ML Aggarwal Simple and Compound Interest Exe-8.2 Class 8 ICSE Ch-8 Maths Solutions. We Provide Step by Step Answer of Exe-8.2 Questions for Simple and Compound Interest as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-8.

**ML Aggarwal Simple and Compound Interest Exe-8.2 Class 8 ICSE Maths Solutions**

Board | ICSE |

Publications | Avichal Publishig Company (APC) |

Subject | Maths |

Class | 8th |

Chapter-8 | Simple and Compound Interest |

Writer | ML Aggarwal |

Book Name | Understanding |

Topics | Solution of Exe-8.2 Questions |

Edition | 2023-2024 |

**Simple and Compound Interest Exe-8.2**

### ML Aggarwal Class 8 ICSE Maths Solutions

Page-140

**Question 1. Calculate the compound interest on 6000 at 10% per for two Years.**

**Answer:**

Rate of interest = 10% per annum

Principal for the first year = Rs 6000

Interest for the first year = Rs (6000 × 10 × 1) / 100

= Rs 600

Amount at the end of first year = Rs 6000 + Rs 600

= Rs 6600

Principal for the second year = Rs 6600

Interest for the second year = Rs (6600 × 10 × 1) / 100

= Rs 660

Amount for the second year = Rs 6600 + Rs 660

= Rs 7260

Hence, compound interest for 2 years = final amount – (original) Principal

= Rs 7260 – Rs 6000

We get,

= Rs 1260

**Question 2. Salma borrowed from Mahila Samiti a sum of ₹ 1875 to purchase a sewing machine. If the rate of interest is 4% per annum, what is the compound interest that she has to pay after 2 years?**

**Answer:**

Principal for the first year = Rs. 1875

Rate of Interest = 4% p.a

Interest for the first year = Rs (1875 × 4 × 1) / 100

Amount at the end of first year =Rs. 1875+ Rs 75=Rs. 1950

Principal for the second year= Rs.1950

interest for the second year =Rs (1950 × 4 × 1) / 100

Amount at the end of first year =Rs.1950+ Rs .78=Rs. 2028

Therefore compound interest paid by salma = Final amount -(original) Principal

=Rs. 2028_ Rs. 1875

= Rs. 153

**Question 3. Jacob invests ₹12000 for 3 years at 10% per annum. Calculate the amount and the compound interest that Jacob will get after 3 years.**

**Answer:**

Principal for the first year = Rs 12000

Rate of interest = 10% p.a.

Interest for the first year = Rs (12000 × 10 × 1) / 100

= Rs 1200

Amount at the end of first year = Rs 12000 + Rs 1200

= 13200

Principal for the second year = Rs 13200

Interest for the second year = Rs (13200 × 10 × 1) / 100

= Rs 1320

Amount at the end of second year = Rs 13200 + Rs 1320

= Rs 14520

Principal for the third year = Rs 14520

Interest for the third year = Rs (14520 × 10 × 1) / 100

= Rs 1452

Amount at the end of third year = Rs 14520 + Rs 1452

= Rs 15972

Compound interest for 3 year = Final amount – (original) Principal

= Rs 15972 – Rs 12000

= Rs 3972

**Question 4. A man invests ₹46875 at 4% per annum compound interest for 3 years. Calculate:**

(i) the interest for the first year.

(ii) the amount standing to his credit at the end of second year.

(iii) the interest for the third year.

**Answer:**

**(i) Principal for the first year = Rs 46875**

Rate of interest = 4% per annum

Interest for the first year = Rs (46875 × 4 × 1) / 100

= Rs 46875 / 25

= Rs 1875

Therefore, interest for the first year is Rs 1875

**(ii) Amount at the end of first year**

= Rs 46875 + Rs 1875

= Rs 48750

Principal for the second year = Rs 48750

Interest for the second year = Rs (48750 × 4 × 1) / 100

= Rs 48750 / 25

= Rs 1950

Amount at the end of second year = Rs 48750 + Rs 1950

= Rs 50700

Therefore, the amount at the end of second year is Rs 50700

**(iii) Principal for the third year = Rs 50700**

Interest for the third year = Rs (50700 × 4 × 1) / 100

We get,

= Rs 507 × 4

= Rs 2028

Therefore, the interest for the third year is Rs 2028

**Question 5. Calculate the compound interest for the second year on ₹6000 invested for 3 years at 10% p.a. Also find the sum due at the end of third year.**

**Answer:**

Principal for the first year = Rs 6000

Rate of interest = 10% p.a.

Interest for the first year = Rs (6000 × 10 × 1) / 100

= Rs 600

Amount at the end of first year = Rs 6000 + Rs 600

= Rs 6600

Principal for the second year = Rs 6600

Interest for the second year = Rs (6600 × 10 × 1) / 100

= Rs 660

Amount at the end of second year = Rs 6600 + Rs 660

= Rs 7260

Compound interest for the second year = Final amount – (original) Principal

= Rs 7260 – Rs 6000

= Rs 1260

Principal for the third year = Rs 7260

Interest for the third year = Rs (7260 × 10 × 1) / 100

= Rs 726

Amount at the end of third year = Rs 7260 + Rs 726

= Rs 7986

**Question 6. Calculate the amount and the compound interest on ₹5000 in 2 years when the rate of interest for successive years is 6% and 8% respectively.**

**Answer:**

Principal for the first year = Rs 5000

Rate of interest = 6% p.a.

Interest for the first year = Rs (5000 × 6 × 1) / 100

= Rs 50 × 6

= Rs 300

Amount at the end of first year = Rs 5000 + Rs 300

= Rs 5300

Principal for the second year = Rs 5300

Rate of interest = 8% p.a.

Interest for the second year = Rs (5300 × 8 × 1) / 100

= Rs 53 × 8

We get,

= Rs 424

Amount for the second year = Rs 5300 + Rs 424

= Rs 5724

Compound interest for two years = Final amount – (original) Principal

= Rs 5724 – Rs 5000

= Rs 724

**Question 7. Calculate the difference between the compound interest and the simple interest on ₹20000 in 2 years at 8% per annum**

**Answer:**

Principal (P) = Rs 20000

Rate (R) = 8% p.a.

Period (T) = 2 years

Simple interest (S.I.) = PRT / 100

= Rs (20000 × 8 × 2) / 100

= Rs 3200

Amount on compound interest

A = P {1 + (R / 100)}^{n}

= RS 20000 {1 + (8 / 100)}^{2}

= Rs 20000 × (27 / 25) × (27 / 25)

= Rs 32 × 729

= Rs 23328

Compound interest = Final amount – (original) Principal

= Rs 23328 – Rs 20000

We get,

= Rs 3328

Difference in compound interest – simple interest

= Rs 3328 – Rs 3200

= Rs 128

— : End of ML Aggarwal Simple and Compound Interest Exe-8.2 Class 8 ICSE Maths Solutions :–

Return to **– ML Aggarwal Maths Solutions for ICSE Class -8**

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