Saturday, March 25, 2023
No menu items!

Circular Motion Obj-2 HC Verma Solutions Vol-1 Ch-7

Circular Motion Obj-2 HC Verma Solutions Vol-1 Ch-7 Concept of Physics for Class-11. Step by Step Solutions of Objective -2 (MCQ-2) Questions of Chapter-7 Circular Motion (Concept of Physics) .Visit official Website CISCE for detail information about ISC Board Class-11 Physics.

Circular Motion Obj-2 (MCQ-2) HC Verma Solutions Ch-7 Vol-1 Concept of Physics for Class-11

Board ISC and other board
Publications Bharti Bhawan Publishers
Chapter-7 Circular Motion
Class 11
Vol  1st
writer HC Verma
Book Name Concept of Physics
Topics Solution of Objective-2 (MCQ-2) Questions
Page-Number 113, 114

-: Select Topics :-

Question for Short Answer

Objective-I

Objective-II

Exercise


Circular Motion Obj-2 (MCQ-2) HC Verma

HC Verma Solutions of Ch-7  Vol-1 Concept of Physics for Class-11

(Page-113)

Question-1 :-

An object follows a curved path. The following quantities may remain constant during the motion

(a) speed
(b) velocity
(c) acceleration
(d) magnitude of acceleration.

Answer-1 :-

The options (a) and (d) are correct

Explanation:

When an object follows a curved path, its direction changes continuously. So, the scalar quantities like speed and magnitude of acceleration may remain constant during the motion.

Answer-3 :-

The options (b) and (d) are correct

Explanation:

If the speed is constant, the position vector of the particle sweeps out equal area in equal time in circular motion.
Also, for constant speed, tangential acceleration is zero, i.e., constant.

Question-4 :-

A particle is going in a spiral path as shown in figure (7-Q.3) with constant speed.

A particle is going in a spiral path as shown in figure with constant speed.

figure (7-Q.3)

(a) The velocity of the particle is constant.

(b) The acceleration of the particle is constant.

(c) The magnitude of acceleration is constant.

(d) The magnitude of acceleration is decreasing continuously.

Answer-4 :-

The options (c) The magnitude of acceleration is constant .is correct.

Explanation:

As the pitch and radius of the path is constant, it shows that the magnitude of tangential and radial acceleration is also constant.
Hence, the magnitude of total acceleration is constant.


(Page-114)

Question-5 :-

A car of mass M is moving on a horizontal circular path of radius r. At an instant its speed is v and is increasing at a rate a.
(a) The acceleration of the car is towards the centre of the path.
(b) The magnitude of the frictional force on the car is greater than mv²/r

(c) The friction coefficient between the ground and the car is not less than a/g.
(d) The friction coefficient between the ground and the car is hc verma cercular motion img 2

Answer-5 :-

The options (b) and (c) are correct

Explanation:

If the magnitude of the frictional force on the car is not greater than mv²/r , it will not move forward, as its speed (v) is increasing at a rate a.

Question-6 :-

A circular road of radius r is banked for a speed v = 40 km/hr. A car of mass of m attempts to go on the circular road. The friction coefficient between the tyre and the road is negligible.

(a) The are cannot make a turn without skidding.
(b) If the car turns at a speed less than 40 km/hr, it will slip down.

(c) If the car turns at the car is equal to mv²/r.

(d) If the car turns at the correct speed of 40 km/hr, the force by the road on the car is greater than mg as well as greater than mv²/r.

Answer-6 :-

The options (b) and (d) are correct

Explanation:

The friction is zero and the road is banked for a speed v = 40 km/hr. If the car turns at a speed less than 40 km/hr, it will slip down.

Question-7 :-

A person applies constant force F  on a particle of mass m and finds that the particle moves in a circle of radius r with a uniform speed v as seen from an inertial frame of reference.

(a) This is not possible.
(b) There are other forces on the particle.
(c) The resultant of the other forces is mv²/r towards the centre.

d) The resultant of the other forces varies in magnitude as well as in direction

Answer-7 :-

The options (b) and (d) are correct

Explanation:

We cannot move a particle in a circle by just applying a constant force. So, there are other forces on the particle.
As a constant force cannot move a particle in a circle, the resultant of other forces varies in magnitude as well as in direction (because   is constant).

—: End of Circular Motion Obj-2 (MCQ-2) HC Verma Solutions Ch-7 Vol-I :–


Return to — HC Verma Solutions Vol-1 Concept of Physics

Thanks

Share with your friends

RELATED ARTICLES

Most Popular