Hydrogen Chloride Very Short Ans Concise Class-10 ICSE Chemistry Selina Solutions Chapter-8. We Provide Step by Step Answer of Very Short Ans Questions of Exercise-8 for ICSE Class-10. The given Solutions is according to the Latest editions. Visit official Website CISCE for detail information about ICSE Board Class-10.

Hydrogen Chloride Very Short Ans Concise Class-10 ICSE Chemistry Selina Solutions Chapter-8
| Board | ICSE |
| Book / Publication | Concise / Selina |
| Subject | Chemistry |
| Class | 10th |
| Writer | Dr SP Singh |
| Chapter-8 | Study of Compounds – Hydrogen Chloride |
| Topics | Very Short Ans |
| Edition | 2025-2026 |
Very Short Ans Questions on Study of Compounds-Hydrogen Chloride
Page-151
Que-1: Fill in the blank from the choices in the brackets:
(a) Quicklime is not used to dry HCl gas because [CaO is alkaline, CaO is acidic, CaO is neutral].
(b) When sodium chloride is heated with concentrated sulphuric acid below 200°C, one of the product formed is …………… (sodium hydrogen sulphate / sodium sulphate / chlorine).
Ans:
(a) alkaline.
(b) sodium hydrogen sulphate
Que-2: Name:
(a) A Black metallic oxide which reacts with hydrochloric acid to give a coloured solution.
(b) Two colourless gases, which when mixed produce a white solid.
(c) Two gases which chemically combine to form liquid.
(d) A chloride which is soluble in excess of ammonium hydroxide.
(e) The chemical in which gold can be dissolved.
(f) the experiment which demonstrates that hydrogen chloride is soluble in water.
(g) the gas produced when chlorine water is exposed to sunlight.
(h) the acid which on mixing with silver nitrate solution produces a white precipitate which is soluble in excess of ammonium hydroxide.
(i) the gas which produces dense white fumes with ammonia gas.
(j) an element which reacts with hydrogen to form compound which is strongly acidic in water.
Ans:
(a) Manganese dioxide
(b) Hydrogen chloride and ammonia
(c) Hydrogen and oxygen
(d) AgCl(Silver chloride)
(e) Aqua regia
(f) Fountain experiment
(g) Hydrogen chloride gas
(h) Dilute hydrochloric acid
(i) Hydrogen chloride
(j) Chlorine
Que-3: Identify the gas evolved when
(i) Potassium sulphite is treated with dilute hydrochloric acid.
(ii) Concentrated hydrochloric acid is made to react with manganese dioxide.
Ans:
(i) When potassium sulphite is treated with dilute hydrochloric acid, sulphur dioxide gas is evolved.
![]()
(ii) When concentrated hydrochloric acid is made to react with manganese dioxide, chlorine gas is evolved.
![]()
Que-4: Solution A reacts with an acid B (which gives greenish yellow gas on reacting with oxidizing agents like Pb3O4) to give white precipitate C insoluble in nitric acid but soluble in ammonium hydroxide. Name A, B and C.
Ans:
A is Silver nitrate
B is Hydrochloric acid
C is Silver chloride
—: End of Study of Compounds – Hydrogen Chloride Very Short Ans Concise Class-10 ICSE Chemistry Selina Solutions : –
Return to:- Concise Selina Chemistry for ICSE Class-10 Solutions
Please Share with Your Friends if Helpful
Thanks



