Playing with Numbers Class 6 RS Aggarwal Exe-6A Goyal Brothers ICSE Maths Solutions

Playing with Numbers Class 6 RS Aggarwal Exe-6A Goyal Brothers Prakashan ICSE Foundation Mathematics Solutions. In this article you will learn Simplification using BODMAS . Visit official Website CISCE for detail information about ICSE Board Class-6 Mathematics.

Playing with Numbers Class 6 RS Aggarwal Exe-6A Goyal Brothers ICSE Maths Solutions

Playing with Numbers Class 6 RS Aggarwal Exe-6A Goyal Brothers ICSE Maths Solutions

Board ICSE
Publications Goyal brothers Prakashan
Subject Maths
Class 6th
Ch-6 Playing with Numbers
Writer RS Aggrawal
Book Name Foundation
Topics Solution of Exe-6A
Academic Session 2023 – 2024

Simplification using BODMAS

BODMAS stands for

  • Brackets (parts of a calculation inside brackets always come first).

  • Orders (numbers involving powers or square roots).

  • Division.

  • Multiplication.

  • Addition.

  • Subtraction.

How to Apply BODMAS?

first simplify the brackets from the inside to the outside ( ), then evaluate the exponents or roots, simplify multiplication and division, and finally perform addition and subtraction operations while moving from left to right.

Exercise-6A (Simplification Using BODMAS)

Playing with Numbers Class 6 RS Aggarwal Goyal Brothers Prakashan ICSE Foundation Mathematics Solutions

Page- 110      Simplify

Que-1: 24 – 20 ÷ 5 x 2

Solution- According to BODMAS first, we do the division then multiplication then subtraction.
24 – 20 ÷ 5 × 2
= 24 – 4 × 2
= 24 – 8 = 16 Ans.

Que-2: 19 + 12 ÷ 6 – 2 x 3

Solution-  According to BODMAS first, we do the division then multiplication then addition then subtraction,
19 + 12 ÷ 6 – 2 × 3
= 19 + 2 – 2 × 3
= 19 + 2 – 6
⇒ 21 – 6 = 15 Ans.

Que-3: 21 – 12 ÷ 4 – 3 x (-7)

Solution- 21 – 3 – 3 x (-7)
= 21 – 3 + 21
= 21 + 18 = 39 Ans.

Que-4: 23 + 18 ÷ 6 + 3 x (-4)

Solution- 23 + 3 + 3 x (-4)
= 23 + 3 – 12
= 26 – 12 = 14 Ans.

Que-5: 30 – {8 ÷ (2 x 3 – 4)}

Solution- 30 – {8 ÷ (6 – 4)}
= 30 – {8 ÷ 2}
= 30 – 4 = 26 Ans.

Que-6: 9 – {5 x 3 + 12 x 16 ÷ (-8)}

Solution- 9 – {5 x 3 + 12 x (-2)}
= 9 – {15 – 24}
= 9 – (-9) = 18 Ans.

Que-7: 16 – {9 – 24 ÷ (8 + 6 x 2 – 16)}

Solution- 16 – {9 – 24 ÷ (8 + 12 – 16)}
= 16 – {9 – 24 ÷ 4}
= 16 – {9 – 6}
⇒ 16 – 3 = 13 Ans.

Que-8: 12 – [13 – {9 + 10 ÷ (7 – 2)}]

Solution- 12 – [13 – {9 + 10 ÷ 5}]
= 12 – [13 – {9 + 2}]
= 12 – [13 – 11]
⇒ 12 – 2 = 10 Ans. 

Que-9: 4 – [16 – {6 + 12 ÷ (9 – 6)}]

Solution- 4 – [16 – {6 + 12 ÷ 3}]
= 4 – [16 – {6 + 4}]
= 4 – [16 – 10]
⇒ 4 – 6 = -2 Ans.

Que-10: 28 – [15 – {8 + 20 ÷ (7 – 8 – 6)}]

Solution- 28 – [15 – {8 + 20 ÷ (7 – 2)}]
= 28 – [15 – {8 + 20 ÷ 5}]
= 28 – [15 – {8 + 4}]
⇒ 28 – [15 – 12]
⇒ 28 – 3 = 25 Ans.

— : end of Playing with Numbers Class 6 RS Aggarwal Exe-6A Goyal Brothers ICSE Mathematics Solutions :–

Return to :- ICSE Class -6 RS Aggarwal Goyal Brothers Math Solutions

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