Motion in One Dimension Class-9 Exe-2C Long Ans Concise Physics ICSE Selina Solutions

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Motion in One Dimension Class-9 Exe-2C Long Ans Concise Physics ICSE Selina Solutions. The long Ans type questions on equations of motion. Visit official Website CISCE for detail information about ICSE Board Class-9.

Motion in One Dimension Class-9 Exe-2C Long Ans Concise Physics ICSE Selina Solutions

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Motion in One Dimension Class-9 Exe-2C Long Ans Concise Physics ICSE Selina Solutions

Board ICSE
Class 9
Subject Physics
Writer / Publication Concise Selina Publishers
Chapter-2 Motion in One Dimension
Exe – 2 C Equations of Motion
Topics Solution of Exe-2(C) Long Answer Type
Academic Session 2025-2026

Equations of Motion

Motion in One Dimension Class-9 Exe-2C Long Ans Concise Physics ICSE Selina Solutions

Page 60

Que-1: Derive the following equations for uniformly accelerated motion:

(i) v = u + at
(ii) s = ut + (1/2) at2
(iii) v2 = u2 + 2aS
where the symbols have their usual meanings.

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Ans: Derivation of equations of motion

First equation of motion:
Consider a particle moving along a straight line with uniform acceleration ‘a’. At t = 0, let the particle be at A and u be its initial velocity, and at t = t, let v be its final velocity.

first law of motion

Acceleration = Change in velocity/Time a = (– u)/t at = v – uv = u+ at … First equation of motion.

Second equation of motion:

Average velocity = Total distance traveled/Total time takenAverage velocity = s/t …(1)
Average velocity can be written as (u+v)/2 Average velocity = (u+v)/2 …(2)
From equations (1) and (2) s/t = (u+v)/2 …(3)
The first equation of motion is v = u + at.
Substituting the value of v in equation (3), we get
s/t = (at)/2 s = (2att/2 = 2ut at2/2 = 2ut/2 + at2/2
s = ut + (1/2) at2 …Second equation of motion.

Third equation of motion: 

The first equation of motion is v = u + at. v – u = at … (1)
Average velocity = s/t …(2)
Average velocity =(u+v)/2 …(3)
From equation (2) and equation (3) we get,
(u v)/2 = s/t …(4)
Multiplying eq (1) and eq (4) we get,
(v – u)(v + u) = at × (2s/t) (v – u)(v + u) = 2as
[We make the use of the identity a2 – b2 = (a + b) (a – b)]
v2 – u2 = 2as …Third equation of motion.

—  : End of Motion in One Dimension Class-9 Exe-2C Long Ans Concise Physics ICSE Selina Solutions :–

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