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Physics and Mathematics Obj-2 HC Verma Solutions Ch-2 Vol-1

Physics and Mathematics Obj-2 (MCQ-2) HC Verma Solutions Ch-2 Vol-1 Concept of Physics for Class-11. Solution of Objective -2 (MCQ-2) Questions of Ch-2 Physics and Mathematics (Concept of Physics) .Visit official Website CISCE for detail information about ISC Board Class-11 Physics.

Physics and Mathematics Obj-2 (MCQ-2) HC Verma Solutions Vol-1 Ch-2

Board ISC and other board
Publications Bharti Bhawan Publishers
Chapter-2 Physics and Mathematics
Class 11
Vol  1st
writer H C Verma
Book Name Concept of Physics
Topics Solution of Objective-2 (MCQ-2) Questions
Page-Number 28

-: Select Topics :-

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Que for Short Ans

Objective-I

Objective-II

Exercise


Physics and Mathematics Obj-2 (MCQ-2) HC Verma Solutions Vol-1 Ch-2

(Page-28)

Question 1:

A situation may be described by using different sets coordinate axes having different orientation. Which the following do not depended on the orientation of the axis?
(a) the value of a scalar
(b) component of a vector
(c) a vector
(d) the magnitude of a vector.

Answer 1:

The options (a),  (c) and (d) are correct

Explanation:

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The value of a scalar, a vector and the magnitude of a vector do not depend on a given set of coordinate axes with different orientation. However, components of a vector depend on the orientation of the axes.

Question-2

Physics and Mathematics Ch-2 Obj-2 HC Verma Solutions Ans 2

(c) C is always equal to A + B

(d) C is never equal to A + B.

Answer-2

The option (b), is correct

Explanation :

Given :   C    =   𝐴     + 

Here, the magnitude of the resultant vector may or may not be equal to or less than the magnitudes of  A ⃗  and   or the sum of the magnitudes of both the vectors if the two vectors are in opposite directions.

Question-3

Let the angle between two nonzero vectors  𝐴   and  B    be 120° and its resultant be C

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(a) C must be equal to |A-B|

(b) C must be less than |A-B|

(c) C must be greater than |A-B|

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(d) C may be equal to |A-B|

Answer-3

The option (c), is correct

Explanation :

Here, we have three vector A, B and C.

Physics and Mathematics Ch-2 Obj-2 HC Verma Solutions Ans 3

Since cosine is negative in the second quadrant so must be greater than |A-B|

Question-4

The x-component of the resultant of several vectors
(a) is equal to the sum of the x-components of the vectors of the vectors
(b) may be smaller than the sum of the magnitudes of the vectors
(c) may be greater than the sum of the magnitudes of the vectors
(d) may be equal to the sum of the magnitudes of the vectors

Answer-4

The options (a) , (b) and (d), are correct

Explanation :

The x-component of the resultant of several vectors cannot be greater than the sum of the magnitudes of the vectors.

Question-5

The magnitude of the vector product of two vectors | 𝐴| and | | may be

(a) greater than AB
(b) equal to AB
(c) less than AB
(d) equal to zero.

Answer-5

The options (b) , (c) and (d), are correct

Explanation :

The magnitude of the vector product of two vectors| 𝐴| and | |  may be less than or equal to AB, or equal to zero, but cannot be greater than AB.

—: End of  Physics and Mathematics Obj-2 (MCQ-2) Vol-1 Ch-2 HC Verma Solutions  :–


Return to — HC Verma Solutions Vol-1 Concept of Physics

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