Measurements and Experimentation Exe-1B MCQs Physics Class-9 ICSE Selina Publishers Solutions Chapter-1. Step By Step ICSE Selina Concise Solutions of Chapter-1Measurements and ExperimentationExe-1(B). Visit official Website CISCE for detail information about ICSE Board Class-9.
Measurements and Experimentation Exe-1B MCQs Physics Class-9 ICSE Concise Selina Publishers
| Board | ICSE |
| Publications | Selina Publication |
| Subject | Physics |
| Class | 9th |
| Chapter-1 | Measurements and Experimentation |
| Book Name | Concise |
| Topics | Solution of Exe-1(B) MCQs Type Measurement of Length |
| Academic Session | 2025-2026 |
Exe-1(B) MCQs Type
Measurements and Experimentation Class-9 Physics Solutions
Page 2
(Choose the correct answer from the options given below).
Que-1: Least count of metre rule having 10 subdivisions in 1 cm is:
(a) 0.01 mm
(b) 1 mm
(c) 0.001 mm
(d) 1 cm
Ans: (b) 1 mm
Hint- The least count of a metre rule is the value of its one division which is one-tenth of a centimetre (or 1 mm).
Que-2: The least count of a vernier callipers is:
(a) 1 cm
(b) 0.001 cm
(c) 0.1 cm
(d) 0.01 cm
Ans: (d) 0.01 cm
Hint- Least count of a vernier callipers is given by the formula:
Least count (L.C.)= Value of 1 main scale div (x)/total no. of div on vernier(n)/
Hence, least count of a vernier callipers whose main scale is graduated to read 1 mm and vernier scale has 10 division will be:
Least count (L.C.) = 1 mm/10
Least count (L.C.) = 0.1 mm = 0.01 cm
Que-3: The strip of a vernier callipers is used to measure:
(a) Length of a wire
(b) Depth of a beaker
(c) Internal diameter of a sphere
(d) Diameter of a hollow sphere
Ans: (b) Depth of a beaker
Hint- The function of Vernier callipers’ strip is to measure the depth of a beaker.
Que-4: On bringing the two jaws of a vernier callipers together, the 6th division of vernier scale coincides with the main scale. If the least count of the vernier callipers is 0.01 cm, then its zero error is:
(a) +0.06 cm
(b) +0.6 cm
(c) +0.006 cm
(d) +0.001 cm
Ans: (a) +0.06 cm
Hint- Zero error = +6 x Least count = +6 x 0.01 = 0.06 cm
Que-5: A microscope has its main scale with 20 divisions in 1 cm and vernier scale with 25 divisions, the length of which is equal to the length of 24 divisions of main scale. The least count of microscope is :
(a) 0.002 cm
(b) 0.001 cm
(c) 0.02 cm
(d) 0.01 cm
Ans: (a) 0.002 cm
Hint- The value of one main scale division x = 1/20 cm
The number of divisions on vernier scale n = 25
Using the formula given below,
Least count (L.C.) = Value of 1 main scale div (x)/total no. of div on vernier(n)
we get,
L.C. = x/n
L.C. = (1/20)/25 cm
L.C. = 1/500 cm
L.C. =0.002 cm
Hence, least count of microscope is 0.002 cm.
Que-6: Identify the correct use of the thimble of a screw gauge:
(a) To read length correct up to 0.01 mm
(b) To read length correct up to 1 mm
(c) To mark main scale and base line
(d) To mark circular scale.
Ans: (d) To mark circular scale.
Hint- Use of the thimble of a screw gauge is to mark the circular scale.
Que-7: Ratchet is a part of:
(a) Vernier callipers
(b) Slide callipers
(c) Screw gauge
(d) None of these
Ans: (c) Screw gauge
Hint- Ratchet is a part of screw gauge used to advance the screw by turning it till the object is gently held between the stud and spindle of the screw.
Que-8: The diameter of a thin wire can be measured by —
(a) A vernier callipers
(b) A metre rule
(c) A screw gauge
(d) None of these
Ans: (c) A screw gauge
Hint- A screw gauge is used to measure the diameter of a thin wire.
Que-9: The circular head of a screw gauge is divided into 50 divisions and the screw moves 1 mm ahead in two revolutions of the circular head. Its pitch would be:
(a) 0.05 cm
(b) 0.001 cm
(c) 0.5 cm
(d) 0.01 cm
Ans: (a) 0.05 cm
Hint- Pitch = distance moved ahead in 1 revolution
Given, distance moved in 2 revolutions = 1 mm
∴ Distance moved in 1 revolution = 1/2 mm = 0.5 mm
Converting 0.5 mm to cm,
0.5 mm = 0.5/10 cm = 0.05 cm
∴ Pitch of screw gauge is 0.05 cm
Que-10: Which of the following is the correct ascending order of accuracy?
(a) Metre rule, vernier callipers, screw gauge
(b) Vernier callipers, metre rule, screw gauge
(c) Screw gauge, vernier callipers, metre rule
(d) None of the above.
Ans: (a) Metre rule, vernier callipers, screw gauge
Hint- The least count of each is :
Meter rule = 0.1 cm
Vernier callipers = 0.01 cm
Screw gauge = 0.001 cm
Hence, the ascending order of accuracy is as follows:
Metre rule, vernier callipers, screw gauge
— : End of Measurements and Experimentation Exe-1B MCQs Class-9 ICSE Physics Solutions :–
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