Number System Class 6 RS Aggarwal Exe-1F MCQs Goyal Brothers Prakashan ICSE Foundation Maths Solutions. We provide step by step Solutions of lesson-1 Number System for ICSE Class-6 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan . Visit official Website CISCE for detail information about ICSE Board Class-6 Mathematics.
Number System Class 6 RS Aggarwal Exe-1F MCQs Goyal Brothers Prakashan ICSE Foundation Maths Solutions
Board | ICSE |
Publications | Goyal brothers Prakashan |
Subject | Maths |
Class | 6th |
Ch-1 | Number System |
Writer | RS Aggrawal |
Book Name | Foundation |
Topics | Solution of Exe-1F MCQs |
Academic Session | 2023 – 2024 |
Solution of Number System Exe-1F MCQs
Ch-1 Class 6 RS Aggarwal Goyal Brothers Prakashan ICSE Foundation Maths Solutions
Page- 29
Exercise- 1F
Multiple Choice Questions :
Que-1: The place value of 7 in the numeral 25,79,206 is
(a) 7 (b) 79,206 (c) 70,000 (d) 257
Ans- (c) 70,000
Reason : The number 25,79,206 can be broken down into thousands, hundreds, tens, and ones places, as follows:
2 (millions place)
5 (hundred thousands place)
7 (ten thousands place)
9 (thousands place)
2 (hundreds place)
0 (tens place)
6 (ones place)
So, the place value of 7 in the numeral 25,79,206 is in the ten thousands place.
Que-2: The face value of 4 in the numeral 36,43,908 is
(a) 40,0000 (b) 4 (c) 364 (d) 43,908
Ans- (b) 4
Reason : In the numeral 36,43,908, the digit 4 is in the ten thousands place.
So, the face value of 4 in the numeral 36,43,908 is simply 4.
Que-3: The difference between the place-value and the face-value of 6 in the numeral 32,53,619 is
(a) 19 (b) 594 (c) 613 (d) 600
Ans- (b) 594
Reason : Place value: 6 is in the hundreds place.
Face value: The digit 6 itself.
Now, we’ll calculate the difference:
Place value of 6 = 6 * 100 = 600
Face value of 6 = 6
Difference = Place value – Face value
Difference = 600 – 6
Difference = 594
So, the difference between the place value and the face value of 6 in the numeral 32,53,619 is 594.
Que-4: The smallest counting number is
(a) 0 (b) 1 (c) 10 (d) 11
Ans- (b) 1
Reason : The smallest counting number, also known as the smallest positive integer, is 1. This is because counting typically starts from 1 and progresses onward, with each subsequent number increasing by 1.
Que-5: The whole number whose successor is 53,100 is
(a) 53,101 (b) 53,099 (c) 53,000 (d) none of these
Ans- (b) 53,099
Reason : To find the whole number whose successor is 53,100, we simply subtract 1 from 53,100.
53,100 − 1 = 53,099
So, the whole number whose successor is 53,100 is 53,099.
Que-6: The difference between the largest number of 3-digits and the smallest number of 3-digits formed by the digits 3,0 and 8 is
(a) 495 (b) 765 (c) 522 (d) 450
Ans- (c) 522
Reason : The largest number formed: 830
The smallest number formed: 308
Now, let’s calculate the difference:
Difference = Largest number−Smallest number
Difference = 830 − 308
Difference=522
So, the difference between the largest number of 3 digits and the smallest number of 3 digits formed by the digits 3, 0, and 8 is 522.
Que-7: How many 7 digit number are there in all ?
(a) 90,00,000 (b) 90,00,001 (c) 89,99,999 (d) 10,00,000
Ans- (a) 90,00,000
Reason : A 7-digit number can start from 10,00,000 and go up to 99,99,999.
So, the total count of 7-digit numbers is the difference between the highest and lowest 7-digit numbers plus 1 (to include both extremes):
99,99,999 − 1,000,000 + 1 = 99,99,999 − 10,00,000 + 1 = 90,00,000
So, there are 90,00,000 seven-digit numbers in total.
Que-8: What comes just before 10,00,000?
(a) 99,999 (b) 99,99,999 (c) 9,99,999 (d) none of these
Ans- (c) 9,99,999
Reason : 10,00,000 − 1 = 9,99,999
So, what comes just before 10,00,000 is 9,99,999.
Que-9: The largest number of 4 digits which is exactly divisible by 25 is
(a) 1,000 (b) 10,000 (c) 9,950 (d) 9,975
Ans- (d) 9,975
Reason : Dividing 9,999 by 25:
9999 ÷ 25 = 399.96
So, the largest multiple of 25 that is less than or equal to 9,999 is 25 × 399 = 9,975.
Therefore, the largest number of 4 digits which is exactly divisible by 25 is 9,975.
Que-10: The number which when divided by 23 gives 17 as quotient and 19 as remainder, is
(a) 413 (b) 412 (c) 411 (d) none of these
Ans- (d) none of these
Reason : Number = (Divisor × Quotient) + Remainder
Substituting the given values:
Number = (23×17) + 19
Number=391+19
Number=410
So, the correct option is (d) none of these, as the correct answer is 410.
Que-11: The sum of the successor and the predecessor of a number is 1326. The number is
(a) 663 (b) 662 (c) 664 (d) 661
Ans- (a) 663
Reason : According to the given condition, the sum of the successor (one more than the number) and the predecessor (one less than the number) of the number x is 1326.
So, we can write the equation as:
(x+1)+(x−1) = 1326
Simplify the equation:
2x = 1326
x = 1326/2
x = 663
Therefore, the number is 663.
— : end of Number System Class 6 RS Aggarwal Exe-1F MCQs Goyal Brothers Prakashan ICSE Foundation Maths :–
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