De-Broglie Wavelength Numerical When Accelerating Potential is Given Class-12 Nootan ISC Physics Solution Ch-24 Matter Waves. Step by step solutions of Kumar and Mittal Physics of Nageen Prakashan as council latest prescribe guideline for upcoming exam. Visit official Website CISCE for detail information about ISC Board Class-12 Physics.
De-Broglie Wavelength Numerical When Accelerating Potential is Given Class-12 Nootan ISC Physics Solution Ch-24 Matter Waves
| Board | ISC |
| Class | 12 |
| Subject | Physics |
| Book | Nootan |
| Chapter-24 | Matter Waves |
| Topics | De-Broglie Wavelength Numerical When Accelerating Potential is Given |
| Academic Session | 2025-2026 |
Class-12 Nootan ISC Physics Solution Ch-24 Matter Waves
De-Broglie Wavelength Numerical When Accelerating Potential is Given
Que-7: Calculate de-Broglie wavelength of an electron of energy 400 eV.
Ans- λ = h/√2mk
= 6.6 x 10^-34 / √(2 x 9.1 x 10^-31 x 400 x 1.6 x 10^-19)
= 0.6116 x 10^-14
= 6116 x 10^-10
= 6116 Å
Que-8: Calculate the de-Broglie wavelength of an electron beam accelerated through a potential difference of 60 V.
Ans- λ = 12.27/√V Å
= 12.27 / √60 Å
= 12.27 / 7.75 Å
= 1.58 Å
Que-9: In a diode valve, the anode has a potential of 100 V relative to the cathode. Find the de-Broglie wavelength of electrons on reaching the anode.
Ans- λ = 12.27/√V Å
= 12.27 / √100 Å
= 1.227 Å
Que-10: What potential must be applied to an electron microscope to produce electrons of wavelength 1.0 Å?
Ans- λ = 12.27/√V Å
1.0 = 12.27 / √V Å
√V = 12.27/1
V = (12.27)^2 = 150 V
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