Simple Interest Class 7 RS Aggarwal Exe-11B MCQs Goyal Brothers ICSE Maths Solutions

Simple Interest Class 7 RS Aggarwal Exe-11B MCQs Goyal Brothers ICSE Foundation Maths Solutions. We provide step by step Solutions of lesson/ Chapter-11 Simple Interest for ICSE Class-7 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-7 Mathematics.

Simple Interest Class 7 RS Aggarwal Exe-11B MCQs Goyal Brothers ICSE Maths Solutions

Simple Interest Class 7 RS Aggarwal Exe-11B MCQs Goyal Brothers ICSE Maths Solutions

Board ICSE
Publications Goyal brothers Prakashan
Subject Maths
Class 7th
Chapter-11 Simple Interest
Writer RS Aggrawal
Book Name Foundation
Topics Solution of Exe-11B MCQs
Academic Session 2024 – 2025

Simple Interest MCQs

Class 7 RS Aggarwal Exe-11B Goyal Brothers ICSE Foundation Maths Solutions

Choose the correct option in each of the following:

Question-1: Which of the following statements is incorrect?

(a) T = (100 × S1) / (P x R)
(b) R = (P * T) / (100 * SI)
(c) SI = (P*R*T) / 100
(d) P = (100 * SI) / (R * T)

Answer- statement (b) is incorrect because, R = (SI * 100) / (P * T).

so, option (b) is in correct.

Question-2: If the principal is ₹600, then the amount to be paid at the end of three years at 7(1/2)% pa. simple interest will be

(a) 735   (b) 750   (c) 775 (d) 785

Answer- P = 600,    T = 3 years,  R = 7(1/2)% = 7.5%

S.I. = P×R×T/100

(600×7.5×3)/100 = 135

A = P + SI =600 + 135 = 735.

so, option (a) is correct.

Question-3: At, what rate Rs 800 gives Rs 208 as simple interest in 2 years?

(a) 11% ,     (b) 12% ,      (c) 13%,  (d) 14%

Answer-  SI = 208           P = 800       T = 2

SI=  (P×R×T)/100

R = (208×100)/(800×2) = 13%

so, option (c) is correct.

Question-4: In how many years will ₹900 give ₹351 as simple interest at 13% p.a.?

(a) 1(1/2) years,    (b) 2 years ,   (c) 2(1/2) years ,   (d) 3 years

Answer-  SI = 351             P = 900            R = 13%

SI = PRT/100

351 = (900 × 13 × T) /100

27 = 9 × 1 × T

T = 3 years so, option (d) is correct.

Question-5:  At what rate per cent per annum simple interest will a sum be double of itself in 8 years?

(a) 10%  ,    (b) 12(1/2)%  ,   (c) 15%  ,   (d) 17(1/2)

Answer-  Let the sum of money be x

Time=8 years

Amount after 8 years becomes double=2x

Therefore,

Simple interest=Amount -principal=2x−x=x

Rate per annum =S.I×100P×T = x × 100x × 8 = 100/8 = 25 /2 = 12(1/2)

so,option (b) is correct.

Question-6: At simple interest a sum becomes 7/4  of itself int 5 years. The rate of interest is

(a) 10%p.a ,  (b) 12% p.a  ,    (c) 12(1/2)%pa.,     (d) 15%pa.

Answer-6:   Let say Sum = 4X

sum becomes 7/4 of itself  = (7/4) 4X = 7X

Simple interest = 7X – 4X  = 3X

Simple interest  = P * R * T /100

3X = 4X * R * 5 /100

3  = R/5

R = 15%

so, option (d) is correct.

MENTAL MATHS

Class 7 RS Aggarwal Exe-11B Goyal Brothers ICSE Foundation Maths Solutions

Question-1:  Fill in the blanks:

(i)The money borrowed for a certain period is called _____

Ans-(i) principal

(ii) The rate per cent per annum is the interest on_____ for 1 year.

Ans-(ii) Rs100

(iii) The simple interest on ₹800 invested at 13% per annum for 3 years is _____

Ans-(iii) P = 800        R = 13%           T = 3

SI = PRT/100

SI =(800* 13* 3) /100

SI = Rs312.

(iv) If ₹2600 becomes 3900 in 5 years, then the rate of interest is _____

Ans-(iv) SI = 3900-2600 = 1300         T = 5              P = 2600

SI =PRT/100

R= (1300 * 100 ) / (2600 * 5)

R = 10%.

(v) If the principal is 3400, then the amount to be paid at the end of 5 years at 8% p.a. simple interest will be ____

Ans-(v) P = 1400             R = 8 %             T = 5

SI = PRT/100

SI = (3400 * 8 * 5) / 100

SI = 1360

A =SI + P = 1360 + 3400 = Rs 4760.

Question-2:  Write true (T) or false (F):

(i) The total money to be paid back to the lender is called interest.___________

Ans-(i) False

(ii) Amount = Principal + Interest ____________

Ans-(ii) True

(iii) The rate per cent per annum is the interest on Rs 1 for 1 year. ____________

Ans-(iii) False

(iv) S.I. = (100 * P) / (R * T) ____________

Ans-(iv) False

(v) If a man borrows ₹5200 at 6% p.a. simple interest, the amount he has to return at the end of 5 years is 6760. ___

Ans-(v) True

— : End of Simple Interest Class 7 RS Aggarwal Exe-11B MCQs Goyal Brothers ICSE Foundation Maths Solutions :–

Return to: – ICSE Class -7 RS Aggarwal Goyal Brothers Math Solutions

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