Numericals on Simple Machines Class 6 Concise Physics ICSE Solutions Ch-4. In this article you would learn how to solve Numericals on Simple Machines . Visit official Website  CISCE  for detail information about ICSE Board Class-6.

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Numericals on Simple Machines Class 6 Concise Physics ICSE Solutions

                                  Numericals on Simple Machines

Que-1: In a machine an effort of 10 kgf is applied to lift a load of 100 kgf. What is its mechanical advantage?

Ans- Given:
Load = 100 kgf
Effort = 10 kgf
Mechanical Advantage (MA) is given by:
MA=Load/Effort
MA=100/10=10
So, Mechanical Advantage = 10

Que-2: The mechanical advantage of a machine is 5. How much load it can exert for the effort of 2 kgf?

Ans- Given:
MA = 5
Effort = 2 kgf
Mechanical Advantage (MA) formula:
M.𝐴 = Load/Effort
Load=MA×Effort
Load=5×2 kgf=10kgf
Thus, load can exert 10 kgf force for the effort of 2 kgf.

Que-3: The mechanical advantage of a machine is 2. It is used to raise a load of 15 kgf. What effort is needed?

Ans- Given:
M.A = 2
Load = 15 kgf
𝑀.𝐴=Load/Effort
Effort=Load/MA
Effort=15 kgf/2=7.5kgf
To raise a load of 15 kgf, an effort of 7.5 kgf is needed.

Que-4: A lever of length 100 cm has effort of 15 kgf at a distance of 40 cm from the fulcrum at one end. What load can be applied at its other end?

Ans- Use the principle of moments for a lever:
Effort×Effort arm=Load×Load arm
Given:
Total length of lever = 100 cm
Effort = 15 kgf
Effort arm = 40 cm (from fulcrum)
Since the fulcrum is at one end,
Load arm = 100 cm
Now,
15×40=Load×100
600=100×Load
Load=600/100=6 kgf
A load of 6 kgf should be applied for the effort of 15 kgf.

Que-5: In a lever, fulcrum is at one end at a distance of 30 cm from the load and effort is at the other end at a distance of 90 cm from the load. Find :
(i) the length of load arm,
(ii) the length of effort arm, and
(iii) the mechanical advantage of the lever.

Ans- Given,
Distance of fulcrum from the load = 30 cm
Distance between load and effort = 90 cm

(i)Length of load arm = Distance of fulcrum from the load = 30 cm
(ii)Length of effort arm = Distance between load and effort + Length of load arm = 90 + 30 = 120 cm
(iii)Mechanical advantage of a lever is : Mechanical Advantage= Effort Arm/Load Arm = 120 cm/30 cm =4

— : End of Numericals on Simple Machines Class 6 Concise Physics ICSE Solutions :–

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