Saturday, March 25, 2023

# Circular Motion Obj-2 HC Verma Solutions Vol-1 Ch-7

Circular Motion Obj-2 HC Verma Solutions Vol-1 Ch-7 Concept of Physics for Class-11. Step by Step Solutions ofÂ Objective -2 (MCQ-2)Â Questions of Chapter-7 Circular Motion (Concept of Physics) .Visit official WebsiteÂ CISCEÂ for detail information about ISC Board Class-11 Physics.

## Circular Motion Obj-2 (MCQ-2) HC Verma SolutionsÂ Ch-7 Vol-1 Concept of Physics for Class-11

 Board ISC and other board Publications Bharti Bhawan Publishers Chapter-7 Circular Motion Class 11 Vol Â 1st writer HC Verma Book Name Concept of Physics Topics Solution ofÂ Objective-2Â (MCQ-2) Questions Page-Number 113, 114

-: Select Topics :-

Objective-I

Objective-II

Exercise

Circular Motion Obj-2Â (MCQ-2) HC Verma

### HC Verma Solutions of Ch-7Â  Vol-1 Concept of Physics for Class-11

(Page-113)

#### Question-1 :-

An object follows a curved path. The following quantities may remain constant during the motion

(a) speed
(b) velocity
(c) acceleration
(d) magnitude of acceleration.

The optionsÂ (a)Â andÂ (d)Â are correct

Explanation:

When an object follows a curved path, its direction changes continuously. So, the scalar quantities like speed and magnitude of acceleration may remain constant during the motion.

The optionsÂ (b)Â andÂ (d)Â are correct

Explanation:

If the speed is constant, the position vector of the particle sweeps out equal area in equal time in circular motion.
Also, for constant speed, tangential acceleration is zero, i.e., constant.

#### Question-4 :-

A particle is going in a spiral path as shown in figure (7-Q.3) with constant speed.

figure (7-Q.3)

(a)Â The velocity of the particle is constant.

(b) The acceleration of the particle is constant.

(c) The magnitude of acceleration is constant.

(d) The magnitude of acceleration is decreasing continuously.

The options (c) The magnitude of acceleration is constant .is correct.

Explanation:

As the pitch and radius of the path is constant, it shows that the magnitude of tangential and radial acceleration is also constant.
Hence, the magnitude of total acceleration is constant.

(Page-114)

#### Question-5 :-

A car of massÂ MÂ is moving on a horizontal circular path of radiusÂ r. At an instant its speed isÂ vÂ and is increasing at a rateÂ a.
(a) The acceleration of the car is towards the centre of the path.
(b) The magnitude of the frictional force on the car is greater than mvÂ²/r

(c) The friction coefficient between the ground and the car is not less thanÂ a/g.
(d) The friction coefficient between the ground and the car is

The optionsÂ (b)Â andÂ (c)Â are correct

Explanation:

If the magnitude of the frictional force on the car is not greater than mvÂ²/r , it will not move forward, as its speed (v) is increasing at a rate a.

#### Question-6 :-

A circular road of radiusÂ rÂ is banked for a speedÂ vÂ = 40 km/hr. A car of mass ofÂ m attempts to go on the circular road. The friction coefficient between the tyre and the road is negligible.

(a) The are cannot make a turn without skidding.
(b) If the car turns at a speed less than 40 km/hr, it will slip down.

(c) If the car turns at the car is equal to mvÂ²/r.

(d) If the car turns at the correct speed of 40 km/hr, the force by the road on the car is greater than mg as well as greater than mvÂ²/r.

The optionsÂ (b)Â andÂ (d)Â are correct

Explanation:

The friction is zero and the road is banked for a speedÂ vÂ = 40 km/hr. If the car turns at a speed less than 40 km/hr, it will slip down.

#### Question-7 :-

A person applies constant force F âƒ—Â on a particle of massÂ mÂ and finds that the particle moves in a circle of radiusÂ rÂ with a uniform speedÂ vÂ as seen from an inertial frame of reference.

(a) This is not possible.
(b) There are other forces on the particle.
(c) The resultant of the other forces is mvÂ²/r towards the centre.

d) The resultant of the other forces varies in magnitude as well as in direction

The optionsÂ (b)Â andÂ (d)Â are correct

Explanation:

We cannot move a particle in a circle by just applying a constant force. So, there are other forces on the particle.
As a constant force cannot move a particle in a circle, the resultant of other forces varies in magnitude as well as in direction (because FÂ âƒ—Â  is constant).

â€”: End of Circular Motion Obj-2 (MCQ-2) HC Verma Solutions Ch-7 Vol-I :â€“

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