Short Ans Questions Practical Work Class-10 Concise Chemistry Selina Solutions Chapter-13. We Provide Step by Step Answer of Short Ans Questions of Exercise-13 for ICSE Class-10. The given Solutions is according to the Latest editions. Visit the official Website CISCE for detail information about the ICSE Board Class-10.

Short Ans Questions Practical Work Class-10 Concise Chemistry Selina Solutions Chapter-13

Board	ICSE
Book / Publication	Concise / Selina
Subject	Chemistry
Class	10th
Writer	Dr SP Singh
Chapter-13	Practical Work
Topics	Short Ans
Edition	2025-2026

Solutions of Short Ans Questions on Practical Work

Page-238

Que-1: Name the anion present in each of the following compounds:

(a) Compound A when warmed with concentrated sulphuric acid gives a gas which fumes in moist air and which gives dense white fumes with ammonia.
(b) When barium chloride solution is added to a solution of compound B, a white precipitate insoluble in dilute hydrochloric acid is formed.
(c) The action of heat on the insoluble compound C produces a gas which turns lime water turbid.
(d) Compound D when warmed with dilute sulphuric acid gives a gas which turns acidified dichromate solution green.

Ans:
(a) Cl^–
(b) SO₄^2-
(c) CO₃^2-
(d) SO₃^2-

Que-2: A given white crystalline salt was tested as follows:

(a) It dissolved in water and the resulting solution of the salt turned blue litmus red.
(b) Addition of barium chloride solution into this solution gave a white precipitate.
(c) A flame test on the salt gave a persistent golden-yellow colourisation.
What conclusions can be drawn for each observation?

Ans:
(a) Since the salt solution turned blue litmus red hence the salt may be an acid.
(b) Since addition of barium chloride into the solution of salt gave white precipitate so the salt may contain SO₄^2-, SO₃^2-, CO₃^2– anion.
(c) The flame test of the salt gives persistent golden yellow colourisation which suggests presence of Na⁺ ion.

Que-3:

(a) Sodium hydroxide solution is added to solution A. A white precipitate is formed which is insoluble in excess sodium hydroxide solution. What is metal ion present in solution A?
(b) When ammonium hydroxide solution is added to solution B, a pale blue precipitate is formed. This pale blue precipitate dissolves in excess ammonium hydroxide giving an inky blue solution. Name the cation present in solution B?
(c) When an ammonium salt is warmed with sodium hydroxide solution, ammonia gas is evolved. State three ways in which you could identify this gas.

Ans:
(a) Ca²⁺
(b) Cu⁺ 
(c) The three ways are:
Ammonia gas turns moist red litmus blue.
If a rod dipped in concentrated HCl is brought near the gas, dense white fumes of NH₄Cl are formed.
The gas turns colourless Nessler’s reagent i.e. K₂HgI₄ brown.

Que-4:The questions (i) to (v) refer to the following salt solutions listed A to F

A. Copper Nitrate
B. Iron (II) Sulphate
C. Iron (III) chloride
D. Lead Nitrate
E. Magnesium sulphate
F. Zinc chloride
(I) Which two solutions will give a white precipitate when treated with dilute hydrochloric acid followed by barium chloride solution?
(II) Which two solutions will give a white precipitate when treated with dilute nitric acid followed by sliver nitrate solution?
(III) Which solution will give white precipitate, when either dilute hydrochloric acid or dilute sulphuric acid is added to it?
(IV) Which solution becomes a deep/inky blue colour when excess of ammonium hydroxide is added to it?
(V) Which solution gives a white precipitate with excess of ammonium hydroxide solution?

Ans:
(I) Iron (II) Sulphate and Magnesium sulphate
(II) Iron (III) chloride and Zinc Chloride
(III) Lead nitrate
(IV) Copper nitrate.
(V) Lead nitrate.

Que-5: Salts A, B, C, D and E undergo reactions (i) to (v) respectively. Identify the anion present in these salts on the basis of these reactions.

(a) When silver nitrate solution is added to a solution of A, a white precipitate, insoluble in dilute nitric acid, is formed.
(b) Addition of dilute hydrochloric acid to B produces a gas which turns lead acetate black paper.
(c) When a freshly prepared solution of ferrous sulphate is added to a solution of C and concentrated sulphuric acid is gently poured from the side of the test-tube, a brown ring is formed.
(d) When dilute sulphuric acid is added to D, a gas is produced which turns acidified potassium dichromate solution from orange to green.
(e) Addition of dilute hydrochloric acid to E produces effervescence. The gas produced turns lime water milky but does not affect acidified potassium dichromate solution.

Ans:

Salt	Anion
A	Cl–
B	S2-
C	NO3–
D	SO32-
E	CO32-

Que-6: State your observation when:

(a)Lead nitrate solution and sodium chloride solution are mixed.
(b) solution of zinc chloride, zinc nitrate solution and zinc sulphate solutions are added individually to
(i) Barium chloride solution
(ii) Lead nitrate solution.
(c) Decomposition of bicarbonates by dil. H₂SO₄
2NaHCO₃ + H₂SO₄ → NaSO₄ + 2H₂O + 2CO₂
2KHCO₃ + H₂SO₄ → K₂SO₄ + 2H₂O + 2CO₂
(d) Zinc carbonate is heated strongly.
(e) a piece of moist blue litmus paper is introduced in a jar of chlorine.
(f) paper soaked in potassium permanganate solution — is introduced in each case into a jar of sulphur dioxide.
(g) When moist starch iodide paper is introduced into chlorine gas.

Ans:
(a) Lead chloride as precipitate and sodium nitrite are formed.
(b)

	chloride of zinc	nitrate of zinc	sulphate of zinc
Barium chloride	No –	Nil	White ppt. is obtained
Lead nitrate	reaction absent	No reaction	reaction not found

(c) Dilute sulphuric acid liberates carbon dioxide from metallic carbonates and bicarbonates. Carbon dioxide when bubbled into a test tube containing calcium hydroxide solution turns it milky.
(d) When zinc carbonate is strongly heated, the light amorphous white solid, changes to pale yellow colour.
ZnCO₃  → ZnO + CO₂
(e) Moist blue litmus turns red and then may eventually get bleached.
(f) Sulphur dioxide turns potassium permanganate from pink to clear colourless.
2KMnO₄ + 2H₂O + 5SO₂ ⟶ K₂SO₄ + 2MnSO₄ + 2H₂SO₄
(g) Chlorine gas turns moist starch iodide paper blue black.
Cl₂ + 2KI ⟶ 2KCl + I₂
[Starch + I₂ ⟶ blue black colour]

Que-7: Complete the following table and write your observations.

	Hydrogen sulphide	Ammonia	Sulphur dioxide	Hydrogen chloride
Shake the gas with red litmus solution
Shake the gas with blue litmus solution
Apply a burning splint to a gas

Ans:

	Hydrogen sulphide	Ammonia	Sulphur dioxide	Hydrogen chloride
Shake the gas with red litmus solution	No change in the colour of litmus solution	Red litmus solution becomes blue in colour.	No change in the colour of litmus solution	No change in the colour of litmus solution
Shake the gas with blue litmus solution	Blue litmus solution becomes red in colour.	No change in the colour of blue litmus solution.	Blue litmus solution becomes red in colour.	Blue litmus solution becomes red in colour
Apply a burning splint to a gas	No reaction.	reaction nil.	reaction.not possible	No reaction.

Que-8: Identify the anion present in the following compounds.

(i) Compound X on heating with copper turnings and conc. sulphuric acid liberates a reddish brown gas.
(ii) When a solution of compound Y is treated with silver nitrate solution, a white precipitate is obtained which is soluble in excess of ammonium hydroxide solution.
(iii) Compound Z which on reacting with dilute sulphuric acid liberates a gas which turns lime water milky, but the gas has no effect on acidified potassium dichromate solution.
(iv) Compound L on reacting with barium chloride solution gives a white precipitate insoluble in dilute hydrochloric acid or dilute nitric acid.

Ans:
(i) Nitrate ion, NO₃^–
(ii) Chloride ion, Cl^–
(iii) Carbonate ion, CO₃^2–
(iv) Sulphate ion, SO₄^2-

Que-9: State giving reasons if:

(a) zinc and aluminium can be distinguished by heating the metal powder with concentrated sodium hydroxide solution.
(b) calcium nitrate and lead nitrate can be distinguished by adding ammonium hydroxide solution to the salt solution.

Ans:
(a) Zinc and aluminium cannot be distinguished by heating the metal powder with concentrated sodium hydroxide solution as they both react with conc. alkalis to form soluble sodium salts and hydrogen gas.
Zinc reacts to form sodium zincate
Zn + 2NaOH ⟶ H₂ + Na₂ZnO₂
Aluminium reacts to form sodium aluminate
2Al + 2NaOH + 2H₂O ⟶ 3H₂ + 2NaAlO₂
(b) Yes, calcium nitrate and lead nitrate can be distinguished using ammonium hydroxide solution. Ammonium hydroxide on reaction with lead nitrate gives chalky white precipitate of Pb(OH)₂. No precipitation occurs on adding Ammonium hydroxide to calcium nitrate even when it is added in excess.
Pb(NO₃)₂ + 2NH₄OH ⟶ Pb(OH)₂ + 2NH₄NO₃

Que-10: Identify the substance ‘R’ based on the information given below:

The pale green solid ‘R’ turns reddish brown on heating. Its aqueous solution gives a white precipitate with barium chloride solution. The precipitate is insoluble in mineral acids.

Ans: R is ferrous sulphate.

Que-11: Write the equation for the reaction of magnesium sulphate solution with barium chloride solution.

Ans: MgSO₄ + BaCl₂→ MgCl₂ + BaSO₄

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