ML Aggarwal Integers Exe-1.1 Class 7 ICSE Maths Solutions
ML Aggarwal Integers Exe-1.1 Class 7 ICSE Maths Solutions. We Provide Step by Step Answer of Exe-1.1 Questions for Integers as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-7.
ML Aggarwal Integers Exe-1.1 Class 7 ICSE Maths Solutions
| Board | ICSE |
| Publications | Avichal Publishig Company (APC) |
| Subject | Maths |
| Class | 7th |
| Chapter-1 | Integers |
| Writer | ML Aggarwal |
| Book Name | Understanding |
| Topics | Solution of Exe-1.1 Questions |
| Edition | 2023-2024 |
Integers Exe-1.1
ML Aggarwal Class 7 ICSE Maths Solutions
Page-4
Question 1. Some integers are marked on the following number line:
(i) Write these integers in ascending order.
(ii) Write these integers in descending order.
(iii) Few dots have been marked on the above number line. Write an appropriate integer at each dot.
Answer:
(i) Given integers in ascending order = – 18, – 9, – 4, 0, 3, 8, 12
(ii) Given integers in descending order = 12, 8, 3, 0, -4, -9, -18
(iii) Few dots have been marked on the above number line,
Integers at each dot = – 17, -14, -11, – 7, -5, -3, 1, 4, 7, 9, 11
Question 2. Arrange 7, -5, 4, 0 and -4 in ascending order and mark them on a number line to check your answer.
Answer:
Ascending order of given integers, -5, -4, 0, 4, 7
Representing the given integers on a number line, we get,
Question 3. In a quiz, positive marks are given for correct answers and negative marks are given for incorrect answers. If Rohit’s scores in five successive rounds were 15, -3, -7, 12 and 8, what was his total at the end?
Answer:
From the question, it is given that,
Rohit’s scores in five successive rounds were 15, -3, -7, 12 and 8
= 15 – 3 – 7 + 12 + 8
= 15 + 12 + 8 – 3 – 7
= 35 – 10
= 25
Hence, Rohit’s total score is 25.
Question 4. Ruchi deposited ₹ 4370 in her account on Monday and then withdrew ₹ 2875 on Tuesday. Next day she deposited ₹ 1550. What was her balance on Thursday?
Answer:
Amount deposited by Ruchi on Monday = ₹ 4370
Amount withdrew on Tuesday by Ruchi = ₹ 2875
Amount deposited by Ruchi on Wednesday = ₹ 1550
So, her total deposit = ₹ 4370 + ₹ 1550 = ₹ 5920
Therefore, Balance on Thursday = ₹ 5920 – ₹ 2875 = ₹ 3045
Question 5. Evaluate the following:
(i) |-13| – |9|
(ii) |13 – 5| – |-9|
(iii) |35 – 21| – |8 – 3|
Answer:
(i) |-13| – |9| = 13 – 9 = 4
(ii) |13 – 5| – |-9| = |8| – |-9| = 8 – 9 = -1
(iii) |35 – 21| – |8 – 3| = |14| – |5| = 14 – 5 = 9
Question 6. Arrange the following integers in ascending order:
-39, 35, -102, 0, -51, -5, -6, 7
Answer:
-39, 35, -102, 0, -51, -5, -6, 7
Arrange in ascending order:
-102, -51, -39, -6, -5, 0, 7, 35
Question 7. Arrange the following integers in descending order:
-31, 139, -203, -97, 0, 4208
Answer:
-31, 139, -203, -97, 0, 4208
Arrange in descending order:
4208, 139, 0, -31, -97, -203
Question 8. State whether each of the following statement is true or false:
(i) 0 is the successor of -1 in integers
(ii) 0 has no predecessor in integers
(iii) -2 is the predecessor of -1
(iv) 0 is greater than every negative integer.
Answer:
(i) 0 is the successor of -1 in integers. True
(ii) 0 has no predecessor in integers. False
(iii) -2 is the predecessor of -1. True
(iv) 0 is greater than every negative integer. True
Question 9. Use the sign >, < or = in the box to make the following statements true:
(i) (-11) + (-7) ……….. (-11) – (-7)
(ii) 23 – 41 + 11 ……… 23 – 41 – 11
(iii) 40 – (-39) + (-5) …….. 40 + (-39) – (-5)
(iv) (-3) + 13 – (15) ……. 25 – (-2) + (-33)
Answer:
(i) (-11) + (-7) ……….. (-11) – (-7)
-18 < -11 + 7 = -4
(ii) 23 – 41 + 11 ……… 23 – 41 – 11
= 34 – 41 …….. 23 – 52
= -9 > -19
(iii) 40 – (-39) + (-5) …….. 40 + (-39) – (-5)
= 40 + 39 – 5 ……….. 40 – 39 + 5
= 79 – 5 ………….. 45 – 39
= 74 > 6
(iv) (-3) + 13 – (15) ……. 25 – (-2) + (-33)
= -3 + 13 – ………………… 25 + 2 – 33
= 13 – 18 ……………. 27 – 33
= -5 > -6
— : End of ML Aggarwal Integers Exe-1.1 Class 7 ICSE Maths Solutions :–
Return to – ML Aggarwal Maths Solutions for ICSE Class -7
Thanks
