Limits Class 11 OP Malhotra Exe-18E ISC Maths Solutions

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Limits Class 11 OP Malhotra Exe-18E ISC Maths Ch-18 Solutions. In this article you would learn about Method- 4 : Using Expansions. Step by step solutions of latest textbook has been given as latest syllabus. Visit official Website CISCE for detail information about ISC Board Class-11 Mathematics.

Limits Class 11 OP Malhotra Exe-18E ISC Maths Solutions

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Limits Class 11 OP Malhotra Exe-18E ISC Maths Solutions Ch-18

Board ISC
Publications  S Chand
Subject Maths
Class 11th
Chapter-18 Limits
Writer O.P. Malhotra
Exe-18(E) Method- 4 : Using Expansions.

Method- 4 : Using Expansions.

Limits Class 11 OP Malhotra Exe-18E ISC Maths Ch-18 Solutions.

In calculus, limits are a fundamental concept defining the behavior of a function as its input approaches a certain value. Sometimes, directly substituting the value into a limit expression results in an indeterminate form (like / (0/0) or making it difficult to evaluate the limit directly. In these cases, limits expansion or series expansion becomes a useful technique

What is limit expansion?

Limit expansion is a method for evaluating limits by expressing a function as an infinite series representation. This technique involves replacing complex functions within the limit expression with their corresponding Taylor or Maclaurin series expansions

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Que-1:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-1:

Sol:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-1: Solution

Que-2:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-2:

Sol:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-2: Solution

Que-3:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-3:

Sol:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-3: Solution

Que-4:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-4:

Sol:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-4: Solution

Que-5:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-5:

Sol:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-5: Solution
= (4×125)/(3×25)
= 20/3.

Que-6:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-6:

Sol:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-6: Solution
= (10×2^9)/(5×2^4)
= (2^10)/(2^4)
= 2^6 = 64.

Que-7:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-7:

Sol: 
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-7: Solution

Que-8:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-8:

Sol:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-8: Solution

Que-9:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-9:

Sol:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-9: Solution

Que-10: Find the value of a
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-10:

Sol:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-10: Solution

Que-11: Find all possible values of a,
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-11:

Sol:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-11: Solution
a = ±3, ±3i
Thus, required real values of a are ±3.

Que-12: Find all possible values of a,
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-12:

Sol:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-12: Solution
a = ±1.

Que-13:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-13:

Sol:
ISC CLASS-11 Maths OP Malhotra Ch-18 Exe-18E Que-13: Solution

–: End of Limits Class 11 OP Malhotra Exe-18E ISC Maths Ch-18 Solutions. :–

Return to :- OP Malhotra ISC Class-11 S Chand Publication Maths Solutions

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