Only 1% of ICSE Students Can Solve These Puzzles !

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Only 1% of ICSE Students Can Solve These Puzzles ! Test your brain with challenging math riddles and logic questions designed for Class 6–10 students. Improve problem-solving skills, boost IQ, and have fun learning. Try now and see if you’re among the top 1% smart students!

Only 1% of ICSE Students Can Solve These Puzzles !

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🧠 Only 1% of ICSE Students Can Solve These Puzzles !

Most students think they’re good at logic… until they try these.

Instructions:
– Don’t rush
– Solve first, then check answers
– Write proper steps

🔥 Puzzle 1: The Misleading Average

The average of 5 consecutive numbers is 18. Find the largest number.

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Puzzle 1: The Misleading Average

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Ans-

Puzzle 1: The Misleading Average

Let numbers be: x−2, x−1, x, x+1, x+2

Average = 18 ⇒ x = 18

Numbers: 16, 17, 18, 19, 20

Largest number = 20

“Ohh… that was simple ! 😁”

⚡ Puzzle 2: The Speed Trap

A student goes to school at 30 km/h and returns at 60 km/h. Find average speed.

⚡ Puzzle 2: The Speed Trap

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Ans-

When a student travels the same distance at two different speeds :

Average speed = (2 × speed1 × speed2 )/(speed1 + speed2)

⚡ Puzzle 2: The Speed Trap

 

Now apply:

  • speed 1 = 30km/h
  • speed 2 = 60km/h

Average speed = 2×30×60/(30+60) = 40 km/h

🧩 Puzzle 3: Sum Shortcut

Find: 1 + 2 + 3 + … + 100

🧩 Puzzle 3: Sum Shortcut

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Ans-

🧩 Puzzle 3: Sum Shortcut
Pair the numbers from start and end:

  • (1 + 100) = 101
  • (2 + 99) = 101
  • (3 + 98) = 101

👉 Total 50 pairs, and each pair = 101

So,
Sum = 50 × 101 = 5050

🧠 Puzzle 4: Probability Challenge

A bag has 3 red and 2 blue balls. Two are drawn without replacement. Find probability both are red.

Puzzle 4: Probability Challenge

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Ans-

Puzzle 4: Probability Challenge

Total balls = 3 red + 2 blue = 5

👉 Probability that both drawn are red (without replacement):

First red = 3/5
​Second red (now 2 red left out of 4) = 2/4

Multiply: 3/5×2/4 = 6/20 = 3/10

🔍 Puzzle 5: Logical Reasoning

All roses are flowers. Some flowers fade quickly. What is definitely true?
A) All flowers are roses

B) Some roses fade quickly
C) Some flowers fade quickly
D) No roses fade quickly

Puzzle 5: Logical Reasoning

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Ans-

Puzzle 5: Logical Reasoning

💡 Trick Explanation:

  • All roses are flowers
  • Some flowers fade quickly

👉 This means:

  1. Roses are a subset of flowers
  2. And some flowers (not necessarily roses) fade quickly

We cannot be sure that roses are included in those fading flowers.
∴ Correct answer : c) Some flowers fade quickly ​

🔢 Puzzle 6: Algebra Trick

If x + 1/x = 5, find x² + 1/x²

Puzzle 6: Algebra Trick

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Ans-

Puzzle 6: Algebra Trick

💡 Trick Method:

Given: x + 1/x = 5

Square both sides:

(x + 1/x)² = 5²

So,

25 = x² + 1/x² + 2

x² + 1/x² = 25-2 = 23

⚙️ Puzzle 7: Work & Time

A can do work in 10 days, B in 15 days. Time together?

Puzzle 7: Work & Time

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Ans-

Puzzle 7: Work & Time

💡 Trick Method:

A’s 1 day work = 1/10
​B’s 1 day work = 1/15

👉 Together (add work rates):

1/10 + 1/15 = (3+2)/30 = 5/30 = 1/6

So, they complete 1/6 work in 1 day ​

∴ They will complete the whole work in 6 days.

🧮 Puzzle 8: Number System

Find remainder when 7¹⁰⁰ is divided by 6.

Puzzle 8: Number System

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Ans-

Puzzle 8: Number System

💡 Trick Method:
7 can be written as :

7 = 6 + 1

when we divide 7 by 6 , remainder is 1

So,

  • 7÷6 leaves remainder 1
  • That means 7 ≡ 1 (mod 6)

Now instead of 7¹⁰⁰ , think :

7¹⁰⁰ = (6+1)¹⁰⁰,

every time you multiply , it will still leave remainder 1

Example :

  • 7² = 49 , remainder when divided by 6 =1
  • 7³ = 343 , remainder =1

∴ 7¹⁰⁰  remainder will also be 1

😵 Puzzle 9: Arrangement

In how many ways can letters of MATHS be arranged?

Puzzle 9: Arrangement

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Ans-

Puzzle 9: Arrangement

💡 Trick Explanation:

The word MATHS has 5 letters and all are different,
so the number of ways to arrange them is given by factorial of 5,
i.e. 5! = 5×4×3×2×1 = 120. ​

💥 Puzzle 10: Final Boss

A number leaves remainder 1 when divided by 7, 8, and 9. Find smallest number.

Puzzle 10: Final Boss

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Ans-

Puzzle 10: Final Boss

A number that leaves remainder 1 when divided by 7, 8, and 9 means:

👉 Number = LCM(7, 8, 9) + 1

LCM of 7, 8, 9 = 504

So,

Number = 504+1 = 505​

🏆 Final Score

9–10 → ICSE Topper Level 🧠🔥

6–8 → Strong Concepts 💪

3–5 → Needs Practice

0–2 → Revise Basics 😅

–: End of Only 1% of ICSE Students Can Solve These Puzzles ! :–

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