Simple Interest Class 7 RS Aggarwal Exe-11B MCQs Goyal Brothers ICSE Foundation Maths Solutions. We provide step by step Solutions of lesson/ Chapter-11 Simple Interest for ICSE Class-7 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan to develop skill and confidence. Visit official Website **CISCE** for detail information about ICSE Board Class-7 Mathematics.

## Simple Interest Class 7 RS Aggarwal Exe-11B MCQs Goyal Brothers ICSE Maths Solutions

Board | ICSE |

Publications | Goyal brothers Prakashan |

Subject | Maths |

Class | 7th |

Chapter-11 | Simple Interest |

Writer | RS Aggrawal |

Book Name | Foundation |

Topics | Solution of Exe-11B MCQs |

Academic Session | 2024 – 2025 |

### Simple Interest MCQs

Class 7 RS Aggarwal Exe-11B Goyal Brothers ICSE Foundation Maths Solutions

Choose the correct option in each of the following:

**Question-1: Which of the following statements is incorrect?**

(a) T = (100 × S1) / (P x R)

(b) R = (P * T) / (100 * SI)

(c) SI = (P*R*T) / 100

(d) P = (100 * SI) / (R * T)

Answer- statement (b) is incorrect because, R = (SI * 100) / (P * T).

so, option (b) is in correct.

**Question-2: If the principal is ₹600, then the amount to be paid at the end of three years at 7(1/2)% pa. simple interest will be**

(a) 735 (b) 750 (c) 775 (d) 785

Answer- P = 600, T = 3 years, R = 7(1/2)% = 7.5%

S.I. = P×R×T/100

(600×7.5×3)/100 = 135

A = P + SI =600 + 135 = 735.

so, option (a) is correct.

**Question-3: At, what rate Rs 800 gives Rs 208 as simple interest in 2 years?**

(a) 11% , (b) 12% , (c) 13%, (d) 14%

Answer- SI = 208 P = 800 T = 2

SI= (P×R×T)/100

R = (208×100)/(800×2) = 13%

so, option (c) is correct.

**Question-4: In how many years will ₹900 give ₹351 as simple interest at 13% p.a.?**

(a) 1(1/2) years, (b) 2 years , (c) 2(1/2) years , (d) 3 years

Answer- SI = 351 P = 900 R = 13%

SI = PRT/100

351 = (900 × 13 × T) /100

27 = 9 × 1 × T

T = 3 years so, option (d) is correct.

**Question-5: At what rate per cent per annum simple interest will a sum be double of itself in 8 years?**

(a) 10% , (b) 12(1/2)% , (c) 15% , (d) 17(1/2)

Answer- Let the sum of money be x

Time=8 years

Amount after 8 years becomes double=2x

Therefore,

Simple interest=Amount -principal=2x−x=x

Rate per annum =S.I×100P×T = x × 100x × 8 = 100/8 = 25 /2 = 12(1/2)

so,option (b) is correct.

**Question-6: At simple interest a sum becomes 7/4 of itself int 5 years. The rate of interest is**

(a) 10%p.a , (b) 12% p.a , (c) 12(1/2)%pa., (d) 15%pa.

Answer-6: Let say Sum = 4X

sum becomes 7/4 of itself = (7/4) 4X = 7X

Simple interest = 7X – 4X = 3X

Simple interest = P * R * T /100

3X = 4X * R * 5 /100

3 = R/5

R = 15%

so, option (d) is correct.

#### MENTAL MATHS

Class 7 RS Aggarwal Exe-11B Goyal Brothers ICSE Foundation Maths Solutions

**Question-1: Fill in the blanks:**

**(i)The money borrowed for a certain period is called _____**

Ans-(i) principal

**(ii) The rate per cent per annum is the interest on_____ for 1 year.**

Ans-(ii) Rs100

**(iii) The simple interest on ₹800 invested at 13% per annum for 3 years is _____**

Ans-(iii) P = 800 R = 13% T = 3

SI = PRT/100

SI =(800* 13* 3) /100

SI = Rs312.

**(iv) If ₹2600 becomes 3900 in 5 years, then the rate of interest is _____**

Ans-(iv) SI = 3900-2600 = 1300 T = 5 P = 2600

SI =PRT/100

R= (1300 * 100 ) / (2600 * 5)

R = 10%.

**(v) If the principal is 3400, then the amount to be paid at the end of 5 years at 8% p.a. simple interest will be ____**

Ans-(v) P = 1400 R = 8 % T = 5

SI = PRT/100

SI = (3400 * 8 * 5) / 100

SI = 1360

A =SI + P = 1360 + 3400 = Rs 4760.

**Question-2: Write true (T) or false (F):**

(i) The total money to be paid back to the lender is called interest.___________

Ans-(i) False

(ii) Amount = Principal + Interest ____________

Ans-(ii) True

(iii) The rate per cent per annum is the interest on Rs 1 for 1 year. ____________

Ans-(iii) False

(iv) S.I. = (100 * P) / (R * T) ____________

Ans-(iv) False

(v) If a man borrows ₹5200 at 6% p.a. simple interest, the amount he has to return at the end of 5 years is 6760. ___

Ans-(v) True

**— : End of Simple Interest Class 7 RS Aggarwal Exe-11B MCQs Goyal Brothers ICSE Foundation Maths Solutions :–**

**Return to: – ICSE Class -7 RS Aggarwal Goyal Brothers Math Solutions**

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