Fractions Class- 7th RS Aggarwal Exe-2B Goyal Brothers ICSE Math Solution . We provide step by step Solutions of lesson-2 Fractions for ICSE Class-7 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan . Our Solutions contain all type Questions of Exe-2B to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-7 Mathematics.
Fractions Class- 7th RS Aggarwal Exe-2B Goyal Brothers ICSE Math Solution
| Board | ICSE |
| Publications | Goyal brothers Prakashan |
| Subject | Maths |
| Class | 7th |
| Chapter-2 | Fractions |
| Writer | RS Aggrawal |
| Book Name | Foundation |
| Topics | Solution of Exe-2B |
| Academic Session | 2023 – 2024 |
Exercise – 2B
Fractions Class- 7th RS Aggarwal Exe-2B Goyal Brothers ICSE Math Solution
Que: 1. Find the reciprocal of :
(i) 13/17
Solution: 13/17
= 1(4/13)
(ii) 3/313
Solution: 3/313
= 313/3
= 104(1/3)
(iii) 217
Solution: 217
= 1/217
(iv) 1/1024
Solution: 1/1024
= 1024
(v) 3(1/3)
Solution: 3(1/3)
= 10/3
= 3/10
(vi) 11(1/11)
Solution: 11(1/11)
= 122/11
= 11/122
(vii) 1(1/2)
Solution: 1(1/2)
= 3/2
= 2/3
(viii) 125(1/8)
Solution: 125(1/8)
= 1008/8
= 8/1008
2. Divide :
(i) (1/2) ÷ (1/3)
Solution: (1/2) ÷ (1/3)
= (1/2) × (3/1)
= 3/2
= 1(1/2)
(ii) (3/14) ÷ (11/42)
Solution: (3/14) ÷ (11/42)
= (3/14) × (42/11)
= (3/1) × (3/11)
= 9/11
(iii) 1 ÷ 6(2/3)
Solution: 1 ÷ 6(2/3)
= 1 ÷ (20/3)
= 1 × (3/20)
= 3/20
(iv) 13(1/3) ÷ 10
Solution: 13(1/3) ÷ 10
= (40/3) ÷ 10
= (40/3) × 10
= 4/3 = 1(1/3)
(v) 12(1/12) ÷ (5/36)
Solution: 12(1/12) ÷ (5/36)
= (145/12) ÷ (5/36)
= (145/12) × (36/5)
= 29 × 3
= 87
(vi) (13/46) ÷ 2(1/11)
Solution: (13/46) ÷ 2(1/11)
= (13/46) ÷ (23/11)
= (13/46) × (11/23)
= 143/1058
(vii) (20/31) ÷ 54
Solution: (20/31) ÷ 54
= (20/31) × (1/54)
= (10/31) × (1/7)
= 10/837
(viii) 9(4/5) ÷ 3(23/25)
Solution: 9(4/5) ÷ 3(23/25)
= (49/5) ÷ (98/25)
= (1/1) × (5/2)
= 5/2 = 2(1/2)
(ix) 32(1/2) ÷ 8(3/4)
Solution: 32(1/2) ÷ 8(3/4)
= (65/2) ÷ (35/4)
= (65/2) × (4/35)
= 26/7 = 3(5/7)
(x) 8(1/21) ÷ 1(6/7)
Solution: 8(1/21) ÷ 1(6/7)
= (169/21) ÷ (13/7)
= (169/21) × (7/13)
= (13/3) × (1/1)
= 13/3 = 4(1/3)
(xi) 6(3/16) ÷ 3(1/7)
Solution: 6(3/16) ÷ 3(1/7)
= (99/16) ÷ (22/7)
= (99/16) × (7/22)
= 63/32 = 1(31/32)
(xii) 3(11/15) ÷ 19(3/5)
Solution: 3(11/15) ÷ 19(3/5)
= (56/15) ÷ (98/5)
= (56/15) ×(5/98)
= 28/147 = 4/21
3. By what fraction should 9/35 be multiplied to get 7/15 ?
Solution: First No. = 9/35
Second No. = (7/5) ÷ (9/35)
= (7/5) × (35/9)
= (7 × 7)/(3 × 9)
= 49/27 = 1(22/27)
4. If the cost of 6(1/4) m of cloth is ₹1421(7/8), Then find the cost of 1 meter of cloth.
Solution: 6(1/4) m of cloth cost = ₹1421(7/8)
1 m of cloth cost = ₹1421(7/8) ÷ 6(1/4)
= ₹(11375/8) ÷ (25/4)
= ₹(11375/8) × (4/25)
= ₹455/2 = ₹227(1/2)
5. How many pieces of length 3(5/7) m each can be cut from a wall paper 52 m long?
Solution: Total wall paper = 52m
length of pieces = 3(5/7) m = 26/7m
Number of pieces = 26/7 ÷ 52
= (52/1) × (7/26)
= 14m
6. A log of wood 6(2/7) m in length, was cut into 11 pieces. What is the length of each pieces?
Solution: L of wood = 6(2/7) m = 44/7 m
Cutting pieces = 11 pieces
L of each pieces = 44/7 ÷ 11
= (44/7) × (1/11)
= 4/7 m
7. A car covers 641(1/4) km in 43(1/8) liters of fuel. How much distance can this car cover in 1 liter of fuel?
Solution: Car covered distance in 43(1/8) = 44/8 liters fuel = 641(1/4) km = 2565/4
Distance covered in 1 liter fuel = ((2565/4) ÷ 43(1/8))km
= 2565/4 ÷ 345/8
= 342/23
= 14(20/23)km
8. The area of a rectangular plot of land is 817(4/5) sq. m. If its breadth is 21(3/4) m, find its length.
Solution: Plot area 817(4/5) sq. m.
Plot breadth = 21(3/4) m
Length of plot = (817(4/5) ÷ 21(3/4)
= (4089/5) ÷ (87/4)
= (4089/5) × (87/4)
= (47 × 4)/(5 × 1)
= 188/5m
= 37(3/5)m
9. The area of a sheet of paper is 623(7/10) sq. cm. If its length is 29(7/10) cm, find its width.
Solution: Area of sheet of paper = 623(7/10) sq. = 6237/10 sq. cm.
Length of sheet of paper = 29(7/10) cm = 297/10 m.
width = ((6237/10) ÷ (297/10))
= (6237/10) × (10/297)
= (21 × 1)/(1 × 1)
= 21 m.
10. A bundle of 500 sheets of paper has a net weight of 2(3/10) kg. Find the weight of 1 sheet of paper.
Solution: Weight of 500 sheet of paper = 2(3/10) = 23/10 kg
Weight of 1 sheet of paper = ((23/10) ÷ 500)
= (23/10) ÷ 500
= (23/10) × (1/500)
= 23/5000
11. A car travels 283(1/2) km in 4(2/3) hours. How far does this car go in 1 hour, travelling at the same speed?
Solution: Distance covered by car in 4(2/3) hours = 283(1/2) = 567/2km
Distance covered by car in 1 hours = ((567/2) ÷ (14/3))km
= (567/2) × (3/14)
= (81 × 1)/(1 × 2)
= 81/2
= 40(1/2)
12. The product of two fractions is 8(7/25). If one of them is 3(1/15), find the other.
Solution: Two fractions = 8(7/25) = 207/25
First fractions = 3(1/15) = 46/15
Second number = ((207/25) ÷ (46/15))
= (207/25) × (15/46)
= 621/230
= 27/10
= 2(7/10)
— : end of Fractions Class- 7th RS Aggarwal Exe-2B Goyal Brothers ICSE Math Solution :–
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