: Give a balanced equation for the preparation of the following salts:

(a) Copper [II] sulphate from copper [II] oxide.
(b) Iron [III] chloride from the metal iron.
(c) Lead sulphate from lead carbonate.
(d) Potassium sulphate from KOH solution.
(e) Lead [II] chloride from lead carbonate [give two equations].
(f) Sodium sulphate — using dilute sulphuric acid.
(g) Copper chloride — using copper carbonate.

Ans:
(a) CuO + H₂SO₄ ⟶ CuSO₄ + H₂O
(b) 2Fe + 3Cl₂ ⟶ 2FeCl₃
(c) PbCO₃ + 2HNO₃ ⟶ Pb(NO₃)₂ + H₂O + CO₂
Pb(NO₃)₂ + Na₂SO₄ ⟶ 2NaNO₃ + PbSO₄
(d) 2KOH + H₂SO₄ [dil.] ⟶ K₂SO₄ + 2H₂O
(e) PbCO₃ + 2HNO₃ ⟶ Pb(NO₃)₂ + H₂O + CO₂ ↑
Pb(NO₃)₂ + 2NaCl ⟶ 2NaNO₃ + PbCl₂
(f) Na₂CO₃ + H₂SO₄(dil.) ⟶ Na₂SO₄ + H₂O + CO₂
(g) CuCO₃ + 2HCl (dil) ⟶ CuCl₂ + H₂O + CO₂

Que-9: Write the balanced equations for the preparation of the following compounds (as major product) starting from iron and using only one other substance:

(a) Iron (II) chloride
(b) Iron (III) chloride
(c) Iron (II) sulphate
(d) Iron (II) sulphide

Ans:
(a) Fe + 2HCl (dil) FeCl₂ + H₂
(b) 2Fe (heated) + 3Cl₂ (dry)  2FeCl₃
(c) Fe + H₂SO₄ (dil)  FeSO₄ + H₂
(d) Fe + S  FeS

—:  End of Acids Bases and Salts Short Ans Concise Class-10 ICSE Chemistry Selina Solutions : –

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