Number System Class 6 RS Aggarwal Exe-1F MCQs Goyal Brothers Prakashan ICSE Foundation Maths Solutions. We provide step by step Solutions of lesson-1 Number System for ICSE Class-6 **Foundation RS Aggarwal Mathematics** of Goyal Brothers Prakashan . Visit official Website **CISCE** for detail information about ICSE Board Class-6 Mathematics.

## Number System Class 6 RS Aggarwal Exe-1F MCQs Goyal Brothers Prakashan ICSE Foundation Maths Solutions

Board | ICSE |

Publications | Goyal brothers Prakashan |

Subject | Maths |

Class | 6th |

Ch-1 | Number System |

Writer | RS Aggrawal |

Book Name | Foundation |

Topics | Solution of Exe-1F MCQs |

Academic Session | 2023 – 2024 |

### Solution of Number System Exe-1F MCQs

Ch-1 Class 6 RS Aggarwal Goyal Brothers Prakashan ICSE Foundation Maths Solutions

**Page- 29**

**Exercise- 1F**

**Multiple Choice Questions :**

**Que-1: The place value of 7 in the numeral 25,79,206 is**

**(a) 7 (b) 79,206 (c) 70,000 (d) 257**

**Ans- **(c) 70,000

**Reason : **The number 25,79,206 can be broken down into thousands, hundreds, tens, and ones places, as follows:

2 (millions place)

5 (hundred thousands place)

7 (ten thousands place)

9 (thousands place)

2 (hundreds place)

0 (tens place)

6 (ones place)

So, the place value of 7 in the numeral 25,79,206 is in the ten thousands place.

**Que-2: The face value of 4 in the numeral 36,43,908 is**

**(a) 40,0000 (b) 4 (c) 364 (d) 43,908**

**Ans- **(b) 4

**Reason : **In the numeral 36,43,908, the digit 4 is in the ten thousands place.

So, the face value of 4 in the numeral 36,43,908 is simply 4.

**Que-3: The difference between the place-value and the face-value of 6 in the numeral 32,53,619 is**

**(a) 19 (b) 594 (c) 613 (d) 600**

**Ans- **(b) 594

**Reason : **Place value: 6 is in the hundreds place.

Face value: The digit 6 itself.

Now, we’ll calculate the difference:

Place value of 6 = 6 * 100 = 600

Face value of 6 = 6

Difference = Place value – Face value

Difference = 600 – 6

Difference = 594

So, the difference between the place value and the face value of 6 in the numeral 32,53,619 is 594.

**Que-4: The smallest counting number is **

**(a) 0 (b) 1 (c) 10 (d) 11**

**Ans- **(b) 1

**Reason : **The smallest counting number, also known as the smallest positive integer, is 1. This is because counting typically starts from 1 and progresses onward, with each subsequent number increasing by 1.

**Que-5: The whole number whose successor is 53,100 is **

**(a) 53,101 (b) 53,099 (c) 53,000 (d) none of these**

**Ans- **(b) 53,099

**Reason : **To find the whole number whose successor is 53,100, we simply subtract 1 from 53,100.

53,100 − 1 = 53,099

So, the whole number whose successor is 53,100 is 53,099.

**Que-6: The difference between the largest number of 3-digits and the smallest number of 3-digits formed by the digits 3,0 and 8 is**

**(a) 495 (b) 765 (c) 522 (d) 450**

**Ans- **(c) 522

**Reason : **The largest number formed: 830

The smallest number formed: 308

Now, let’s calculate the difference:

Difference = Largest number−Smallest number

Difference = 830 − 308

Difference=522

So, the difference between the largest number of 3 digits and the smallest number of 3 digits formed by the digits 3, 0, and 8 is 522.

**Que-7: How many 7 digit number are there in all ?**

**(a) 90,00,000 (b) 90,00,001 (c) 89,99,999 (d) 10,00,000**

**Ans- **(a) 90,00,000

**Reason : **A 7-digit number can start from 10,00,000 and go up to 99,99,999.

So, the total count of 7-digit numbers is the difference between the highest and lowest 7-digit numbers plus 1 (to include both extremes):

99,99,999 − 1,000,000 + 1 = 99,99,999 − 10,00,000 + 1 = 90,00,000

So, there are 90,00,000 seven-digit numbers in total.

**Que-8: What comes just before 10,00,000?**

**(a) 99,999 (b) 99,99,999 (c) 9,99,999 (d) none of these**

**Ans- **(c) 9,99,999

**Reason : **10,00,000 − 1 = 9,99,999

So, what comes just before 10,00,000 is 9,99,999.

**Que-9: The largest number of 4 digits which is exactly divisible by 25 is **

**(a) 1,000 (b) 10,000 (c) 9,950 (d) 9,975**

**Ans- **(d) 9,975

**Reason : **Dividing 9,999 by 25:

9999 ÷ 25 = 399.96

So, the largest multiple of 25 that is less than or equal to 9,999 is 25 × 399 = 9,975.

Therefore, the largest number of 4 digits which is exactly divisible by 25 is 9,975.

**Que-10: The number which when divided by 23 gives 17 as quotient and 19 as remainder, is**

**(a) 413 (b) 412 (c) 411 (d) none of these**

**Ans- **(d) none of these

**Reason : **Number = (Divisor × Quotient) + Remainder

Substituting the given values:

Number = (23×17) + 19

Number=391+19

Number=410

So, the correct option is (d) none of these, as the correct answer is 410.

**Que-11: The sum of the successor and the predecessor of a number is 1326. The number is**

**(a) 663 (b) 662 (c) 664 (d) 661**

**Ans- **(a) 663

**Reason : **According to the given condition, the sum of the successor (one more than the number) and the predecessor (one less than the number) of the number x is 1326.

So, we can write the equation as:

(x+1)+(x−1) = 1326

Simplify the equation:

2x = 1326

x = 1326/2

x = 663

Therefore, the number is 663.

**— : end of Number System Class 6 RS Aggarwal Exe-1F MCQs Goyal Brothers Prakashan ICSE Foundation Maths :–**

**Return to- ICSE Class -7 RS Aggarwal Goyal Brothers Math Solutions**

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