Decimals Class- 7th RS Aggarwal Exe-3F Goyal Brothers ICSE Math Solution

Decimals Class- 7th RS Aggarwal Exe-3F Goyal Brothers ICSE Math Solution . We provide step by step Solutions of lesson-3 Decimals for ICSE Class-7 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan . Our Solutions contain all type Questions of Exe-3F to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-7 Mathematics.

Decimals Class- 7th RS Aggarwal Exe-3F Goyal Brothers ICSE Math Solution

Decimals Class- 7th RS Aggarwal Exe-3F Goyal Brothers ICSE Math Solution

Board ICSE
Publications Goyal brothers Prakashan
Subject Maths
Class 7th
Chapter-3 Decimals
Writer RS Aggrawal
Book Name Foundation
Topics Solution of Exe-3F
Academic Session 2023 – 2024

Exercise – 3F

Decimals Class- 7th RS Aggarwal Exe-3F Goyal Brothers ICSE Math Solution

1. Round off each of the following to the nearest whole number :

(i) 87.46

Solution: 87.46

= 87      (46 is less than 50)

(ii) 65.83

Solution: 65.83

= 66       (83 is greater than 50)

(iii) 71.54

Solution: 71.54

= 72       (54 is greater than 50)

(iv) 98.5

Solution: 98.5

= 99          (5 is equal than 50)

(v) 60.29

Solution: 60.29

= 60          (29 is less than 50)

2. Round off :

(i) 6.342, correct to 2 decimal places

Solution: 6.342, correct to 2 decimal places

= 6.340           [approx]

= 6.34

(ii) 8.1347, correct to 3 decimal places

Solution: 8.1347, correct to 3 decimal places

= 8.1350           [approx]

= 8.135

(iii) 0.845, correct to 2 decimal places

Solution: 0.845, correct to 2 decimal places

= 0.850           [approx]

= 0.85

(iv) 1.732, correct to 1 decimal places

Solution: 1.732, correct to 1 decimal places

= 1.732         [approx]

= 1.73           [approx]

= 1.7

(v) 9.638, correct to 2 decimal places

Solution: 9.638, correct to 2 decimal places

= 9.640          [approx]

= 9.64

(vi) 0.047, correct to 2 decimal places

Solution: 0.047, correct to 2 decimal places

= 0.050          [approx]

= 0.05

3. Write the value of :

(i) 7.451 to the nearest hundredths

Solution: 7.451 to the nearest hundredths

= 7.450         [approx]

= 7.45

(ii) 3.157 to the nearest tenths

Solution: 3.157 to the nearest tenths

= 3.16        [approx]

= 3.2

(iii) 0.6428 to the nearest thousandths

Solution: 0.6428 to the nearest thousandths

= 0.6430        [approx]

= 0.643

(iv) 0.061 to the nearest tenths

Solution: 0.061 to the nearest tenths

= 0.06         [approx]

= 0.10         [approx]

= 0.1

(v) 0.136 to the nearest hundredths

Solution: 0.136 to the nearest hundredths

= 0.140        [approx]

= 0.14

4. Express (6/7) as a decimal, correct to 2 decimal places.

Solution: (6/7)

= 0.857

= 0.860           [approx]

= 0.86

— : end of Decimals Class- 7th RS Aggarwal Exe-3F Goyal Brothers ICSE Math Solution:–

Return to- ICSE Class -7 RS Aggarwal Goyal Brothers Math Solutions

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