Computer Application Semester-1 ICSE Specimen Paper Solved Class-10

Computer Application Semester-1 ICSE Specimen Paper Solved Class-10.  Step by step solutions of ICSE Class-10 specimen model sample paper .  During solutions of semester-1 Computer Application specimen paper so that student can achieve their goal in next upcoming exam of council .

Computer Application Semester-1 ICSE Specimen Paper Solved Class-10

Board ICSE
Class  10th (X)
Subject Computer Application
Topic Semester-1 ICSE Specimen Paper Solved
Syllabus  on bifurcated syllabus (after reduction)
session 2021-22
Question Type  MCQ/ Objective (as prescribe by council)
Total
question
Total- 10 with all parts
Max
mark
50
Warning :- before viewing solution view Question Paper

Question 1

Choose the correct answer

(a) Which of the following are valid comments?

(i) /* comment */
(ii) /* comment
(iii) // comment
(iv) */ comment */

1. (i) & (iii)
2. (i) & (ii)
3. All of the above
4. None of the above

Solution :

1. (i) & (iii)

 

(b) Operators with higher precedence are evaluated before operators with relatively lower precedence. Arrange the operators given below in order of higher precedence to lower precedence.

(i) && (ii) % (iii) >= (iv) ++

1. (iv), (i), (iii), (ii)
2. (iv), (iii), (ii), (i)
3. (iv), (ii), (iii), (i)
4. (i), (ii), (iii), (iv)

Solution :

4. (i), (ii), (iii), (iv)

 

(c) Which of the following keyword is used to create an instance of a class?

1. new
2. public
3. class
4. None of the above

Solution :

1. new

 

(d) What is the final value stored in variable x ?

double a =-8.35;

double x = Math.abs (Math.floor(a));

1. 9.0
2. 7.0
3. 6
4. 7

Solution :

1. 9.0

 

(e) Name the type of error in the statement given below:

int r=100/0;

1. Syntax
2. Runtime
3. Logical
4. None of the above

Solution :

2. Runtime

 

Question 2

Fill in the blanks with the correct option

(a) The _____________ allows a class to use the properties and methods of another class.

1. Inheritance
2. Polymorphism
3. Encapsulation
4. None of the above

Solution :

1. Inheritance

 

(b) The number of bytes occupied by char data type is __________byte/s

1. 4
2. 8
3. 2
4. None

Solution :

2. 8

 

(c) The _________ is called an instance of a class

1. Object
2. Attributes
3. State
4. None

Solution :

1. Object

 

(d) The ____________ are the words which have special meaning

1. Keywords
2. Identifier
3. Methods
4. Package

Solution :

1. Keywords

 

(e) Method that accepts a string without any space is _______

1. next()
2. nextLine()
3. nextInt()
4. None of the above

Solution :

1. next()

 

Question 3  (Computer Application Semester-1 ICSE)

Name the following 

(a) The wrapper class to which the method parseInt() belongs to

1. integer
2. Int
3. Integer

Solution :

3. Integer

 

(b) Intermediate code obtained after compilation

1. Source code
2. Byte Code

3. Object code

Solution :

2. Byte Code

 

(c) The method with the same name as of the class and which does not have a return data type is called as

1. Constructor
2. Function
3. Method

Solution :

1. Constructor

 

(d) The statement to stop the execution of a construct.

1. System.exit(0)
2. break
3. STOP

Solution :

2. break

 

(e) Invoking a function by passing the objects of a class is termed as

1. Call by value
2. call by reference
3. call by method

Solution :

2. call by reference

 

Question 4

State True Or False 

(a) byte is a non – primitive data type

1. True

2. False

Solution :

2. False

 

(b) !(2>3&&4>6 )

1. true
2. false

Solution :

1. true

 

(c) Scope of local variable is with in a class.

1. True
2. false

Solution :

2. false

 

(d) The default statement is optional in switch- case.

1. True
2. False

Solution :

1. True

 

(e) The assignment operator(=) is left associative.

1. True
2. False

Solution :

2. False

 

Question 5

Choose the odd one

(a)

1. Encapsulation

2. Data abstraction
3. Portable
4. Polymorphism

Solution :

3. Portable

 

(b)

1. >
2. ==
3. &&
4. <

Solution :

3. &&

 

(c)

1. return
2. break
3. continue
4. System.exit(0)

Solution :

4. System.exit(0)

 

(d)

1. int
2. double
3. char
4. String

Solution :

4. String

 

(e)

1. +
2. %
3. /
4. ||

Solution :

4. ||

 

Question 6

Give the output of the following

(a) x + = x++ + ++ x + –x + x; [ x = 5 ]

1. 29
2. 28
3. 26
4. 25

Solution :

1. 29

 

(b) if ( a > b )

System.out.println(a+b);

System.out.println (a*b); when a = 5 and b = 7

1. 12, 35
2. 35
3. 35, 12

Solution :

2. 35

 

(c) String x = (a >= 90) ? “excellent” : “best”; when a = 90

1. best
2. excellent
3. excellentbest

Solution :

2. excellent

 

(d) switch ( x )

{ case ‘a’ : System.out.println(“Discipline”);

case ‘b’ : System.out.println (“Dedication”); break;

case ‘c’ : System.out.println(“Commitment”);

default : System.out.println(“Success”);

} when x=’A’

1. Discipline
2. Dedication
3. Success

Solution :

3. Success

 

(e) n=1000;

while (n>10)

{ n=n/10;

}
System.out.println(n); How many time the loop is executed and what is the output?

1. Loop is executed 2 times and the output is 100
2. Loop is executed 3 times and the output is 10
3. Loop is executed 2 times and the output is 10.
Solution :

3. Loop is executed 2 times and the output is 10.

 

Question 7

Given below is a class with the following specifications:

Class name : overload

Member Methods:

void print ( int n ) – to print the first ‘n’ natural numbers

boolean print (int m, int n) – to check whether n is a multiple of m or not Fill in the blanks of the given program with appropriate java statements –

class (a)____________
{
void print (int n)
{
int k;
for ( (b)_______; (c)_________; (d)____________)
{
System.out.println(k);
}
}
boolean print( int m, (e)________)
{
if ( (f)_________________)
return true;
else
return false;
}
}

(a)

1. OVERLOAD
2. overload
3. class

Solution :

2. overload

 

(b)

1. k = 1;
2. k = n;
3. k = 0

Solution :

1. k = 1;

 

(c)

1. k<=n;
2. k>=n;

3. k+n;

Solution :

1. k<=n;

 

(d)

1. k+=2
2. k+=5
3. k++

Solution :

3. k++

 

(e)

1. int n
2. double n
3. char n

Solution :

1. int n

 

(f)

1. if (n%m == 0)
2. if (m%n==0)
3. if (m/n==0)

Solution :

1. if (n%m == 0)

 

Question 8  (Computer Application Semester-1 ICSE)

The following program is based on the specification given below. Fill in the blanks with appropriate java statements.

class name : telephone

member variables : int noc [ number of calls]

double bill [ telephone bill to be paid ]

String n [ name of the customer ]

Member methods :

void input ( ) – to accept the data using the scanner class

void print() – to print the details

void calculate () – to calculate the telephone bill as per the following criteria based on number

of calls

Number of calls Rate per call

First 100 calls free

Above 100 callsRs.2.50

void main ( ) – to create an object of the class and invoke the functions of the class
class (a)_____________

{ int noc; double bill ; String n;
Scanner ob = (b)______________ Scanner(System.in);
void input( )
{ System.out.println(“Enter Number of calls”);
noc = (c)____________________;
System.out.println(“Enter name “);
n=ob.next();
}
void calculate()
{ if ( (d)__________________)
bill =0;
else
bill = (e)_____________________________;
}
void print()
{ System.out.println(“Name = “+n);
System.out.println(“Amount to be paid=”+bill);
}
void main ()
{ telephone t = new telephone();
t.input();
(f)______________________;
t.print();
}
}

(a)

1. telephone
2. class
3. object

Solution :

1. telephone

 

(b)

1. old

2. new

3. void

Solution :

2. new

 

(c)

1. ob.nextDouble()

2. ob.nextLine()

3. ob.nextInt()

Solution :

3. ob.nextInt()

 

(d)

1. noc<100

2. noc < = 100

3. noc > 100

Solution :

2. noc < = 100

 

(e)

1. bill=0+(n-100)*2.50

2. bill = (n-100)*3.50

3. bill = n*2.50

Solution :

1. bill=0+(n-100)*2.50

 

(f)

1. t.input()

2. t.calculate()

3. t.print()

Solution :

2. t.calculate()

Question 9

The following program segment calculates the norm of a number, norm of a number is square root of sum of squares of all digits of the number.

Example:

The norm of 68 is 10
6×6 + 8×8 = 36+64 = 100 square root of 100 is 10.
Fill in the blanks with appropriate java statements.
void norm ( int n)
{ int d, s =(a)______;

While ( (b)_________)
{ d = n%10;
s = (c)________________;
n=n/10;
}
System.out.println(“Norm = “ + (d)_____________);
}

(a)

1. 0
2. 0.0
3. 1

Solution :

1. 0

 

(b)

1. n>0

2. n<0

3. n>1

Solution :

1. n>0

 

(c)

1. s+d*d

2. s*d+d

3. s*s+d

Solution :

1. s+d*d

 

(d)

1. Math.sqrt(s)

2. Math.SQRT(s)

3. Math.sqrt(n)

Solution :

1. Math.sqrt(s)

Question 10  (Computer Application Semester-1 ICSE)

Read the paragraph given below and answer the questions given below:
Case study 1

To check for a condition and execute the statements based on the condition can be done using the decision control statements. The two decision control statements in java are if and switch, switch is also called as multiple branching statement. An if statement within another if statement is termed as Nested if Statement. Repetitive execution of a set of statements is termed as looping. The two types of looping statements are entry controlled and exit controlled loops. Both while and for are termed as entry-controlled loops. A for loop is used when the number of iterations is known. A while is used when the set of statements are executed as long as the condition is true, it is executed when the number of iterations are not known.

(a) What are the two decision control statements in java? 

1. if and switch
2. for and while
3. ternary and logical

Solution :

1. if and switch

 

(b) An if statement within another if statement is termed as 

1. Nested
2. Nested while
3. Nested if

Solution :

3. Nested if

 

(c) Name given for repetitive execution of set of statements. 

1. Looping
2. Decision Control
3. Assignment

Solution :

1. Looping

 

(d) Which one of the following does not execute even once? 

1. for(k = 1; k<=100;k++);
2. for(k=10;k<1;k++);
3. for(k=1;k>=1;k++);

Solution :

2. for(k=10;k<1;k++);

–: End of ICSE Computer Application Sem-1 Specimen Paper Solutions:–


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