Sulphuric Acid Long Ans Concise Class-10 ICSE Chemistry Selina Solutions Chapter-11. We Provide Step by Step Answer of Long Ans Questions of Exercise-11 for ICSE Class-10. The given Solutions is according to the Latest editions. Visit official Website CISCE for detail information about ICSE Board Class-10.
Sulphuric Acid Long Ans Concise Class-10 ICSE Chemistry Selina Solutions Chapter-11
| Board | ICSE |
| Book / Publication | Concise / Selina |
| Subject | Chemistry |
| Class | 10th |
| Writer | Dr SP Singh |
| Chapter-11 | Study of Compounds – Sulphuric Acid |
| Topics | Long Ans |
| Edition | 2025-2026 |
Long Ans Questions on Study of Compounds-Sulphuric Acid
Page-187
Que-1: What property of conc. H2SO4 is made use of in each of the following cases? Give an equation for the reaction in each case.
(a) In the production of HCl gas when it reacts with a chlorine
(b) In the preparation of CO from HCOOH
(c) As a source of hydrogen by diluting it and adding a strip of magnesium
(d) In the preparation of sulphur dioxide by warming a mixture of conc. Sulphuric acid and copper -turnings.
(e) Hydrogen sulphide gas is passed through concentrated sulphuric acid
(f) Its reaction with (i) ethanol (ii) carbon
Ans:
(a) Due to its reducing property. i.e, it is a non-volatile acid.
NaCl+ H2SO4 ⟶ NaHSO4 + HCl
(b) It is a dehydrating agent.
HCOOH ⟶ (Coc. H2SO4) CO + H2O
(c) Magnesium is present above hydrogen in the reactivity series so sulphuric acid is able to liberate hydrogen gas by reacting with magnesium strip.
Mg + H2SO4 ⟶ MgSO4 + H2
(d) Due to its oxidizing character
Cu +H2SO4 ⟶ CuSO4 + 2H2O + SO2
(e) Due to its oxidizing property Hydrogen sulphide gas is passed through concentrated sulphuric acid to liberate sulphur dioxide and sulphur is formed.
H2S + H2SO4 ⟶ S + 2H2O + SO2
(f) (i) Ethanol: C + 2H2SO4 → CO2 + H2O + 2SO4 ↑
(ii) Carbon: C2H5OH → C2H4 ↑ + H2O
Que-2:
(a) Which property of sulphuric acid accounts for its use as a dehydrating agent?
(b) Concentrated sulphuric acid is both an oxidizing agent and a non-volatile acid. Write one equation. Each to illustrate the above mentioned properties of sulphuric acid.
Ans:
(a) Sulphuric acid is powerful dehydrating agent on account of its strong affinity towards water.
(b) Concentrated sulphuric acid as
Oxidising agent: The oxidising property of conc. sulphuric acid its due to the fact that on thermal decomposition, it yields nacent oxygen [O].
H2SO4→ H2O + SO2 + [O]
Non-volatile acid: conc. sulphuric acid has high boiling point (338°C) that why it is said to be a non volatile compound, therefore it is used for preparing volatile acids like hydrochloric acids, nitric acids from there salts by double decomposition.
H2SO4 + NaCl → NaHSO4 + HCl
—: End of Study of Compounds – Sulphuric Acid Long Ans Concise Class-10 ICSE Chemistry Selina Solutions : –
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